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5.4 Further Integration

Question 1a

Marks: 3

Consider the function f defined by f open parentheses x close parentheses equals open parentheses x squared minus 3 x plus 2 close parentheses open parentheses x plus 2 close parentheses comma space minus 3 less or equal than x less or equal than 5 over 4.

a)
Find the indefinite integral
integral open parentheses x squared minus 3 x plus 2 close parentheses open parentheses x plus 2 close parentheses d x

 

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    Question 1b

    Marks: 4
    b)
    Use your answer to part (a) to calculate the area of the region enclosed by the graph of  y equals f open parentheses x close parentheses and the x-axis.
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      Key Concepts
      Definite Integrals

      Question 2a

      Marks: 2
      a)
      Find the indefinite integral for
      integral sin open parentheses fraction numerator square root of 3 over denominator 2 end fraction x close parentheses d x
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        Question 2b

        Marks: 2
        b)
        Find the indefinite integral for
        integral 7 over e to the power of 4 x minus 9 end exponent d x
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          Key Concepts
          Integrating e^x & 1/x

          Question 2c

          Marks: 2
          c)
          Find an expression for y given that
          fraction numerator d y over denominator d x end fraction equals cos open parentheses 2 open parentheses straight pi over 8 minus x close parentheses close parentheses
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            Question 3a

            Marks: 2
            a)
            Find the indefinite integral
            integral negative fraction numerator 7 over denominator 5 x end fraction d x
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              Question 3b

              Marks: 3
              b)
              Find an expression for given that
              fraction numerator d y over denominator d x end fraction equals x e to the power of x squared minus 2 end exponent
              and also that y equals 3 when x equals negative square root of 2
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                Question 4a

                Marks: 3
                a)
                Find the indefinite integral for
                integral open parentheses square root of 3 x end root plus fraction numerator 5 over denominator cube root of 8 x end root end fraction close parentheses d x
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                  Question 4b

                  Marks: 3
                  b)
                  Find the indefinite integral for
                  integral fraction numerator open parentheses 8 x close parentheses to the power of 2 over 3 end exponent minus 5 x to the power of 1 over 6 end exponent over denominator x cube root of x end fraction d x
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                    Question 5a

                    Marks: 4
                    a)
                    Find the indefinite integral
                    integral fraction numerator x plus 2 x squared over denominator open parentheses 1 minus x squared close parentheses open parentheses 2 plus x squared close parentheses end fraction d x
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                      Key Concepts
                      Reverse Chain Rule

                      Question 5b

                      Marks: 5
                      b)
                      Let  g apostrophe open parentheses x close parentheses equals fraction numerator cos open parentheses ln space x close parentheses over denominator x end fraction for x greater than 0. 
                      Find  g open parentheses x close parentheses given that  g open parentheses 1 close parentheses equals straight pi.
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                        Question 5c

                        Marks: 4
                        c)
                        Show that
                        integral tan space x space d x equals ln open vertical bar fraction numerator 1 over denominator cos space x end fraction close vertical bar plus c
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                          Question 6

                          Marks: 6

                          A curve with equation y equals f open parentheses x close parentheses is such that

                           fraction numerator d y over denominator d x end fraction equals fraction numerator k over denominator open parentheses 1 plus sin space pi x close parentheses open parentheses 1 minus sin space pi x close parentheses end fraction 

                          where k is a real constant. 

                          Given that the curve passes through the points open parentheses 0 comma negative 3 close parentheses and open parentheses negative 1 fourth comma negative straight pi close parentheses, find f open parentheses x close parentheses.

                           

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                            Question 7a

                            Marks: 2
                            a)
                            Explain why
                            fraction numerator 1 over denominator tan space theta end fraction equals fraction numerator cos space theta space space over denominator sin space theta end fraction
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                              Question 7b

                              Marks: 7
                              b)
                              Use definite integration, along with the result from part (a), to show that
                              integral subscript 0 superscript square root of straight pi over 6 end root end superscript fraction numerator x over denominator tan open parentheses x squared minus fraction numerator 2 straight pi over denominator 3 end fraction close parentheses end fraction d x equals negative 1 half ln open parentheses fraction numerator square root of 3 over denominator 2 end fraction close parentheses
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                                Question 7c

