Directly related questions
-
22N.1A.SL.TZ0.22:
Which substance is the reducing agent in the given reaction?
H+ (aq) + 2H2O (l) + 2MnO4− (aq) + 5SO2 (g) → 2Mn2+ (aq) + 5HSO4− (aq)
A. H+B. H2O
C. MnO4−
D. SO2
-
22N.1A.SL.TZ0.22:
Which substance is the reducing agent in the given reaction?
H+ (aq) + 2H2O (l) + 2MnO4− (aq) + 5SO2 (g) → 2Mn2+ (aq) + 5HSO4− (aq)
A. H+B. H2O
C. MnO4−
D. SO2
- 22N.1A.SL.TZ0.23: Which combination is correct regarding the anode and electron flow in an electrolytic cell?
- 22N.1A.SL.TZ0.23: Which combination is correct regarding the anode and electron flow in an electrolytic cell?
-
22N.1A.SL.TZ0.18:
The exothermic reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) is at equilibrium in a fixed volume. What is correct about the reaction quotient, Q, and shift in position of equilibrium the instant temperature is raised?
A. Q > K, equilibrium shifts right towards products.B. Q > K, equilibrium shifts left towards reactants.
C. Q < K, equilibrium shifts right towards products.
D. Q < K, equilibrium shifts left towards reactants.
-
22N.1A.SL.TZ0.18:
The exothermic reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) is at equilibrium in a fixed volume. What is correct about the reaction quotient, Q, and shift in position of equilibrium the instant temperature is raised?
A. Q > K, equilibrium shifts right towards products.B. Q > K, equilibrium shifts left towards reactants.
C. Q < K, equilibrium shifts right towards products.
D. Q < K, equilibrium shifts left towards reactants.
- 22N.2.SL.TZ0.4a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
- 22N.2.SL.TZ0.4a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
- 22N.2.SL.TZ0.a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
-
19N.1A.HL.TZ0.22:
What is the intercept on the y-axis when a graph of lnk is plotted against on the x-axis?
A. lnA
B.
C.
D.
-
19N.1A.HL.TZ0.22:
What is the intercept on the y-axis when a graph of lnk is plotted against on the x-axis?
A. lnA
B.
C.
D.
Sub sections and their related questions
Reactivity 2.3.1—A state of dynamic equilibrium is reached in a closed system when the rates of forward and backward reactions are equal. Describe the characteristics of a physical and chemical system at equilibrium.
NoneReactivity 2.3.2—The equilibrium law describes how the equilibrium constant, K, can be determined from the stoichiometry of a reaction. Deduce the equilibrium constant expression from an equation for a homogeneous reaction.
-
22M.2.SL.TZ1.3a(i):
Deduce the expression for the equilibrium constant, Kc, for this equation.
- 19N.2.SL.TZ0.4a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
-
21N.2.SL.TZ0.3c(v):
State the equilibrium constant expression, Kc, for this reaction.
-
22M.2.SL.TZ2.4c:
State the equilibrium constant expression, Kc, for this reaction.
-
19M.1A.SL.TZ2.18:
What is the equilibrium constant expression for the following equation?
2NO2 (g) + F2 (g) 2NO2F (g)
A.
B.
C.
D.
-
19M.1A.SL.TZ1.22:
Kc for 2N2O (g) 2N2 (g) + O2 (g) is 7.3 × 1034.
What is Kc for the following reaction, at the same temperature?
N2 (g) + O2 (g) N2O (g)
A. 7.3 × 1034
B.
C.
D.
-
21N.2.SL.TZ0.3c(ii):
State the equilibrium constant expression, Kc, for this reaction.
-
21M.2.SL.TZ2.7a:
State the equilibrium constant expression, Kc, for the reaction above.
-
22M.2.SL.TZ1.3a(i):
Deduce the expression for the equilibrium constant, Kc, for this equation.
-
22M.2.SL.TZ1.a(i):
Deduce the expression for the equilibrium constant, Kc, for this equation.
