Directly related questions
-
22N.1A.SL.TZ0.2:
What life function is illustrated?
A. Nutrition
B. Homeostasis
C. Endocytosis
D. Response
-
22N.1A.SL.TZ0.2:
What life function is illustrated?
A. Nutrition
B. Homeostasis
C. Endocytosis
D. Response
- 22N.1A.SL.TZ0.3: What would happen if the unicellular organism was placed in a solution slightly less concentrated...
- 22N.1A.SL.TZ0.3: What would happen if the unicellular organism was placed in a solution slightly less concentrated...
- 22N.1A.HL.TZ0.26: In transcription, which enzyme has a role similar to that of helicase in replication? A. DNA...
- 22N.1A.HL.TZ0.26: In transcription, which enzyme has a role similar to that of helicase in replication? A. DNA...
- 22N.1A.SL.TZ0.10: A DNA triplet on the strand that is transcribed has the bases TAG. Which anticodon on tRNA is...
- 22N.1A.SL.TZ0.10: A DNA triplet on the strand that is transcribed has the bases TAG. Which anticodon on tRNA is...
- 22N.1A.SL.TZ0.13: What is a difference between two alleles of a gene? A. Their positions on homologous...
- 22N.1A.SL.TZ0.13: What is a difference between two alleles of a gene? A. Their positions on homologous...
- 22N.1A.SL.TZ0.14: Which event occurs in the first division of meiosis? A. Synthesis of DNA B. Pulling apart of...
- 22N.1A.SL.TZ0.14: Which event occurs in the first division of meiosis? A. Synthesis of DNA B. Pulling apart of...
-
22N.1A.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
-
22N.1A.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
-
22N.1A.SL.TZ0.20:
By the end of the 19th century in England, the dark form of the moth Biston betularia formed up to 98% of the total population in industrial areas. From 1970, the percentage of dark forms decreased significantly. What is an explanation for the decrease?
A. An increase in environmental pollution killed the dark forms more than the light forms.
B. Reduction of pollution resulted in greater camouflage for light forms of the moth.
C. Dark forms could no longer find mates.
D. Light forms had superior feeding mechanisms.
-
22N.1A.SL.TZ0.20:
By the end of the 19th century in England, the dark form of the moth Biston betularia formed up to 98% of the total population in industrial areas. From 1970, the percentage of dark forms decreased significantly. What is an explanation for the decrease?
A. An increase in environmental pollution killed the dark forms more than the light forms.
B. Reduction of pollution resulted in greater camouflage for light forms of the moth.
C. Dark forms could no longer find mates.
D. Light forms had superior feeding mechanisms.
- 22N.1A.SL.TZ0.29: The graph shows human body temperature variation in a daily rhythm of 24 hours. Which hormone...
- 22N.1A.SL.TZ0.29: The graph shows human body temperature variation in a daily rhythm of 24 hours. Which hormone...
-
22N.1A.HL.TZ0.27:
The diagram illustrates some of the processes involved in DNA replication.
[Source: Rohrmann, G., 2019. AcMNPV DNA replication. [diagram online] Available at:
https://www.ncbi.nlm.nih.gov/books/NBK543453/figure/ch05.F1/ [Accessed 26 October 2021].]What is shown in the diagram?
A. DNA polymerase bonding nucleotides in a 3’ to 5’ direction
B. Single-stranded DNA-binding proteins on the old strands
C. Gyrase reforming the double helix
D. DNA ligase joining Okazaki fragments in the leading strand
-
22N.1A.HL.TZ0.27:
The diagram illustrates some of the processes involved in DNA replication.
[Source: Rohrmann, G., 2019. AcMNPV DNA replication. [diagram online] Available at:
https://www.ncbi.nlm.nih.gov/books/NBK543453/figure/ch05.F1/ [Accessed 26 October 2021].]What is shown in the diagram?
A. DNA polymerase bonding nucleotides in a 3’ to 5’ direction
B. Single-stranded DNA-binding proteins on the old strands
C. Gyrase reforming the double helix
D. DNA ligase joining Okazaki fragments in the leading strand
- 22N.1A.HL.TZ0.28: The diagram shows a ribosome and associated mRNA Which of these events occurs first in...
- 22N.1A.HL.TZ0.28: The diagram shows a ribosome and associated mRNA Which of these events occurs first in...
- 22N.1A.HL.TZ0.35: Black, short-haired guinea pigs, heterozygous for both characteristics, were crossed. They...
- 22N.1A.HL.TZ0.35: Black, short-haired guinea pigs, heterozygous for both characteristics, were crossed. They...
- 22N.1A.HL.TZ0.40: What is the role of HCG in pregnancy? A. It is secreted by the embryo to stimulate progesterone...
- 22N.1A.HL.TZ0.40: What is the role of HCG in pregnancy? A. It is secreted by the embryo to stimulate progesterone...
- 22N.1A.HL.TZ0.39: Which step occurs in both spermatogenesis and oogenesis? A. First division of meiosis is stopped...
- 22N.1A.HL.TZ0.39: Which step occurs in both spermatogenesis and oogenesis? A. First division of meiosis is stopped...
- 22N.2.SL.TZ0.3c: State one other gas that contributes to global warming.
- 22N.2.SL.TZ0.3c: State one other gas that contributes to global warming.
- 22N.2.SL.TZ0.c: State one other gas that contributes to global warming.
-
22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.3a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
-
22N.2.SL.TZ0.3a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
-
22N.2.SL.TZ0.a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
-
22N.2.SL.TZ0.3b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
-
22N.2.SL.TZ0.3b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
-
22N.2.SL.TZ0.b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
-
22N.2.HL.TZ0.4b:
Outline how nucleosomes affect the transcription of DNA.
-
22N.2.HL.TZ0.4b:
Outline how nucleosomes affect the transcription of DNA.
-
22N.2.HL.TZ0.b:
Outline how nucleosomes affect the transcription of DNA.
- 22N.2.HL.TZ0.4c.i: Identify X, the enzyme which copies a DNA sequence.
- 22N.2.HL.TZ0.4c.i: Identify X, the enzyme which copies a DNA sequence.
- 22N.2.HL.TZ0.c.i: Identify X, the enzyme which copies a DNA sequence.
- 22N.2.HL.TZ0.5a.i: Identify structure X.
- 22N.2.HL.TZ0.5a.i: Identify structure X.
- 22N.2.HL.TZ0.a.i: Identify structure X.
- 22N.2.HL.TZ0.5a.ii: Identify structure Y.
- 22N.2.HL.TZ0.5a.ii: Identify structure Y.
- 22N.2.HL.TZ0.a.ii: Identify structure Y.
-
22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
-
22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
-
22N.2.SL.TZ0.b:
Calculate the probability of male Y having an allele for the disorder.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.2.SL.TZ0.c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
-
22N.2.SL.TZ0.4d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
-
22N.2.SL.TZ0.4d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
-
22N.2.SL.TZ0.d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
- 22N.2.HL.TZ0.4c.ii: Identify Y, non-coding DNA at the start of a gene.
- 22N.2.HL.TZ0.4c.ii: Identify Y, non-coding DNA at the start of a gene.
- 22N.2.HL.TZ0.c.ii: Identify Y, non-coding DNA at the start of a gene.
-
22N.2.HL.TZ0.4e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
22N.2.HL.TZ0.4e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
22N.2.HL.TZ0.e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
22N.2.HL.TZ0.5b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.5b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.5c:
Explain the role of the hormone ADH in osmoregulation.
-
22N.2.HL.TZ0.5c:
Explain the role of the hormone ADH in osmoregulation.
-
22N.2.HL.TZ0.c:
Explain the role of the hormone ADH in osmoregulation.
- 22N.2.HL.TZ0.6a: Outline the processes occurring during interphase in the cell cycle.
- 22N.2.HL.TZ0.6a: Outline the processes occurring during interphase in the cell cycle.
- 22N.2.HL.TZ0.a: Outline the processes occurring during interphase in the cell cycle.
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.HL.TZ0.b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
- SPM.2.HL.TZ0.a: Identify the recombinant phenotypes amongst the offspring.
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
SPM.2.HL.TZ0.a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
- SPM.2.HL.TZ0.c: Describe the use of gene knockout technology in research.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
-
SPM.2.SL.TZ0.b:
Outline one example of a human disease caused by an autosomal recessive allele.
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
- SPM.2.SL.TZ0.b: Explain how sexual reproduction gives rise to genetic variation.
