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DP IB Maths: AA HL

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5.10 Differential Equations

Question 1

Marks: 5

Consider the first-order differential equation

 fraction numerator d y over denominator d x end fraction plus fraction numerator 1 over denominator 2 x end fraction equals sin space 3 x space cos space 3 x 

Solve the equation given that y equals 0 when  x equals straight pi over 2,  giving your answer in the form  y equals f left parenthesis x right parenthesis.       .

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    Question 2a

    Marks: 4

    Use separation of variables to solve each of the following differential equations

    (a)
    fraction numerator d y over denominator d x end fraction equals fraction numerator 3 y to the power of 4 over denominator 4 x cubed end fraction
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      Question 2b

      Marks: 5
      (b)
      fraction numerator d y over denominator d x end fraction equals fraction numerator x squared over denominator y open parentheses straight pi minus x cubed close parentheses end fraction e to the power of y squared end exponent
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        Question 3a

        Marks: 5

        Solve each of the following differential equations for y which satisfies the given boundary condition, giving your answers in the form y equals f open parentheses x close parentheses.

        (a)
        cos space straight pi x to the power of 4 fraction numerator d y over denominator d x end fraction equals tan space straight pi x to the power of 4 open parentheses x over y close parentheses cubed semicolon space space space space space space space y open parentheses 0 close parentheses equals negative 3
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          Question 3b

          Marks: 6
          (b)
          e to the power of x squared end exponent cos e c space y fraction numerator d y over denominator d x end fraction equals x space sin space y semicolon space space space space space y open parentheses 0 close parentheses equals fraction numerator 3 straight pi over denominator 4 end fraction
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            Question 4a

            Marks: 8

            As the atoms in a sample of radioactive material undergo radioactive decay, the rate of change of the number of radioactive atoms remaining in the sample at any time t is proportional to the number, N, of radioactive atoms currently remaining.  The amount of time, lambda, that it takes for half the radioactive atoms in a sample of radioactive material to decay is known as the ­half-life of the material. 

            Let N subscript 0 be the number of radioactive atoms originally present in a sample. 

            (a)
            By first writing and solving an appropriate differential equation, show that the number of radioactive atoms remaining in the sample at any time t greater or equal than 0 may be expressed as
            N open parentheses t close parentheses equals N subscript 0 e to the power of negative fraction numerator ln space 2 over denominator lambda end fraction t end exponent
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              Question 4b

              Marks: 3

              Plutonium-239, a by-product of uranium fission reactors, has a half-life of 24000 years.

              (b)

              For a particular sample of Plutonium-239, determine how long it will take until less than 1% of the original radioactive Plutonium-239 atoms in the sample remain.

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                Question 5a

                Marks: 2

                Consider the standard logistic equation

                 fraction numerator d P over denominator d t end fraction equals k P open parentheses a minus P close parentheses 

                where P is the size of a population at time t greater or equal than 0,  and where k and a are positive constants.  Let the population at time t equals 0 be denoted by P subscript 0. 

                (a)
                Write down the solution to the logistic equation in the case where P subscript 0 equals a, using mathematical reasoning to justify your answer.
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                  Question 5b

                  Marks: 8
                  (b)
                  In the case where P subscript 0 not equal to alpha, show that the solution to the logistic equation is
                  P open parentheses t close parentheses equals fraction numerator a A e to the power of a k t end exponent over denominator 1 plus A e to the power of a k t end exponent end fraction  
                  where A is an arbitrary constant.
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                    Question 5c

                    Marks: 2
                    (c)

                    In the case where P subscript 0 not equal to alpha, write down an expression for A in terms of a and P subscript 0.

                    .
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                      Question 5d

                      Marks: 3
                      (d)
                      In the case where P subscript 0 not equal to 0, determine the behaviour of P as t becomes large.
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                        Question 5e

                        Marks: 4
                        (e)
                        In the case where 0 less than 2 P subscript 0 less than a, determine the value of t at which the initial population will have doubled.  Your answer should be given explicitly in terms of a comma k spaceand P subscript 0.

                         

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                          Question 6

                          Marks: 8

                          Solve the differential equation

                          x fraction numerator d y over denominator d x end fraction minus y equals fraction numerator x y squared over denominator y squared sin open parentheses y over x close parentheses minus x squared cos open parentheses x over y close parentheses end fraction

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                            Question 7a

                            Marks: 9

                            Consider the differential equation

                            x squared y apostrophe equals y squared plus 3 x y minus 8 x squared 

                            with the boundary condition y open parentheses 1 close parentheses equals negative 3

                            (a)
                            Solve the differential equation for y which satisfies the given boundary condition, giving your answer in the form y equals f open parentheses x close parentheses.
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                              Question 7b

                              Marks: 3
                              (b)
                              Determine the asymptotic behaviour of the graph of the solution as x becomes large.
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                                Question 8

                                Marks: 7

                                Solve the differential equation

                                open parentheses 4 x squared plus 1 close parentheses y apostrophe plus y equals fraction numerator 1 minus x plus 4 x squared minus 4 x cubed over denominator square root of e to the power of arctan space 2 x end exponent end root end fraction

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                                  Key Concepts
                                  Integrating Factor

                                  Question 9a

                                  Marks: 3

                                  Consider the differential equation

                                   fraction numerator d y over denominator d x end fraction equals fraction numerator 5 over denominator square root of 63 plus 11 x squared minus 2 x to the power of 4 end root end fraction minus fraction numerator 2 x y over denominator 2 x squared plus 7 end fraction 

                                  with the boundary condition y open parentheses negative fraction numerator 3 square root of 2 over denominator 2 end fraction close parentheses equals 1.

                                  (a)
                                  Apply Euler’s method with a step size of  h equals 0.2 to approximate the solution to the differential equation at x equals fraction numerator 2 minus 3 square root of 3 over denominator 2 end fraction .
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                                    Question 9b

                                    Marks: 7
                                    (b)
                                    Solve the differential equation analytically, for y which satisfies the given boundary condition.
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                                      Question 9c

                                      Marks: 3
                                      (c)
                                      (i)
                                      Compare your approximation from part (a) to the exact value of the solution at x equals fraction numerator 2 minus 3 square root of 2 over denominator 2 end fraction.
                                      (ii)
                                      Explain how the accuracy of the approximation in part (a) could be improved.

                                       

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                                        Question 10a

                                        Marks: 3

                                        A particle moves in a straight line, such that its displacement x at time t is described by the differential equation

                                         fraction numerator d x over denominator d t end fraction equals fraction numerator sin space t over denominator 1 plus cos squared t end fraction comma space space space space space space space space space space space 0 less or equal than t less or equal than 3 

                                        At time  t equals 1.6 comma space x equals 1. 

                                        (a)
                                        By using Euler’s method with a step length of 0.04, find an approximate value for x at time t equals 1.8.
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                                          Question 10b

                                          Marks: 7

                                          The diagram below shows a graph of the exact solution  x equals f open parentheses t close parentheses to the differential equation with the given boundary condition.

                                           q10b_5-10_differential-equations_veryhard_ib_aa_hl_maths_diagram

                                          Given that the graph of x equals f open parentheses t close parentheses  has exactly one point of inflection, find the exact value of the t-coordinate of the point of inflection.

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                                            Key Concepts
                                            Points of Inflection

                                            Question 10c

                                            Marks: 3
                                            (c)
                                            Hence determine whether the approximation found in part (a) will be an overestimate or an underestimate for the true value of x when t equals 1.8.  Be sure to use mathematical reasoning to justify your answer.
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