- 19N.2.SL.TZ0.4a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
- 19N.2.SL.TZ0.a(ii): The value of the equilibrium constant for the first dissociation at 298 K is 5.01 × 10−4. State,...
-
21N.2.SL.TZ0.3c(v):
State the equilibrium constant expression, Kc, for this reaction.
-
21N.2.SL.TZ0.c(v):
State the equilibrium constant expression, Kc, for this reaction.
-
22M.2.SL.TZ2.4c:
State the equilibrium constant expression, Kc, for this reaction.
-
22M.2.SL.TZ2.c:
State the equilibrium constant expression, Kc, for this reaction.
-
19M.1A.SL.TZ2.18:
What is the equilibrium constant expression for the following equation?
2NO2 (g) + F2 (g) 2NO2F (g)
A.
B.
C.
D.
-
19M.1A.SL.TZ1.22:
Kc for 2N2O (g) 2N2 (g) + O2 (g) is 7.3 × 1034.
What is Kc for the following reaction, at the same temperature?
N2 (g) + O2 (g) N2O (g)
A. 7.3 × 1034
B.
C.
D.
-
21N.2.SL.TZ0.3c(ii):
State the equilibrium constant expression, Kc, for this reaction.
-
21N.2.SL.TZ0.c(ii):
State the equilibrium constant expression, Kc, for this reaction.
-
21M.2.SL.TZ2.7a:
State the equilibrium constant expression, Kc, for the reaction above.
-
21M.2.SL.TZ2.a:
State the equilibrium constant expression, Kc, for the reaction above.
Reactivity 2.3.3—The magnitude of the equilibrium constant indicates the extent of a reaction at equilibrium and is temperature dependent. Determine the relationships between K values for reactions that are the reverse of each other at the same temperature.
-
22M.2.SL.TZ1.3b(i):
Determine the enthalpy change, ΔH, for the Haber–Bosch process, in kJ. Use Section 11 of the data booklet.
-
22M.2.SL.TZ1.3b(iii):
Demonstrate that your answer to (b)(i) is consistent with the effect of an increase in temperature on the percentage yield, as shown in the graph.
-
22M.1A.SL.TZ2.20:
What is the strongest acid in the equation below?
H3AsO4 + H2O H2AsO4− + H3O+ Kc = 4.5 × 10−4
A. H3AsO4
B. H2O
C. H2AsO4−
D. H3O+
- 21N.1A.SL.TZ0.27: What is correct for pure hot water?
-
21N.1A.SL.TZ0.19:
The equilibrium 2H2 (g) + N2 (g) N2H4 (g) has an equilibrium constant, K, at 150 °C.
What is the equilibrium constant at 150 °C, for the reverse reaction?
N2H4 (g) 2H2 (g) + N2 (g)
A. KB. K−1
C. −K
D. 2K
-
22M.2.SL.TZ1.3b(i):
Determine the enthalpy change, ΔH, for the Haber–Bosch process, in kJ. Use Section 11 of the data booklet.
-
22M.2.SL.TZ1.3b(iii):
Demonstrate that your answer to (b)(i) is consistent with the effect of an increase in temperature on the percentage yield, as shown in the graph.
-
22M.2.SL.TZ1.b(i):
Determine the enthalpy change, ΔH, for the Haber–Bosch process, in kJ. Use Section 11 of the data booklet.
-
22M.2.SL.TZ1.b(iii):
Demonstrate that your answer to (b)(i) is consistent with the effect of an increase in temperature on the percentage yield, as shown in the graph.
-
22M.1A.SL.TZ2.20:
What is the strongest acid in the equation below?
H3AsO4 + H2O H2AsO4− + H3O+ Kc = 4.5 × 10−4
A. H3AsO4
B. H2O
C. H2AsO4−
D. H3O+
- 21N.1A.SL.TZ0.27: What is correct for pure hot water?
-
21N.1A.SL.TZ0.19:
The equilibrium 2H2 (g) + N2 (g) N2H4 (g) has an equilibrium constant, K, at 150 °C.
What is the equilibrium constant at 150 °C, for the reverse reaction?