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
-
SPM.2.SL.TZ0.a:
Explain the mechanisms involved in thermoregulation in humans.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
-
SPM.2.SL.TZ0.c:
Explain the role of mutations in evolution.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.iii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
Sub sections and their related questions
D1.1. DNA replication
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.1A.HL.TZ2.13: A nucleotide containing dideoxyribose is shown. What is the reason for the use of...
-
21M.2.HL.TZ2.7b:
Outline the role of three enzymes used in the replication of DNA.
- 21N.1A.SL.TZ0.16: The image shows the result of DNA profiling of a mother, a child and four men. Which man is most...
- 19M.1A.HL.TZ2.12: What are the functions of DNA primase and DNA polymerase I in DNA replication?
-
22M.2.SL.TZ1.8b:
Describe how DNA profiling can be used to establish paternity.
- 19N.1A.SL.TZ0.17: What is PCR used for? A. Separate fragments of DNA by size B. Amplify small amounts of DNA C....
-
22M.1A.HL.TZ1.28:
This DNA sequence was used to synthesize a polypeptide.
DNA (sense strand): 3′ T A C T G A 5′
DNA (template strand): 5′ A T G A C T 3′
Which are the bases of the tRNA (anticodons)?
A. T A C T G A
B. U A C U G A
C. A U G A C U
D. A T G A C T
-
22M.2.SL.TZ2.7b:
Describe the function of three named enzymes involved in DNA replication.
- 20N.1A.SL.TZ0.27: Which are two proteins that assist in the unwinding and separation of DNA strands during...
- 19M.2.SL.TZ1.7a: Outline the roles of helicase and ligase in DNA replication.
-
20N.1A.SL.TZ0.10:
What is the reason for Taq DNA polymerase being used in the polymerase chain reaction (PCR)?
A. It does not denature at high temperatures.
B. It produces Okazaki fragments more rapidly.
C. It allows translation to proceed rapidly.
D. It works efficiently with helicase in PCR.
-
21M.2.SL.TZ1.8a:
Outline the process of DNA profiling.
-
21M.2.HL.TZ1.8b:
Outline the role of DNA polymerase III in DNA replication.
- 22M.1A.SL.TZ2.11: What is a function of the enzyme helicase? A. It coils DNA up into a double helical shape. B....
- 19N.1A.SL.TZ0.26: What is a function of DNA polymerase I? A. Adds nucleotides in a 5’ to 3’ direction to elongate...
- 22N.2.HL.TZ0.4c.i: Identify X, the enzyme which copies a DNA sequence.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
23M.2.HL.TZ1.7b:
Describe the processes that are carried out by enzymes that bind to DNA.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 19M.2.SL.TZ2.h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 19M.2.SL.TZ2.h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 19M.2.SL.TZ2.h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 19M.2.SL.TZ2.h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.2.SL.TZ2.1h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.1i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 19M.2.SL.TZ2.h: Identify, with a reason, the aphids that were most strongly repelled by EBF.
-
19M.2.SL.TZ2.i:
Outline the conclusions that can be drawn from the data in the graph for the group of aphids fed for three generations on transgenic thale cress plants (T).
- 22M.1A.HL.TZ1.26: The image shows a replication fork. Which row identifies X, Y and Z in the diagram?
- 19M.1A.HL.TZ2.13: A nucleotide containing dideoxyribose is shown. What is the reason for the use of...
-
21M.2.HL.TZ2.7b:
Outline the role of three enzymes used in the replication of DNA.
-
21M.2.HL.TZ2.b:
Outline the role of three enzymes used in the replication of DNA.
- 21N.1A.SL.TZ0.16: The image shows the result of DNA profiling of a mother, a child and four men. Which man is most...
- 19M.1A.HL.TZ2.12: What are the functions of DNA primase and DNA polymerase I in DNA replication?
-
22M.2.SL.TZ1.8b:
Describe how DNA profiling can be used to establish paternity.
-
22M.2.SL.TZ1.b:
Describe how DNA profiling can be used to establish paternity.
- 19N.1A.SL.TZ0.17: What is PCR used for? A. Separate fragments of DNA by size B. Amplify small amounts of DNA C....
-
22M.1A.HL.TZ1.28:
This DNA sequence was used to synthesize a polypeptide.
DNA (sense strand): 3′ T A C T G A 5′
DNA (template strand): 5′ A T G A C T 3′
Which are the bases of the tRNA (anticodons)?
A. T A C T G A
B. U A C U G A
C. A U G A C U
D. A T G A C T
-
22M.2.SL.TZ2.7b:
Describe the function of three named enzymes involved in DNA replication.
-
22M.2.SL.TZ2.b:
Describe the function of three named enzymes involved in DNA replication.
- 20N.1A.SL.TZ0.27: Which are two proteins that assist in the unwinding and separation of DNA strands during...
- 19M.2.SL.TZ1.7a: Outline the roles of helicase and ligase in DNA replication.
- 19M.2.SL.TZ1.a: Outline the roles of helicase and ligase in DNA replication.
-
20N.1A.SL.TZ0.10:
What is the reason for Taq DNA polymerase being used in the polymerase chain reaction (PCR)?
A. It does not denature at high temperatures.
B. It produces Okazaki fragments more rapidly.
C. It allows translation to proceed rapidly.
D. It works efficiently with helicase in PCR.
-
21M.2.SL.TZ1.8a:
Outline the process of DNA profiling.
-
21M.2.HL.TZ1.8b:
Outline the role of DNA polymerase III in DNA replication.
-
21M.2.SL.TZ1.a:
Outline the process of DNA profiling.
-
21M.2.HL.TZ1.b:
Outline the role of DNA polymerase III in DNA replication.
- 22M.1A.SL.TZ2.11: What is a function of the enzyme helicase? A. It coils DNA up into a double helical shape. B....
- 19N.1A.SL.TZ0.26: What is a function of DNA polymerase I? A. Adds nucleotides in a 5’ to 3’ direction to elongate...
- 22N.2.HL.TZ0.4c.i: Identify X, the enzyme which copies a DNA sequence.
- 22N.2.HL.TZ0.c.i: Identify X, the enzyme which copies a DNA sequence.
-
SPM.1A.HL.TZ0.9:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
SPM.1A.SL.TZ0.7:
What is a reason that Taq polymerase is a suitable enzyme for use in the polymerase chain reaction (PCR)?
A. It can work at a wide range of pH.B. It works at higher temperatures than most enzymes.
C. It can separate two strands of DNA.
D. It allows DNA to be replicated without the use of primers.
-
23M.2.HL.TZ1.7b:
Describe the processes that are carried out by enzymes that bind to DNA.
-
23M.2.HL.TZ1.b:
Describe the processes that are carried out by enzymes that bind to DNA.
D1.2. Protein synthesis
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
20N.2.HL.TZ0.6c:
Explain how polypeptides are produced by the process of translation.
- 21N.1A.SL.TZ0.11: The data shows part of the genetic code for mRNA. Which anticodon could be found on a tRNA...
- 19N.2.SL.TZ0.2a: Outline the function of codons.
- 19N.2.SL.TZ0.2b.i: Determine the sequence of amino acids that could be translated from the sequence of mRNA.
- 19N.2.SL.TZ0.2b.ii: Determine the DNA base sequence transcribed to form this sequence of mRNA.
- 19N.2.SL.TZ0.2c: Suggest a hypothesis that accounts for the slightly different meaning of some codons in a very...
- 19N.2.SL.TZ0.2d.ii: State the type of reaction that removes water while linking amino acids together to form...
- 19M.1A.HL.TZ2.14: What applies to DNA base sequences? I. Some genes do not code for proteins. II. Promoters are...
- 22M.1A.SL.TZ1.10: What is the minimum number of nucleotides needed to code for a polypeptide composed of 210 amino...
- 22M.1A.HL.TZ2.27: Promoters are non-coding regions in DNA. What is the role of a promoter? A. It starts...
-
19M.2.HL.TZ2.2a.iii:
DNA has regions that do not code for proteins. State two functions of these regions.
1.
2.
- 21M.1A.HL.TZ2.28: The mRNA codon UAC codes for the amino acid tyrosine. Which tRNA carries tyrosine?
-
22M.1A.HL.TZ1.28:
This DNA sequence was used to synthesize a polypeptide.
DNA (sense strand): 3′ T A C T G A 5′
DNA (template strand): 5′ A T G A C T 3′
Which are the bases of the tRNA (anticodons)?
A. T A C T G A
B. U A C U G A
C. A U G A C U
D. A T G A C T
- 21M.1A.HL.TZ1.26: Which regions of DNA code for the production of specific proteins? A. Telomeres B. Genes for...