                                Marks: 1
                                c)
                                Using your knowledge of the natural logarithm function, explain (without using your GDC) why the value of the integral found in part (b) is a positive number.
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                                  Question 8a

                                  Marks: 4

                                  The diagram below shows the graph of the function f which is defined by

                                  f open parentheses x close parentheses equals x sin space 2 x comma space space space space space space space 0 less or equal than x less or equal than fraction numerator 3 straight pi over denominator 2 end fraction

                                  mi-q8a-5-4-ib-ai-hl-further-integration-very-hard_dig

                                  The shaded region in the diagram is the region enclosed by the x-axis and the graph of y equals f open parentheses x close parentheses.  The three sub-parts of the shaded region are denoted by R, S and T, as shown.

                                  (a)        Find the value of

                                  integral subscript 0 superscript fraction numerator 3 straight pi over denominator 2 end fraction end superscript x space sin space 2 x space d x

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                                    Question 8b

                                    Marks: 5
                                    b)
                                    Find the individual areas of each of the three sub-parts R, S and T of the shaded region.
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                                      Question 8c

                                      Marks: 4
                                      c)
                                      Compare the sum of the answers in part (b) to the answer in part (a) and comment on the result.
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                                        Key Concepts
                                        Negative Integrals

                                        Question 9

                                        Marks: 8

                                        The diagram below depicts the design for a new company logo.  The upper border of the logo is formed by a part of the curve with equation  y equals 9 minus x squared,  while the lower border of the logo is formed by a part of the curve with equation y equals 1 over 8 x squared minus 5.  As shown in the diagram, the logo is divided into a shaded part and an unshaded part by a part of the curve with equation y equals fraction numerator open parentheses 9 minus x squared close parentheses open parentheses 2 x minus 1 close parentheses over denominator 10 end fraction.

                                        mi-q9-5-4-ib-ai-hl-further-integration-very-hard_dig

                                        Find the percentage of the total area of the logo that is shaded.

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                                          Question 10a

                                          Marks: 9

                                          The following diagram shows a part of the graph of the curve with equation y squared equals k open parentheses 1600 minus 25 open parentheses x minus 8 close parentheses squared close parentheses,  where k greater than 0 is a constant.  The point marked A is the vertex of the curve.  Region R is the region enclosed by the curve and the x-axis, for the part of the curve where y is non-negative.  Region S is the region enclosed by the curve, the positive y-axis, and the line through point A with gradient zero.

                                          mi-q10a-5-4-ib-ai-hl-further-integration-very-hard-2_dig

                                          When region R is rotated 2 straight pi radians about the x-axis, the resultant solid of revolution has a volume equal to fraction numerator 12800 straight pi over denominator 3 end fraction space units cubed

                                          a)
                                          Find the area of region S by calculating an area between the curve and the y-axis.
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                                            Question 10b

                                            Marks: 4
                                            b)
                                            Find the area of region S by calculating an area between the curve and the x-axis.  Confirm that this matches your answer to part (a).
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                                              Question 11

                                              Marks: 8

                                              The diagram below shows the cross-section of a goldfish bowl to be produced by Pieseize Manufacturing, a specialist company supplying products for goldfish enthusiasts.

                                               q12-5-9-ib-aa-hl-advanced-integration-very-hard-maths_diagram

                                              The glass part of the bowl sits on a solid base, indicated by the shaded region on the diagram. The cross-section of the glass part of the bowl is symmetrical about the y-axis, and may be described by the curve with equation

                                              x squared over 400 plus open parentheses y minus 17 close parentheses squared over 225 equals 1

                                              The dashed horizontal line represents the diameter of the open top of the fishbowl.  The maximum depth of the fishbowl, measured along the y-axis from the diameter of the open top to where the glass part of the bowl meets the base, is indicated by d  in the diagram.  All coordinates are expressed in centimetres, and for purposes of answering this question the thickness of the glass sides of the bowl may be regarded as negligible.

                                              The owner of the company, Skodyn Pieseize, is extremely superstitious and is obsessed with the number 23. Therefore he insists that the capacity of the glass part of this new fishbowl must be exactly 23 litres.  Find the value of d that satisfies this requirement.

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