N2H4 (g) 2H2 (g) + N2 (g)
A. KB. K−1
C. −K
D. 2K
Reactivity 2.3.4—Le Châtelier’s principle enables the prediction of the qualitative effects of changes in concentration, temperature and pressure to a system at equilibrium. Apply Le Ch.telier’s principle to predict and explain responses to changes of systems at equilibrium.
- 22M.2.SL.TZ2.3b(ii): Explain the effect of increasing temperature on the yield of SO3.
- 22M.2.SL.TZ1.3a(ii): State how the use of a catalyst affects the position of the equilibrium.
-
19N.2.SL.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on the equilibrium constant, of increasing the temperature.
-
19M.2.SL.TZ2.5a(iii):
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.5b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
- 22M.2.SL.TZ2.6b(ii): Explain the effect of increasing temperature on the yield of SO3.
-
19M.2.SL.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) ⇌ CH3COOOH (aq) + H2O (l)
-
21N.2.SL.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
19M.2.SL.TZ2.5b:
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.5d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) CH3COOOH (aq) + H2O (l)
-
19M.1A.HL.TZ2.22:
Consider the following equilibrium reaction.
2N2O (g) + O2 (g) 4NO (g) ΔH = +16 kJ
Which change will move the equilibrium to the right?
A. Decrease in pressure
B. Decrease in temperature
C. Increase in [NO]
D. Decrease in [O2]
-
19M.2.SL.TZ1.5b:
A solution of bleach can be made by reacting chlorine gas with a sodium hydroxide solution.
Cl2 (g) + 2NaOH (aq) NaOCl (aq) + NaCl (aq) + H2O (l)
Suggest, with reference to Le Châtelier’s principle, why it is dangerous to mix vinegar and bleach together as cleaners.
-
19N.2.SL.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on Ka, of increasing the temperature.
- 21M.2.SL.TZ1.6b(ii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
-
21N.2.SL.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21M.2.SL.TZ2.2e:
Consider the following equilibrium reaction:
2SO2 (g) + O2 (g) 2SO3 (g)
State and explain how the equilibrium would be affected by increasing the volume of the reaction container at a constant temperature.
- 19N.1A.HL.TZ0.24: Which corresponds to a system at equilibrium?
-
19N.1A.SL.TZ0.19:
What effect does increasing both pressure and temperature have on the equilibrium constant, Kc?
N2 (g) + 3H2 (g) 2NH3 (g) ΔH = −45.9 kJ
A. Decreases
B. Increases
C. Remains constant
D. Cannot be predicted as effects are opposite
- 20N.1B.SL.TZ0.2b: The ice bath is used at equilibrium to slow down the forward and reverse reactions. Explain why...
- 20N.1B.SL.TZ0.2c: Suggest why the titration must be conducted quickly even though a low temperature is maintained.
-
20N.1A.SL.TZ0.18:
What is correct when temperature increases in this reaction at equilibrium?
-
21M.1A.SL.TZ1.18:
Which changes produce the greatest increase in the percentage conversion of methane?
CH4 (g) + H2O (g) CO (g) + 3H2 (g)
- 21M.2.SL.TZ1.6b(iii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
- 21M.2.SL.TZ2.7b: State and explain how the equilibrium would be affected by increasing the volume of the reaction...
- 22N.2.SL.TZ0.4a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
- 22N.1A.SL.TZ0.23: Which combination is correct regarding the anode and electron flow in an electrolytic cell?
-
22N.1A.SL.TZ0.18:
The exothermic reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) is at equilibrium in a fixed volume. What is correct about the reaction quotient, Q, and shift in position of equilibrium the instant temperature is raised?
A. Q > K, equilibrium shifts right towards products.B. Q > K, equilibrium shifts left towards reactants.
C. Q < K, equilibrium shifts right towards products.
D. Q < K, equilibrium shifts left towards reactants.
-
22N.1A.HL.TZ0.23:
Which of these changes would shift the equilibrium to the right?