- 21M.1A.SL.TZ1.27: Which statement applies to tRNA? A. There is at least one type of tRNA that combines with each...
-
22M.2.SL.TZ2.6a:
Outline how a protein is made in a cell by the process of translation.
- 19M.1A.HL.TZ2.9: The base sequences of a short section of DNA are shown, together with mRNA that has been...
-
20N.1A.SL.TZ0.28:
The diagram shows the three-dimensional structure of tRNA.
[Source: Structure reproduced with the kind permission of N.R. Voss.]
What can attach to the region marked X?
A. mRNA
B. An amino acid
C. An anticodon
D. The P site of the ribosome
-
21M.1A.SL.TZ2.27:
What is a feature of transcription in the single-celled organism shown in the electron micrograph?
[Source: George E. Palade Electron Microscopy Slide Collection Harvey Cushing/John Hay Whitney Medical Library Yale University Library.]
A. mRNA splicing
B. Removal of introns
C. Codon-anticodon binding
D. Synthesis of RNA in a 5′ to 3′ direction
-
20N.1A.SL.TZ0.9:
The diagram represents transcription and translation.
[Source: © International Baccalaureate Organization 2020.]
What structures do the letters X and Y represent?
-
19N.1A.SL.TZ0.7:
The diagram shows mRNA codons.
[Source: elementix / Alamy Stock Photo]
The mRNA sequence UGGAACGUA codes for what amino acid sequence?
A. Glycine-Glutamine-Methionine
B. Methionine-Glutamine-Glycine
C. Threonine-Valine-Histidine
D. Tryptophan-Asparagine-Valine
-
21N.2.HL.TZ0.6b:
Explain transcription.
- 19M.1A.SL.TZ1.10: The gene that codes for a particular polypeptide includes the base sequence...
-
19M.1A.SL.TZ1.27:
The diagram shows the arrangement of introns and exons in a segment of pre-mRNA. Pre-mRNA is immature mRNA containing introns and exons.
Which is a mature mRNA molecule derived from the pre-mRNA by splicing?
[Source: © International Baccalaureate Organization 2019]
- 19M.2.SL.TZ1.7a: Outline the stages in the production of mRNA by transcription.
- 19N.2.SL.TZ0.6c: Explain how a polypeptide chain is synthesized in a eukaryotic cell.
- 20N.1A.SL.TZ0.8: The genetic code is shown. In a coding gene, the DNA triplet in the transcribed strand is...
-
22N.2.SL.TZ0.4d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
- 22N.2.HL.TZ0.4c.ii: Identify Y, non-coding DNA at the start of a gene.
-
22N.1A.HL.TZ0.27:
The diagram illustrates some of the processes involved in DNA replication.
[Source: Rohrmann, G., 2019. AcMNPV DNA replication. [diagram online] Available at:
https://www.ncbi.nlm.nih.gov/books/NBK543453/figure/ch05.F1/ [Accessed 26 October 2021].]What is shown in the diagram?
A. DNA polymerase bonding nucleotides in a 3’ to 5’ direction
B. Single-stranded DNA-binding proteins on the old strands
C. Gyrase reforming the double helix
D. DNA ligase joining Okazaki fragments in the leading strand
- 22N.1A.HL.TZ0.26: In transcription, which enzyme has a role similar to that of helicase in replication? A. DNA...
- 22N.1A.SL.TZ0.10: A DNA triplet on the strand that is transcribed has the bases TAG. Which anticodon on tRNA is...
- 22N.1A.HL.TZ0.28: The diagram shows a ribosome and associated mRNA Which of these events occurs first in...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- 23M.1A.SL.TZ1.27: The image shows leucyl-tRNA synthetase from Thermus thermophilus complexed with a tRNA. This...
- 23M.1A.SL.TZ2.7: What is the proteome of an individual? A. The amino acids unique to an individual making up the...
- 23M.1A.SL.TZ2.9: The anticodons of three tRNAs and the amino acids they carry are shown in the table. tRNA...
- 23M.1A.SL.TZ2.11: The anticodons of three tRNAs and the amino acids they carry are shown in the table. tRNA...
- 23M.1A.HL.TZ2.23: What happens to an RNA molecule in eukaryotes after transcription in order to process it into...
- 23M.1A.SL.TZ2.25: The graph shows the energy changes during a chemical reaction. The horizontal lines represent the...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
-
22M.2.SL.TZ1.c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
-
22M.2.SL.TZ1.c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
-
22M.2.SL.TZ1.c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
-
22M.2.SL.TZ1.c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
22M.2.SL.TZ1.4c:
Outline the role of tRNA in hemoglobin synthesis.
-
22M.2.SL.TZ1.c:
Outline the role of tRNA in hemoglobin synthesis.
- 22M.1A.HL.TZ1.27: During modification in eukaryotes, mRNA is spliced. What is splicing of mRNA? A. Separation of...
- 22M.1A.SL.TZ1.7: What is a universal characteristic of the genetic code? A. There are more than 64 different...
-
20N.2.HL.TZ0.6c:
Explain how polypeptides are produced by the process of translation.
-
20N.2.HL.TZ0.c:
Explain how polypeptides are produced by the process of translation.
- 21N.1A.SL.TZ0.11: The data shows part of the genetic code for mRNA. Which anticodon could be found on a tRNA...
- 19N.2.SL.TZ0.a: Outline the function of codons.
- 19N.2.SL.TZ0.b.i: Determine the sequence of amino acids that could be translated from the sequence of mRNA.
- 19N.2.SL.TZ0.b.ii: Determine the DNA base sequence transcribed to form this sequence of mRNA.
- 19N.2.SL.TZ0.c: Suggest a hypothesis that accounts for the slightly different meaning of some codons in a very...
- 19N.2.SL.TZ0.d.ii: State the type of reaction that removes water while linking amino acids together to form...
- 19M.1A.HL.TZ2.14: What applies to DNA base sequences? I. Some genes do not code for proteins. II. Promoters are...
- 22M.1A.SL.TZ1.10: What is the minimum number of nucleotides needed to code for a polypeptide composed of 210 amino...
- 22M.1A.HL.TZ2.27: Promoters are non-coding regions in DNA. What is the role of a promoter? A. It starts...
-
19M.2.HL.TZ2.2a.iii:
DNA has regions that do not code for proteins. State two functions of these regions.
1.
2.
-
19M.2.HL.TZ2.a.iii:
DNA has regions that do not code for proteins. State two functions of these regions.
1.
2.
- 21M.1A.HL.TZ2.28: The mRNA codon UAC codes for the amino acid tyrosine. Which tRNA carries tyrosine?
-
22M.1A.HL.TZ1.28:
This DNA sequence was used to synthesize a polypeptide.
DNA (sense strand): 3′ T A C T G A 5′
DNA (template strand): 5′ A T G A C T 3′
Which are the bases of the tRNA (anticodons)?
A. T A C T G A
B. U A C U G A
C. A U G A C U
D. A T G A C T
- 21M.1A.HL.TZ1.26: Which regions of DNA code for the production of specific proteins? A. Telomeres B. Genes for...
- 21M.1A.SL.TZ1.27: Which statement applies to tRNA? A. There is at least one type of tRNA that combines with each...
-
22M.2.SL.TZ2.6a:
Outline how a protein is made in a cell by the process of translation.
-
22M.2.SL.TZ2.a:
Outline how a protein is made in a cell by the process of translation.
- 19M.1A.HL.TZ2.9: The base sequences of a short section of DNA are shown, together with mRNA that has been...
-
20N.1A.SL.TZ0.28:
The diagram shows the three-dimensional structure of tRNA.
[Source: Structure reproduced with the kind permission of N.R. Voss.]
What can attach to the region marked X?
A. mRNA
B. An amino acid
C. An anticodon
D. The P site of the ribosome
-
21M.1A.SL.TZ2.27:
What is a feature of transcription in the single-celled organism shown in the electron micrograph?
[Source: George E. Palade Electron Microscopy Slide Collection Harvey Cushing/John Hay Whitney Medical Library Yale University Library.]
A. mRNA splicing
B. Removal of introns
C. Codon-anticodon binding
D. Synthesis of RNA in a 5′ to 3′ direction
-
20N.1A.SL.TZ0.9:
The diagram represents transcription and translation.
[Source: © International Baccalaureate Organization 2020.]
What structures do the letters X and Y represent?
-
19N.1A.SL.TZ0.7:
The diagram shows mRNA codons.