[Co(H2O)6]2+ (aq) + 4Cl− (aq) [CoCl4]2− (aq) + 6H2O (l)
I. Addition of 0.01 M HCl
II. Addition of concentrated HCl
III. Evaporation of water
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
- 22M.2.SL.TZ2.3b(ii): Explain the effect of increasing temperature on the yield of SO3.
- 22M.2.SL.TZ2.b(ii): Explain the effect of increasing temperature on the yield of SO3.
- 22M.2.SL.TZ1.3a(ii): State how the use of a catalyst affects the position of the equilibrium.
- 22M.2.SL.TZ1.a(ii): State how the use of a catalyst affects the position of the equilibrium.
-
19N.2.SL.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on the equilibrium constant, of increasing the temperature.
-
19N.2.SL.TZ0.a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on the equilibrium constant, of increasing the temperature.
-
19M.2.SL.TZ2.5a(iii):
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.5b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.a(iii):
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.b(i):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
- 22M.2.SL.TZ2.6b(ii): Explain the effect of increasing temperature on the yield of SO3.
- 22M.2.SL.TZ2.b(ii): Explain the effect of increasing temperature on the yield of SO3.
-
19M.2.SL.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) ⇌ CH3COOOH (aq) + H2O (l)
-
19M.2.SL.TZ1.c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) ⇌ CH3COOOH (aq) + H2O (l)
-
21N.2.SL.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21N.2.SL.TZ0.c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
19M.2.SL.TZ2.5b:
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.5d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ2.b:
When a bottle of carbonated water is opened, these equilibria are disturbed.
State, giving a reason, how a decrease in pressure affects the position of Equilibrium (1).
-
19M.2.SL.TZ2.d(ii):
Predict, referring to Equilibrium (2), how the added sodium hydrogencarbonate affects the pH.(Assume pressure and temperature remain constant.)
-
19M.2.SL.TZ1.4c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) CH3COOOH (aq) + H2O (l)
-
19M.2.SL.TZ1.c:
Comment on why peracetic acid, CH3COOOH, is always sold in solution with ethanoic acid and hydrogen peroxide.
H2O2 (aq) + CH3COOH (aq) CH3COOOH (aq) + H2O (l)
-
19M.1A.HL.TZ2.22:
Consider the following equilibrium reaction.
2N2O (g) + O2 (g) 4NO (g) ΔH = +16 kJ
Which change will move the equilibrium to the right?
A. Decrease in pressure
B. Decrease in temperature
C. Increase in [NO]
D. Decrease in [O2]
-
19M.2.SL.TZ1.5b:
A solution of bleach can be made by reacting chlorine gas with a sodium hydroxide solution.
Cl2 (g) + 2NaOH (aq) NaOCl (aq) + NaCl (aq) + H2O (l)
Suggest, with reference to Le Châtelier’s principle, why it is dangerous to mix vinegar and bleach together as cleaners.
-
19M.2.SL.TZ1.b:
A solution of bleach can be made by reacting chlorine gas with a sodium hydroxide solution.
Cl2 (g) + 2NaOH (aq) NaOCl (aq) + NaCl (aq) + H2O (l)
Suggest, with reference to Le Châtelier’s principle, why it is dangerous to mix vinegar and bleach together as cleaners.
-
19N.2.SL.TZ0.4a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on Ka, of increasing the temperature.
-
19N.2.SL.TZ0.a(iii):
The dissociation of citric acid is an endothermic process. State the effect on the hydrogen ion concentration, [H+], and on Ka, of increasing the temperature.
- 21M.2.SL.TZ1.6b(ii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
- 21M.2.SL.TZ1.b(ii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
-
21N.2.SL.TZ0.5c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21N.2.SL.TZ0.c:
Calculate the concentration of H3PO4 if 25.00 cm3 is completely neutralised by the addition of 28.40 cm3 of 0.5000 mol dm−3 NaOH.
-
21M.2.SL.TZ2.2e:
Consider the following equilibrium reaction:
2SO2 (g) + O2 (g) 2SO3 (g)
State and explain how the equilibrium would be affected by increasing the volume of the reaction container at a constant temperature.
-
21M.2.SL.TZ2.e:
Consider the following equilibrium reaction:
2SO2 (g) + O2 (g) 2SO3 (g)
State and explain how the equilibrium would be affected by increasing the volume of the reaction container at a constant temperature.
- 19N.1A.HL.TZ0.24: Which corresponds to a system at equilibrium?
-
19N.1A.SL.TZ0.19:
What effect does increasing both pressure and temperature have on the equilibrium constant, Kc?
N2 (g) + 3H2 (g) 2NH3 (g) ΔH = −45.9 kJ
A. Decreases
B. Increases
C. Remains constant
D. Cannot be predicted as effects are opposite
- 20N.1B.SL.TZ0.b: The ice bath is used at equilibrium to slow down the forward and reverse reactions. Explain why...
- 20N.1B.SL.TZ0.c: Suggest why the titration must be conducted quickly even though a low temperature is maintained.
-
20N.1A.SL.TZ0.18:
What is correct when temperature increases in this reaction at equilibrium?
-
21M.1A.SL.TZ1.18:
Which changes produce the greatest increase in the percentage conversion of methane?
CH4 (g) + H2O (g) CO (g) + 3H2 (g)
- 21M.2.SL.TZ1.6b(iii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
- 21M.2.SL.TZ1.b(iii): Outline why increasing the concentration of N2O5 increases the rate of reaction.
- 21M.2.SL.TZ2.7b: State and explain how the equilibrium would be affected by increasing the volume of the reaction...
- 21M.2.SL.TZ2.b: State and explain how the equilibrium would be affected by increasing the volume of the reaction...
- 22N.2.SL.TZ0.4a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
- 22N.2.SL.TZ0.a.ii: Explain, with reference to Le Châtelier’s principle, the effect of using dilute rather than...
- 22N.1A.SL.TZ0.23: Which combination is correct regarding the anode and electron flow in an electrolytic cell?
-
22N.1A.SL.TZ0.18:
The exothermic reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) is at equilibrium in a fixed volume. What is correct about the reaction quotient, Q, and shift in position of equilibrium the instant temperature is raised?
A. Q > K, equilibrium shifts right towards products.B. Q > K, equilibrium shifts left towards reactants.
C. Q < K, equilibrium shifts right towards products.
D. Q < K, equilibrium shifts left towards reactants.
-
22N.1A.HL.TZ0.23:
Which of these changes would shift the equilibrium to the right?
[Co(H2O)6]2+ (aq) + 4Cl− (aq) [CoCl4]2− (aq) + 6H2O (l)
I. Addition of 0.01 M HCl
II. Addition of concentrated HCl
III. Evaporation of water
A. I and II onlyB. I and III only
C. II and III only
D. I, II and III
Reactivity 2.3.5—The reaction quotient, Q, is calculated using the equilibrium expression with nonequilibrium concentrations of reactants and products. Calculate the reaction quotient Q from the concentrations of reactants and products at a particular time, and determine the direction in which the reaction will proceed to reach equilibrium.
-
22M.2.HL.TZ1.3a(iii):
With reference to the reaction quotient, Q, explain why the percentage yield increases as the pressure is increased at constant temperature.
-
21N.1A.HL.TZ0.22:
A reversible reaction has a reaction quotient, Q, of 4.5 and equilibrium constant, Kc, of 6.2.
2A (g) A2 (g)
Which statement describes the reaction at this time?
A. The system has reached equilibrium.B. The rate of the forward reaction is greater than the rate of the reverse reaction.
C. The concentration of reactant is greater than the concentration of product.
D. At equilibrium, the concentration of reactant is greater than the concentration of product.
-
22M.2.HL.TZ1.3a(iii):
With reference to the reaction quotient, Q, explain why the percentage yield increases as the pressure is increased at constant temperature.
-
22M.2.HL.TZ1.a(iii):
With reference to the reaction quotient, Q, explain why the percentage yield increases as the pressure is increased at constant temperature.