[Source: elementix / Alamy Stock Photo]
The mRNA sequence UGGAACGUA codes for what amino acid sequence?
A. Glycine-Glutamine-Methionine
B. Methionine-Glutamine-Glycine
C. Threonine-Valine-Histidine
D. Tryptophan-Asparagine-Valine
-
21N.2.HL.TZ0.6b:
Explain transcription.
-
21N.2.HL.TZ0.b:
Explain transcription.
- 19M.1A.SL.TZ1.10: The gene that codes for a particular polypeptide includes the base sequence...
-
19M.1A.SL.TZ1.27:
The diagram shows the arrangement of introns and exons in a segment of pre-mRNA. Pre-mRNA is immature mRNA containing introns and exons.
Which is a mature mRNA molecule derived from the pre-mRNA by splicing?
[Source: © International Baccalaureate Organization 2019]
- 19M.2.SL.TZ1.7a: Outline the stages in the production of mRNA by transcription.
- 19M.2.SL.TZ1.a: Outline the stages in the production of mRNA by transcription.
- 19N.2.SL.TZ0.6c: Explain how a polypeptide chain is synthesized in a eukaryotic cell.
- 19N.2.SL.TZ0.c: Explain how a polypeptide chain is synthesized in a eukaryotic cell.
- 20N.1A.SL.TZ0.8: The genetic code is shown. In a coding gene, the DNA triplet in the transcribed strand is...
-
22N.2.SL.TZ0.4d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
-
22N.2.SL.TZ0.d:
Explain how a single base substitution mutation in DNA can cause a change to a protein.
- 22N.2.HL.TZ0.4c.ii: Identify Y, non-coding DNA at the start of a gene.
- 22N.2.HL.TZ0.c.ii: Identify Y, non-coding DNA at the start of a gene.
-
22N.1A.HL.TZ0.27:
The diagram illustrates some of the processes involved in DNA replication.
[Source: Rohrmann, G., 2019. AcMNPV DNA replication. [diagram online] Available at:
https://www.ncbi.nlm.nih.gov/books/NBK543453/figure/ch05.F1/ [Accessed 26 October 2021].]What is shown in the diagram?
A. DNA polymerase bonding nucleotides in a 3’ to 5’ direction
B. Single-stranded DNA-binding proteins on the old strands
C. Gyrase reforming the double helix
D. DNA ligase joining Okazaki fragments in the leading strand
- 22N.1A.HL.TZ0.26: In transcription, which enzyme has a role similar to that of helicase in replication? A. DNA...
- 22N.1A.SL.TZ0.10: A DNA triplet on the strand that is transcribed has the bases TAG. Which anticodon on tRNA is...
- 22N.1A.HL.TZ0.28: The diagram shows a ribosome and associated mRNA Which of these events occurs first in...
- SPM.1A.HL.TZ0.10: Which are examples of non-coding DNA? A. Dominant and recessive alleles B. Promoters and...
- 23M.1A.SL.TZ1.27: The image shows leucyl-tRNA synthetase from Thermus thermophilus complexed with a tRNA. This...
- 23M.1A.SL.TZ2.7: What is the proteome of an individual? A. The amino acids unique to an individual making up the...
- 23M.1A.SL.TZ2.9: The anticodons of three tRNAs and the amino acids they carry are shown in the table. tRNA...
- 23M.1A.SL.TZ2.11: The anticodons of three tRNAs and the amino acids they carry are shown in the table. tRNA...
- 23M.1A.HL.TZ2.23: What happens to an RNA molecule in eukaryotes after transcription in order to process it into...
- 23M.1A.SL.TZ2.25: The graph shows the energy changes during a chemical reaction. The horizontal lines represent the...
D1.3. Mutations and gene editing
-
21N.2.SL.TZ0.3d:
All of the leaves in the image are from Solanum, a wild genus of tomato.
[Source: Courtesy: National Science Foundation, Credit Leonie Moyle.]
State one cause of variation in a plant such as the tomato.
- 20N.2.SL.TZ0.4b.i: Define mutation.
- 19M.2.SL.TZ2.4b: Explain one cause of mutation.
- 19M.1A.HL.TZ2.4: Which processes are involved in the development of cancer? I. Mutations occur in oncogenes. II....
- 19M.2.SL.TZ2.7c: Explain the cause of sickle cell anemia and how this disease affects humans.
-
21M.2.SL.TZ1.7b:
Explain how genetic variation between the individuals in a species can be generated.
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
-
23M.2.HL.TZ1.7c:
Explain the effects that the environment can have on DNA in living organisms.
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
-
21N.2.SL.TZ0.3d:
All of the leaves in the image are from Solanum, a wild genus of tomato.
[Source: Courtesy: National Science Foundation, Credit Leonie Moyle.]
State one cause of variation in a plant such as the tomato.
-
21N.2.SL.TZ0.d:
All of the leaves in the image are from Solanum, a wild genus of tomato.
[Source: Courtesy: National Science Foundation, Credit Leonie Moyle.]
State one cause of variation in a plant such as the tomato.
- 20N.2.SL.TZ0.4b.i: Define mutation.
- 20N.2.SL.TZ0.b.i: Define mutation.
- 19M.2.SL.TZ2.4b: Explain one cause of mutation.
- 19M.2.SL.TZ2.b: Explain one cause of mutation.
- 19M.1A.HL.TZ2.4: Which processes are involved in the development of cancer? I. Mutations occur in oncogenes. II....
- 19M.2.SL.TZ2.7c: Explain the cause of sickle cell anemia and how this disease affects humans.
- 19M.2.SL.TZ2.c: Explain the cause of sickle cell anemia and how this disease affects humans.
-
21M.2.SL.TZ1.7b:
Explain how genetic variation between the individuals in a species can be generated.
-
21M.2.SL.TZ1.b:
Explain how genetic variation between the individuals in a species can be generated.
- SPM.1A.HL.TZ0.11: The table shows the mRNA codons for three amino...
- SPM.1A.SL.TZ0.8: A strand of DNA containing four codons with base sequence ACT GTA CTC TAC mutates, changing the...
- SPM.2.HL.TZ0.10a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.10c: Describe the use of gene knockout technology in research.
- SPM.2.HL.TZ0.a: Outline the role of UV radiation as a mutagen.
- SPM.2.HL.TZ0.c: Describe the use of gene knockout technology in research.
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
-
SPM.2.SL.TZ0.7a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.7c:
Explain the role of mutations in evolution.
-
SPM.2.SL.TZ0.a:
Outline how mutation can lead to cancer.
-
SPM.2.SL.TZ0.c:
Explain the role of mutations in evolution.
- SPM.2.SL.TZ0.b: Explain how sexual reproduction gives rise to genetic variation.
-
23M.2.HL.TZ1.7c:
Explain the effects that the environment can have on DNA in living organisms.
-
23M.2.HL.TZ1.c:
Explain the effects that the environment can have on DNA in living organisms.
D2.1 Cell and nuclear division
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
21M.1A.SL.TZ1.17:
A two-cell sea urchin (Echinoidea) embryo was physically separated by scientists into two cells. Each cell, through further embryonic development, became an adult sea urchin.
[Source: Clker-Free-Vector-Images/Pixabay.]
What is the relationship between the two adult sea urchins?
A. They are equivalent to non-identical twins.
B. Half of the genes would be the same.
C. Both adults would have haploid cells.
D. They are clones.
- 21M.1A.SL.TZ1.35: Which statement is valid regarding chromatids? A. Sister chromatids separate during meiosis...
- 19N.1A.HL.TZ0.5: Students examined micrographs and counted cells in the different stages of mitosis as well as...
-
21M.1A.SL.TZ2.12:
The image shows tetrads in the anther of a lily. A tetrad is a group of four cells, produced when one mother cell divides by meiosis. The tetrad indicated by the arrow contains a total of 48 chromosomes.
[Source: [Tetrad], 2012. [image online] Available at: https://www.iasprr.org/old/iasprr-pix/lily/tetrad.jpg [accessed: 4 April 2019]. Photo courtesy of Professor Scott D. Russell.]
What is the diploid number of the plant?
A. 12
B. 24
C. 48
D. 96
-
21M.2.HL.TZ1.1c:
Based on the information, suggest with a reason which of the labelled cell types will become more common in Allium root tips treated with ZDV.
-
21M.2.HL.TZ1.1d:
Allium root tips continue to show some growth even at high concentrations of NVP. Suggest a possible reason for the growth seen in root tips with 800μmol NVP.
- 21M.2.HL.TZ1.1e: Deduce the change in mitotic index after 72 hours compared to the control.