-
21N.1A.HL.TZ0.22:
A reversible reaction has a reaction quotient, Q, of 4.5 and equilibrium constant, Kc, of 6.2.
2A (g) A2 (g)
Which statement describes the reaction at this time?
A. The system has reached equilibrium.B. The rate of the forward reaction is greater than the rate of the reverse reaction.
C. The concentration of reactant is greater than the concentration of product.
D. At equilibrium, the concentration of reactant is greater than the concentration of product.
Reactivity 2.3.6—The equilibrium law is the basis for quantifying the composition of an equilibrium mixture. Solve problems involving values of K and initial and equilibrium concentrations of the components of an equilibrium mixture.
-
22M.1A.SL.TZ2.23:
0.50 mol of (g) and 0.50 mol of Br2 (g) are placed in a closed flask. The following equilibrium is established.
(g) + Br2 (g) 2Br (g)
The equilibrium mixture contains 0.80 mol of Br (g). What is the value of Kc?
A. 0.64
B. 1.3
C. 2.6
D. 64
- 19M.1A.HL.TZ2.23: Iodine and bromine gases were mixed and allowed to reach equilibrium. What is the value of the...
-
21M.1A.SL.TZ2.23:
Sulfur dioxide reacts with oxygen to form sulfur trioxide.
2SO2 (g) + O2 (g) 2SO3 (g) ΔH = −197 kJ
Which change increases the value of Kc?
A. increasing the temperature
B. decreasing the temperature
C. decreasing [SO2 (g)]
D. decreasing [SO3 (g)]
-
21M.2.HL.TZ2.7c:
SO2 (g), O2 (g) and SO3 (g) are mixed and allowed to reach equilibrium at 600 °C.
Determine the value of Kc at 600 °C.
-
22M.1A.HL.TZ1.23:
At equilibrium, the concentrations of chlorine and iodine are both 0.02 mol dm–3.
Cl2 (g) + (g) Cl (g) Kc = 454
What is the concentration of iodine monochloride, Cl?
A.B.
C.
D.
-
22M.1A.HL.TZ1.18:
Cl2 (g) + (g) Cl (g) Kc = 454
What is the Kc value for the reaction below?
2 Cl (g) Cl2 (g) + (g)
A.
B.
C.
D.
-
22N.1A.SL.TZ0.22:
Which substance is the reducing agent in the given reaction?
H+ (aq) + 2H2O (l) + 2MnO4− (aq) + 5SO2 (g) → 2Mn2+ (aq) + 5HSO4− (aq)
A. H+B. H2O
C. MnO4−
D. SO2
-
22N.1A.HL.TZ0.22:
For the reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) at a certain temperature, the equilibrium concentrations are (in mol dm−3):
[2] = 0.20, [Cl2] = 0.20, [Cl3] = 2.0
What is the value of Kc?
A. 0.25B. 50
C. 2500
D. 5000
-
22M.1A.SL.TZ2.23:
0.50 mol of (g) and 0.50 mol of Br2 (g) are placed in a closed flask. The following equilibrium is established.
(g) + Br2 (g) 2Br (g)
The equilibrium mixture contains 0.80 mol of Br (g). What is the value of Kc?
A. 0.64
B. 1.3
C. 2.6
D. 64
- 19M.1A.HL.TZ2.23: Iodine and bromine gases were mixed and allowed to reach equilibrium. What is the value of the...
-
21M.1A.SL.TZ2.23:
Sulfur dioxide reacts with oxygen to form sulfur trioxide.
2SO2 (g) + O2 (g) 2SO3 (g) ΔH = −197 kJ
Which change increases the value of Kc?
A. increasing the temperature
B. decreasing the temperature
C. decreasing [SO2 (g)]
D. decreasing [SO3 (g)]
-
21M.2.HL.TZ2.7c:
SO2 (g), O2 (g) and SO3 (g) are mixed and allowed to reach equilibrium at 600 °C.
Determine the value of Kc at 600 °C.
-
21M.2.HL.TZ2.c:
SO2 (g), O2 (g) and SO3 (g) are mixed and allowed to reach equilibrium at 600 °C.
Determine the value of Kc at 600 °C.
-
22M.1A.HL.TZ1.23:
At equilibrium, the concentrations of chlorine and iodine are both 0.02 mol dm–3.
Cl2 (g) + (g) Cl (g) Kc = 454
What is the concentration of iodine monochloride, Cl?
A.B.
C.
D.
-
22M.1A.HL.TZ1.18:
Cl2 (g) + (g) Cl (g) Kc = 454
What is the Kc value for the reaction below?
2 Cl (g) Cl2 (g) + (g)
A.
B.
C.
D.
-
22N.1A.SL.TZ0.22:
Which substance is the reducing agent in the given reaction?
H+ (aq) + 2H2O (l) + 2MnO4− (aq) + 5SO2 (g) → 2Mn2+ (aq) + 5HSO4− (aq)
A. H+B. H2O
C. MnO4−
D. SO2
-
22N.1A.HL.TZ0.22:
For the reaction 2 (g) + 3Cl2 (g) 2Cl3 (g) at a certain temperature, the equilibrium concentrations are (in mol dm−3):
[2] = 0.20, [Cl2] = 0.20, [Cl3] = 2.0
What is the value of Kc?
A. 0.25B. 50
C. 2500
D. 5000
Reactivity 2.3.7—The equilibrium constant and Gibbs energy change, ΔG, can both be used to measure the position of an equilibrium reaction.
- 22M.2.HL.TZ1.3c(i): State, giving a reason, whether the reaction is spontaneous or not at 298 K.
-
22M.2.HL.TZ1.3c(ii):
Calculate the value of the equilibrium constant, K, at 298 K. Use sections 1 and 2 of the data booklet.
- 19M.1A.HL.TZ1.23: Which is correct for a reaction with a positive change in Gibbs free energy, ΔGθ? A. The...
-
19M.2.HL.TZ2.6b:
Phenylethene is manufactured from benzene and ethene in a two-stage process. The overall reaction can be represented as follows with ΔGθ = +10.0 kJ mol−1 at 298 K.
Calculate the equilibrium constant for the overall conversion at 298 K, using section 1 of the data booklet.
-
19N.2.HL.TZ0.4a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
- 20N.1A.HL.TZ0.23: Which statement is correct for a spontaneous reaction?
- 22M.2.HL.TZ1.3c(i): State, giving a reason, whether the reaction is spontaneous or not at 298 K.
-
22M.2.HL.TZ1.3c(ii):
Calculate the value of the equilibrium constant, K, at 298 K. Use sections 1 and 2 of the data booklet.
- 22M.2.HL.TZ1.c(i): State, giving a reason, whether the reaction is spontaneous or not at 298 K.
-
22M.2.HL.TZ1.c(ii):
Calculate the value of the equilibrium constant, K, at 298 K. Use sections 1 and 2 of the data booklet.
- 19M.1A.HL.TZ1.23: Which is correct for a reaction with a positive change in Gibbs free energy, ΔGθ? A. The...
-
19M.2.HL.TZ2.6b:
Phenylethene is manufactured from benzene and ethene in a two-stage process. The overall reaction can be represented as follows with ΔGθ = +10.0 kJ mol−1 at 298 K.
Calculate the equilibrium constant for the overall conversion at 298 K, using section 1 of the data booklet.
-
19M.2.HL.TZ2.b:
Phenylethene is manufactured from benzene and ethene in a two-stage process. The overall reaction can be represented as follows with ΔGθ = +10.0 kJ mol−1 at 298 K.
Calculate the equilibrium constant for the overall conversion at 298 K, using section 1 of the data booklet.
-
19N.2.HL.TZ0.4a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
-
19N.2.HL.TZ0.a(iv):
Calculate the standard Gibbs free energy change, , in kJ mol−1, for the first dissociation of citric acid at 298 K, using section 1 of the data booklet.
- 20N.1A.HL.TZ0.23: Which statement is correct for a spontaneous reaction?