-
21N.2.SL.TZ0.6b:
Explain the need for halving the chromosome number during a sexual life cycle and how this is done.
- 21N.2.SL.TZ0.2b.i: Draw the same chromosomes to show their structure at the same stage of meiosis if there had been...
- 21N.2.SL.TZ0.2b.ii: State the stage of meiosis where chiasmata formation may occur.
-
21N.1A.HL.TZ0.5:
The graph shows the mitotic index in the roots of lentil plants at different distances from the end of the root.
[Source: Physiologia Plantarum, Volume 105, Issue 1, January 1999, Pages 171–178, Effect of microgravity on the cell cycle
in the lentil root F. Yu, D. Driss-Ecole, J. Rembur, V. Legué, G. Perbal Wiley Online Library: https://onlinelibrary.wiley.
com/doi/abs/10.1034/j.1399-3054.1999.105125.x]What can be deduced from the graph?
A. As the distance from the end of the root increases, more cells are undergoing mitosis.
B. At 0.5 mm from the end of the root, most of the cells are in prophase.
C. There were fewer cells observed at 1.5 mm than at 0.5 mm.
D. As the distance from the end of the root increases, the percentage of cells in interphase increases.
-
19M.2.SL.TZ2.2a.i:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
- 19M.2.SL.TZ2.2a.ii: Outline what is indicated by the mitotic index of tissue taken from a tumour.
-
19M.1A.SL.TZ1.36:
The diagram shows the chromosomes derived from a single homologous pair following meiosis in a diploid cell.
Which diagram represents the homologous pair from which these chromosomes were derived?
[Source: © International Baccalaureate Organization 2019]
- 19M.1A.HL.TZ2.4: Which processes are involved in the development of cancer? I. Mutations occur in oncogenes. II....
-
22M.1A.SL.TZ2.14:
The karyogram shown belongs to a human being.
[Source: Reproduced from Tennakoon J, Kandasamy Y, Alcock G, Koh TH. Edwards syndrome with double trisomy. Singapore Med J. 2008 Jul;49(7):e190-1. PMID: 18695855.]
What can be deduced from this karyogram?
A. The person is a male with Down syndrome.
B. The person is a female with Down syndrome.
C. The person is a male with a genetic disorder.
D. The person is a female with a missing chromosome.
- 19M.2.SL.TZ1.2c.ii: State the haploid number for this nucleus.
-
19N.1A.SL.TZ0.4:
In the micrograph, which letter points to a cell in anaphase?
[Source: Berkshire Community College Bioscience Image Library,
https://commons.wikimedia.org/wiki/File:Mitotic_Stages_in_Apical_Meristem_of_Allium_Root_Tip_(36762516673).jpg,
licensed under Creative Commons CC0 1.0 Universal Public Domain Dedication] - 19N.1A.SL.TZ0.35: Which event happens in meiosis II but not in meiosis I? A. Spindle microtubules attach to...
- 21M.1A.SL.TZ2.35: What process occurs in both mitosis and meiosis? A. Formation of chiasmata B. Reduction...
- 22M.2.SL.TZ1.7b: Distinguish between the processes of meiosis and mitosis.
- 22M.1A.HL.TZ2.5: Cisplatin is an anti-cancer drug that prevents tumour cells from dividing by mitosis as it...
- 21M.1A.SL.TZ2.4: When does DNA replication occur? A. S phase of interphase B. Early prophase C. G phase of...
-
22M.1A.SL.TZ1.5:
In the chimpanzee (Pan troglodytes), the haploid number of chromosomes is 24. How many sister chromatids are present in the G2 phase of a somatic cell, such as a cell in the bone marrow of the chimpanzee?
A. 12
B. 24
C. 48
D. 96
- 19M.1A.HL.TZ1.5: The table shows the number of cells in various stages of the cell cycle in four samples of...
-
19M.1A.SL.TZ2.13:
The graph shows the incidence of trisomy resulting from non-disjunction in pregnancies at different maternal ages.
[Source: Center for Disease Control]
What can be inferred from the graph?
A. The incidence of three copies of a chromosome increases directly in proportion with the age of the mother.
B. The incidence of three sets of chromosomes increases from age 20.
C. The incidence of three copies of a chromosome increases the most from age 35.
D. The incidence of three sets of chromosomes increases the most from age 30.
- 21M.1A.SL.TZ1.19: Which statement applies to meiosis and mitosis? A. Meiosis occurs in a greater number of...
-
20N.2.SL.TZ0.6b:
Outline what occurs in cells in the first division of meiosis.
-
20N.1A.SL.TZ0.13:
Testing the chromosomes of a girl with Turner syndrome produced the following karyogram.
[Source: Turner’s syndrome karyotype 45,XO. This female lacks the second X chromosome present in the
normal karyotype. Symptoms include short stature, neck webbing, elbow deformity, widely spaced nipples with shield chest, primary amenorrhea, sexual infantilism and sterility. The ovaries are reduced to fibrous streaks. Also known as XO syndrome or ovarian short-stature syndrome. Credit: Wessex Reg. Genetics Centre. Attribution 4.0 International (CC BY 4.0).]The condition can result from non-disjunction occurring in anaphase I of meiosis in an egg cell. Two cells result from the first division, one of which would lead to Turner syndrome. Which chromosomes will be in the other cell (polar body) at the end of meiosis I?
A. 44 autosomes and X
B. 44 autosomes and XX
C. 22 autosomes and X
D. 22 autosomes and XX
-
21M.1B.SL.TZ1.1e:
By referring to both graphs, evaluate the hypothesis that vinblastine targets cells in mitosis and prevents them from completing the process.
-
21M.2.HL.TZ1.1g:
Discuss one advantage and one disadvantage of using plant tissue to investigate drugs intended to treat cancer in humans.
Advantage:
Disadvantage:
-
21M.2.HL.TZ2.2a:
State processes occurring during interphase.
-
21M.2.HL.TZ2.2b.i:
Using the letter C, label the stage on the diagram where chromosome supercoiling occurs.
-
21M.2.HL.TZ2.2b.ii:
Using the letter M, label the stage on the diagram where sister chromatids migrate to opposite poles.
-
21M.2.HL.TZ2.2c:
Distinguish between the outcomes of a cell dividing either by mitosis or meiosis.
-
21M.2.HL.TZ2.2d:
The mitotic index is an important prognostic tool for predicting the response of cancer cells to chemotherapy. Outline how the mitotic index is calculated.
-
19M.1A.SL.TZ1.14:
At which stage of meiosis are bivalents formed?
A. Interphase
B. Prophase I
C. Prophase II
D. Metaphase II
- 20N.1A.SL.TZ0.5: How many chromosomes are there in a cell during anaphase of mitosis, if the diploid number of the...
- 22M.1A.SL.TZ1.15: What is produced by meiosis in a cell of a male animal? A. Four gametes, each with the same...
-
22M.1A.HL.TZ1.4:
In which stage of the cell cycle are chromosomes duplicated?
[Source: M1llx, 2019. Cell cycle simple pl. [online] Available at: https://commons.wikimedia.org/wiki/File:Cell_cycle_simple_pl.png This file is licensed
under the Creative Commons Attribution-Share Alike 4.0 International license.
https://creativecommons.org/licenses/by-sa/4.0/deed.en [Accessed 1 August 2019].]A. G1 phase
B. G2 phase
C. S phase
D. Mitosis
- 19M.2.SL.TZ1.6b: Identify the chromosome that is affected by a trisomy in this individual, naming the condition...
-
19M.1A.SL.TZ2.3:
The image shows a micrograph of a cell.
[Source: © 2014, https://commons.wikimedia.org/wiki/File:Mitosis_(261_13)_Pressed;_root_meristem_of_onion_(cells_
in_prophase,_metaphase,_anaphase,_telophase).jpg by Doc. RNDr. Josef Reischig, CSc.]What explains the appearance of the cell in the micrograph?
A. The cell is dying.
B. The DNA is replicating.
C. The cell is in metaphase.
D. The cell is in telophase.
-
19M.2.SL.TZ2.2a:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
-
19M.1A.SL.TZ2.17:
The diagram shows a stage in cell division.
[Source: © International Baccalaureate Organization 2019]
What is the stage shown?
A. Anaphase I of mitosis
B. Anaphase II of mitosis
C. Anaphase I of meiosis
D. Anaphase II of meiosis
- 20N.1A.HL.TZ0.4: What would show that a person has developed metastatic cancer? A. Alveolus cells forming a...
- 22N.1A.SL.TZ0.14: Which event occurs in the first division of meiosis? A. Synthesis of DNA B. Pulling apart of...
- 22N.2.HL.TZ0.6a: Outline the processes occurring during interphase in the cell cycle.
- 21M.1A.HL.TZ1.7: A tissue sample was examined under the microscope in order to determine a mitotic index. The...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- 23M.2.SL.TZ1.7a: Outline the changes to chromosomes that occur during prophase in the first division of meiosis.
- 23M.2.SL.TZ1.6a: Outline the sequence of events that occurs during mitosis.
-
23M.2.HL.TZ2.6a:
Explain how changes to the cell cycle can result in tumour formation.
- 23M.2.HL.TZ2.3a: State one cause of lung cancer.
-
23M.2.HL.TZ2.3b:
Suggest one difference between tissue taken from a lung cancer tumour and normal lung tissue that might be seen in micrographs.
- 23M.2.HL.TZ2.3c: The lung tumour in the light micrograph was slow-growing. Predict with a reason what would have...
-
23M.1A.SL.TZ1.11:
The micrograph shows a cross section of a lily (Lilium longiflorum) anther.
[Source: Sinhyu / iStock.]
What can be found in X?
A. Haploid nuclei produced by meiosis
B. Diploid nuclei produced by fertilization
C. Haploid nuclei produced by mitosis
D. Diploid nuclei produced by pollination
- 23M.1A.SL.TZ1.36: What happens in the first division of meiosis? A. Formation of chiasmata where two sister...
- 23M.1A.SL.TZ1.15: Non-disjunction of chromosome 21 causes trisomy. What can be said about the incidence...
- 23M.1A.SL.TZ1.16: For what reason do gametes contain only one allele of each gene? A. To prevent inbreeding in a...
-
23M.1A.SL.TZ2.5:
The image shows a cell from the root tip of an onion (Allium cepa) (2n = 16) during late prophase of mitosis.
[Source: Davidson, M.W. and Molecular Expressions at Florida State University, n.d. Late prophase. [image online]
Available at: https://micro.magnet.fsu.edu/micro/gallery/mitosis/mitosis.html [Accessed 5 October 2021].]How many chromatids are present in the cell?
A. 8B. 16
C. 32
D. 64
-
23M.1A.SL.TZ2.5:
The image shows a cell from the root tip of an onion (Allium cepa) (2n = 16) during late prophase of mitosis.
[Source: Davidson, M.W. and Molecular Expressions at Florida State University, n.d. Late prophase. [image online]
Available at: https://micro.magnet.fsu.edu/micro/gallery/mitosis/mitosis.html [Accessed 5 October 2021].]How many chromatids are present in the cell?
A. 8B. 16
C. 32
D. 64
- 23M.1A.SL.TZ2.12: At what stage of meiosis do chromosome pairing and crossing over occur? A. Interphase B. ...
- 23M.1A.SL.TZ2.31: What is a result of crossing over in meiosis? A. Gene linkage B. Non-disjunction C. Haploid...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
-
22M.2.SL.TZ2.a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
-
22M.2.SL.TZ2.a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
-
22M.2.SL.TZ2.a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
-
22M.2.SL.TZ2.a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
22M.2.SL.TZ2.2a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.2a.iii:
State the role of cyclins in the cell cycle.
-
22M.2.SL.TZ2.a.i:
Identify, with a reason, the stage shown at X.
-
22M.2.HL.TZ2.a.iii:
State the role of cyclins in the cell cycle.
- 22M.1A.SL.TZ1.12: Which process occurs in meiosis but not in mitosis? A. Attachment of spindle fibres to the...
-
21M.1A.SL.TZ1.17:
A two-cell sea urchin (Echinoidea) embryo was physically separated by scientists into two cells. Each cell, through further embryonic development, became an adult sea urchin.
[Source: Clker-Free-Vector-Images/Pixabay.]
What is the relationship between the two adult sea urchins?
A. They are equivalent to non-identical twins.
B. Half of the genes would be the same.
C. Both adults would have haploid cells.
D. They are clones.
- 21M.1A.SL.TZ1.35: Which statement is valid regarding chromatids? A. Sister chromatids separate during meiosis...
- 19N.1A.HL.TZ0.5: Students examined micrographs and counted cells in the different stages of mitosis as well as...
-
21M.1A.SL.TZ2.12:
The image shows tetrads in the anther of a lily. A tetrad is a group of four cells, produced when one mother cell divides by meiosis. The tetrad indicated by the arrow contains a total of 48 chromosomes.
[Source: [Tetrad], 2012. [image online] Available at: https://www.iasprr.org/old/iasprr-pix/lily/tetrad.jpg [accessed: 4 April 2019]. Photo courtesy of Professor Scott D. Russell.]
What is the diploid number of the plant?
A. 12
B. 24
C. 48
D. 96
-
21M.2.HL.TZ1.1c:
Based on the information, suggest with a reason which of the labelled cell types will become more common in Allium root tips treated with ZDV.
-
21M.2.HL.TZ1.1d:
Allium root tips continue to show some growth even at high concentrations of NVP. Suggest a possible reason for the growth seen in root tips with 800μmol NVP.
- 21M.2.HL.TZ1.1e: Deduce the change in mitotic index after 72 hours compared to the control.
-
21M.2.HL.TZ1.c:
Based on the information, suggest with a reason which of the labelled cell types will become more common in Allium root tips treated with ZDV.
-
21M.2.HL.TZ1.d:
Allium root tips continue to show some growth even at high concentrations of NVP. Suggest a possible reason for the growth seen in root tips with 800μmol NVP.
- 21M.2.HL.TZ1.e: Deduce the change in mitotic index after 72 hours compared to the control.
-
21N.2.SL.TZ0.6b:
Explain the need for halving the chromosome number during a sexual life cycle and how this is done.
-
21N.2.SL.TZ0.b:
Explain the need for halving the chromosome number during a sexual life cycle and how this is done.
- 21N.2.SL.TZ0.2b.i: Draw the same chromosomes to show their structure at the same stage of meiosis if there had been...
- 21N.2.SL.TZ0.2b.ii: State the stage of meiosis where chiasmata formation may occur.
- 21N.2.SL.TZ0.b.i: Draw the same chromosomes to show their structure at the same stage of meiosis if there had been...
- 21N.2.SL.TZ0.b.ii: State the stage of meiosis where chiasmata formation may occur.
-
21N.1A.HL.TZ0.5:
The graph shows the mitotic index in the roots of lentil plants at different distances from the end of the root.
[Source: Physiologia Plantarum, Volume 105, Issue 1, January 1999, Pages 171–178, Effect of microgravity on the cell cycle
in the lentil root F. Yu, D. Driss-Ecole, J. Rembur, V. Legué, G. Perbal Wiley Online Library: https://onlinelibrary.wiley.
com/doi/abs/10.1034/j.1399-3054.1999.105125.x]What can be deduced from the graph?
A. As the distance from the end of the root increases, more cells are undergoing mitosis.
B. At 0.5 mm from the end of the root, most of the cells are in prophase.
C. There were fewer cells observed at 1.5 mm than at 0.5 mm.
D. As the distance from the end of the root increases, the percentage of cells in interphase increases.
-
19M.2.SL.TZ2.2a.i:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
- 19M.2.SL.TZ2.2a.ii: Outline what is indicated by the mitotic index of tissue taken from a tumour.
-
19M.2.SL.TZ2.a.i:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
- 19M.2.SL.TZ2.a.ii: Outline what is indicated by the mitotic index of tissue taken from a tumour.
-
19M.1A.SL.TZ1.36:
The diagram shows the chromosomes derived from a single homologous pair following meiosis in a diploid cell.
Which diagram represents the homologous pair from which these chromosomes were derived?
[Source: © International Baccalaureate Organization 2019]
- 19M.1A.HL.TZ2.4: Which processes are involved in the development of cancer? I. Mutations occur in oncogenes. II....
-
22M.1A.SL.TZ2.14:
The karyogram shown belongs to a human being.
[Source: Reproduced from Tennakoon J, Kandasamy Y, Alcock G, Koh TH. Edwards syndrome with double trisomy. Singapore Med J. 2008 Jul;49(7):e190-1. PMID: 18695855.]
What can be deduced from this karyogram?
A. The person is a male with Down syndrome.
B. The person is a female with Down syndrome.
C. The person is a male with a genetic disorder.
D. The person is a female with a missing chromosome.
- 19M.2.SL.TZ1.2c.ii: State the haploid number for this nucleus.
- 19M.2.SL.TZ1.c.ii: State the haploid number for this nucleus.
-
19N.1A.SL.TZ0.4:
In the micrograph, which letter points to a cell in anaphase?
[Source: Berkshire Community College Bioscience Image Library,
https://commons.wikimedia.org/wiki/File:Mitotic_Stages_in_Apical_Meristem_of_Allium_Root_Tip_(36762516673).jpg,
licensed under Creative Commons CC0 1.0 Universal Public Domain Dedication] - 19N.1A.SL.TZ0.35: Which event happens in meiosis II but not in meiosis I? A. Spindle microtubules attach to...
- 21M.1A.SL.TZ2.35: What process occurs in both mitosis and meiosis? A. Formation of chiasmata B. Reduction...
- 22M.2.SL.TZ1.7b: Distinguish between the processes of meiosis and mitosis.
- 22M.2.SL.TZ1.b: Distinguish between the processes of meiosis and mitosis.
- 22M.1A.HL.TZ2.5: Cisplatin is an anti-cancer drug that prevents tumour cells from dividing by mitosis as it...
- 21M.1A.SL.TZ2.4: When does DNA replication occur? A. S phase of interphase B. Early prophase C. G phase of...
-
22M.1A.SL.TZ1.5:
In the chimpanzee (Pan troglodytes), the haploid number of chromosomes is 24. How many sister chromatids are present in the G2 phase of a somatic cell, such as a cell in the bone marrow of the chimpanzee?
A. 12
B. 24
C. 48
D. 96
- 19M.1A.HL.TZ1.5: The table shows the number of cells in various stages of the cell cycle in four samples of...
-
19M.1A.SL.TZ2.13:
The graph shows the incidence of trisomy resulting from non-disjunction in pregnancies at different maternal ages.
[Source: Center for Disease Control]
What can be inferred from the graph?
A. The incidence of three copies of a chromosome increases directly in proportion with the age of the mother.
B. The incidence of three sets of chromosomes increases from age 20.
C. The incidence of three copies of a chromosome increases the most from age 35.
D. The incidence of three sets of chromosomes increases the most from age 30.
- 21M.1A.SL.TZ1.19: Which statement applies to meiosis and mitosis? A. Meiosis occurs in a greater number of...
-
20N.2.SL.TZ0.6b:
Outline what occurs in cells in the first division of meiosis.
-
20N.2.SL.TZ0.b:
Outline what occurs in cells in the first division of meiosis.
-
20N.1A.SL.TZ0.13:
Testing the chromosomes of a girl with Turner syndrome produced the following karyogram.
[Source: Turner’s syndrome karyotype 45,XO. This female lacks the second X chromosome present in the
normal karyotype. Symptoms include short stature, neck webbing, elbow deformity, widely spaced nipples with shield chest, primary amenorrhea, sexual infantilism and sterility. The ovaries are reduced to fibrous streaks. Also known as XO syndrome or ovarian short-stature syndrome. Credit: Wessex Reg. Genetics Centre. Attribution 4.0 International (CC BY 4.0).]The condition can result from non-disjunction occurring in anaphase I of meiosis in an egg cell. Two cells result from the first division, one of which would lead to Turner syndrome. Which chromosomes will be in the other cell (polar body) at the end of meiosis I?
A. 44 autosomes and X
B. 44 autosomes and XX
C. 22 autosomes and X
D. 22 autosomes and XX
-
21M.1B.SL.TZ1.1e:
By referring to both graphs, evaluate the hypothesis that vinblastine targets cells in mitosis and prevents them from completing the process.
-
21M.2.HL.TZ1.1g:
Discuss one advantage and one disadvantage of using plant tissue to investigate drugs intended to treat cancer in humans.
Advantage:
Disadvantage:
-
21M.1B.SL.TZ1.e:
By referring to both graphs, evaluate the hypothesis that vinblastine targets cells in mitosis and prevents them from completing the process.
-
21M.2.HL.TZ1.g:
Discuss one advantage and one disadvantage of using plant tissue to investigate drugs intended to treat cancer in humans.
Advantage:
Disadvantage:
-
21M.2.HL.TZ2.2a:
State processes occurring during interphase.
-
21M.2.HL.TZ2.2b.i:
Using the letter C, label the stage on the diagram where chromosome supercoiling occurs.
-
21M.2.HL.TZ2.2b.ii:
Using the letter M, label the stage on the diagram where sister chromatids migrate to opposite poles.
-
21M.2.HL.TZ2.2c:
Distinguish between the outcomes of a cell dividing either by mitosis or meiosis.
-
21M.2.HL.TZ2.2d:
The mitotic index is an important prognostic tool for predicting the response of cancer cells to chemotherapy. Outline how the mitotic index is calculated.
-
21M.2.HL.TZ2.a:
State processes occurring during interphase.
-
21M.2.HL.TZ2.b.i:
Using the letter C, label the stage on the diagram where chromosome supercoiling occurs.
-
21M.2.HL.TZ2.b.ii:
Using the letter M, label the stage on the diagram where sister chromatids migrate to opposite poles.
-
21M.2.HL.TZ2.c:
Distinguish between the outcomes of a cell dividing either by mitosis or meiosis.
-
21M.2.HL.TZ2.d:
The mitotic index is an important prognostic tool for predicting the response of cancer cells to chemotherapy. Outline how the mitotic index is calculated.
-
19M.1A.SL.TZ1.14:
At which stage of meiosis are bivalents formed?
A. Interphase
B. Prophase I
C. Prophase II
D. Metaphase II
- 20N.1A.SL.TZ0.5: How many chromosomes are there in a cell during anaphase of mitosis, if the diploid number of the...
- 22M.1A.SL.TZ1.15: What is produced by meiosis in a cell of a male animal? A. Four gametes, each with the same...
-
22M.1A.HL.TZ1.4:
In which stage of the cell cycle are chromosomes duplicated?
[Source: M1llx, 2019. Cell cycle simple pl. [online] Available at: https://commons.wikimedia.org/wiki/File:Cell_cycle_simple_pl.png This file is licensed
under the Creative Commons Attribution-Share Alike 4.0 International license.
https://creativecommons.org/licenses/by-sa/4.0/deed.en [Accessed 1 August 2019].]A. G1 phase
B. G2 phase
C. S phase
D. Mitosis
- 19M.2.SL.TZ1.6b: Identify the chromosome that is affected by a trisomy in this individual, naming the condition...
- 19M.2.SL.TZ1.b: Identify the chromosome that is affected by a trisomy in this individual, naming the condition...
-
19M.1A.SL.TZ2.3:
The image shows a micrograph of a cell.
[Source: © 2014, https://commons.wikimedia.org/wiki/File:Mitosis_(261_13)_Pressed;_root_meristem_of_onion_(cells_
in_prophase,_metaphase,_anaphase,_telophase).jpg by Doc. RNDr. Josef Reischig, CSc.]What explains the appearance of the cell in the micrograph?
A. The cell is dying.
B. The DNA is replicating.
C. The cell is in metaphase.
D. The cell is in telophase.
-
19M.2.SL.TZ2.2a:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
-
19M.2.SL.TZ2.a:
Identify the stage of mitosis labelled X in the image, giving a reason.
[Source: Copyright 2002, The Trustees of Indiana University]
-
19M.1A.SL.TZ2.17:
The diagram shows a stage in cell division.
[Source: © International Baccalaureate Organization 2019]
What is the stage shown?
A. Anaphase I of mitosis
B. Anaphase II of mitosis
C. Anaphase I of meiosis
D. Anaphase II of meiosis
- 20N.1A.HL.TZ0.4: What would show that a person has developed metastatic cancer? A. Alveolus cells forming a...
- 22N.1A.SL.TZ0.14: Which event occurs in the first division of meiosis? A. Synthesis of DNA B. Pulling apart of...
- 22N.2.HL.TZ0.6a: Outline the processes occurring during interphase in the cell cycle.
- 22N.2.HL.TZ0.a: Outline the processes occurring during interphase in the cell cycle.
- 21M.1A.HL.TZ1.7: A tissue sample was examined under the microscope in order to determine a mitotic index. The...
- SPM.1A.HL.TZ0.20: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- SPM.1A.SL.TZ0.14: What is a function of histones? A. Supercoiling of DNA during binary fission in prokaryotes B. ...
- 23M.2.SL.TZ1.7a: Outline the changes to chromosomes that occur during prophase in the first division of meiosis.
- 23M.2.SL.TZ1.a: Outline the changes to chromosomes that occur during prophase in the first division of meiosis.
- 23M.2.SL.TZ1.6a: Outline the sequence of events that occurs during mitosis.
- 23M.2.SL.TZ1.a: Outline the sequence of events that occurs during mitosis.
-
23M.2.HL.TZ2.6a:
Explain how changes to the cell cycle can result in tumour formation.
-
23M.2.HL.TZ2.a:
Explain how changes to the cell cycle can result in tumour formation.
- 23M.2.HL.TZ2.3a: State one cause of lung cancer.
-
23M.2.HL.TZ2.3b:
Suggest one difference between tissue taken from a lung cancer tumour and normal lung tissue that might be seen in micrographs.
- 23M.2.HL.TZ2.3c: The lung tumour in the light micrograph was slow-growing. Predict with a reason what would have...
- 23M.2.HL.TZ2.a: State one cause of lung cancer.
-
23M.2.HL.TZ2.b:
Suggest one difference between tissue taken from a lung cancer tumour and normal lung tissue that might be seen in micrographs.
- 23M.2.HL.TZ2.c: The lung tumour in the light micrograph was slow-growing. Predict with a reason what would have...
-
23M.1A.SL.TZ1.11:
The micrograph shows a cross section of a lily (Lilium longiflorum) anther.
[Source: Sinhyu / iStock.]
What can be found in X?
A. Haploid nuclei produced by meiosis
B. Diploid nuclei produced by fertilization
C. Haploid nuclei produced by mitosis
D. Diploid nuclei produced by pollination
- 23M.1A.SL.TZ1.36: What happens in the first division of meiosis? A. Formation of chiasmata where two sister...
- 23M.1A.SL.TZ1.15: Non-disjunction of chromosome 21 causes trisomy. What can be said about the incidence...
- 23M.1A.SL.TZ1.16: For what reason do gametes contain only one allele of each gene? A. To prevent inbreeding in a...
-
23M.1A.SL.TZ2.5:
The image shows a cell from the root tip of an onion (Allium cepa) (2n = 16) during late prophase of mitosis.
[Source: Davidson, M.W. and Molecular Expressions at Florida State University, n.d. Late prophase. [image online]
Available at: https://micro.magnet.fsu.edu/micro/gallery/mitosis/mitosis.html [Accessed 5 October 2021].]How many chromatids are present in the cell?
A. 8B. 16
C. 32
D. 64
-
23M.1A.SL.TZ2.5:
The image shows a cell from the root tip of an onion (Allium cepa) (2n = 16) during late prophase of mitosis.
[Source: Davidson, M.W. and Molecular Expressions at Florida State University, n.d. Late prophase. [image online]
Available at: https://micro.magnet.fsu.edu/micro/gallery/mitosis/mitosis.html [Accessed 5 October 2021].]How many chromatids are present in the cell?
A. 8B. 16
C. 32
D. 64
- 23M.1A.SL.TZ2.12: At what stage of meiosis do chromosome pairing and crossing over occur? A. Interphase B. ...
- 23M.1A.SL.TZ2.31: What is a result of crossing over in meiosis? A. Gene linkage B. Non-disjunction C. Haploid...
D2.2 Gene expression [HL only]
-
21M.2.HL.TZ2.7c:
Insulin is produced in β cells of the pancreas and not in other cells of the human body. Explain how differentiation of cells and regulation of gene expression allow proteins such as insulin to be produced in only certain types of body cell.
-
21N.1A.HL.TZ1.27:
What is the difference between the DNA of adult identical (monozygotic) twins?
A. Order of genes
B. Sequence of nucleotides
C. Methylation pattern
D. Ratio of complementary base pairs
- 19M.2.HL.TZ2.2b.i: Outline the difference in methylation pattern between tumorous and normal tissue samples.
- 19M.2.HL.TZ2.2b.ii: Suggest a way methylation may affect tumour cell genes.
- 19N.1A.HL.TZ0.6: What is a proteome? A. The genes that code for all the proteins in the ribosome B. The group of...
-
22M.1A.HL.TZ2.6:
The micrograph of a section through a plant stem shows at least ten different types of cells.
[Source: Joan Carles Juarez / Shutterstock.com.]
What explains the differences between these cells?
A. Only one gene is expressed in each cell type.
B. Different genes are expressed in each cell type.
C. Only useful genes remain in the DNA of each cell type.
D. Changes in the DNA sequence take place when these cells develop.
-
19M.1A.HL.TZ2.8:
Which statement correctly describes genome and proteome?
A. Only the genome but not the proteome can be analysed using gel electrophoresis.
B. The genome and the proteome are the same in all tissues in an organism.
C. In cells of different tissues, the genome is the same while the proteome varies.
D. Only mutations in the proteome but not in the genome cause any variability.
- 20N.1A.HL.TZ0.26: The number of protein-coding genes in the human genome is estimated to be about 20 000, which is...
-
22N.2.HL.TZ0.4b:
Outline how nucleosomes affect the transcription of DNA.
-
22N.2.HL.TZ0.4e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
23M.1A.HL.TZ1.26:
DNA methylation profiles in zebrafish (Danio rerio) gametes were determined. The methylated areas were divided into three groups according to the amount of methylation: high, medium and low methylation.
[Source: Potok, M.E., Nix, D.A., Parnell, T.J. and Cairns, B.R., 2013.
Reprogramming the Maternal Zebrafish Genome afterFertilization to
Match the Paternal Methylation Pattern.
Cell, [e-journal] 153(4), pp. 759–772. http://dx.doi.org/10.1016/j.
cell.2013.04.030.]Methylation of DNA in sperm and egg is removed immediately after fertilization. What is the reason for this?
A. Methylation allows RNA polymerase to join the promoter.B. It is needed to form homologous pairs of chromosomes.
C. It allows expression of genes linked to early development.
D. Transcription of promoters only occurs in methylated genes.
- 23M.1A.HL.TZ2.8: What is the proteome of an individual? A. The amino acids unique to an individual making up the...
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
21M.2.HL.TZ2.7c:
Insulin is produced in β cells of the pancreas and not in other cells of the human body. Explain how differentiation of cells and regulation of gene expression allow proteins such as insulin to be produced in only certain types of body cell.
-
21M.2.HL.TZ2.c:
Insulin is produced in β cells of the pancreas and not in other cells of the human body. Explain how differentiation of cells and regulation of gene expression allow proteins such as insulin to be produced in only certain types of body cell.
-
21N.1A.HL.TZ1.27:
What is the difference between the DNA of adult identical (monozygotic) twins?
A. Order of genes
B. Sequence of nucleotides
C. Methylation pattern
D. Ratio of complementary base pairs
- 19M.2.HL.TZ2.2b.i: Outline the difference in methylation pattern between tumorous and normal tissue samples.
- 19M.2.HL.TZ2.2b.ii: Suggest a way methylation may affect tumour cell genes.
- 19M.2.HL.TZ2.b.i: Outline the difference in methylation pattern between tumorous and normal tissue samples.
- 19M.2.HL.TZ2.b.ii: Suggest a way methylation may affect tumour cell genes.
- 19N.1A.HL.TZ0.6: What is a proteome? A. The genes that code for all the proteins in the ribosome B. The group of...
-
22M.1A.HL.TZ2.6:
The micrograph of a section through a plant stem shows at least ten different types of cells.
[Source: Joan Carles Juarez / Shutterstock.com.]
What explains the differences between these cells?
A. Only one gene is expressed in each cell type.
B. Different genes are expressed in each cell type.
C. Only useful genes remain in the DNA of each cell type.
D. Changes in the DNA sequence take place when these cells develop.
-
19M.1A.HL.TZ2.8:
Which statement correctly describes genome and proteome?
A. Only the genome but not the proteome can be analysed using gel electrophoresis.
B. The genome and the proteome are the same in all tissues in an organism.
C. In cells of different tissues, the genome is the same while the proteome varies.
D. Only mutations in the proteome but not in the genome cause any variability.
- 20N.1A.HL.TZ0.26: The number of protein-coding genes in the human genome is estimated to be about 20 000, which is...
-
22N.2.HL.TZ0.4b:
Outline how nucleosomes affect the transcription of DNA.
-
22N.2.HL.TZ0.4e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
22N.2.HL.TZ0.b:
Outline how nucleosomes affect the transcription of DNA.
-
22N.2.HL.TZ0.e:
State one reason that identical twins may show different methylation patterns as they grow older.
-
SPM.1A.HL.TZ0.19:
The graph shows the effect of methylation on the expression of MT1E, a gene involved in the control of prostate cancer development. Patients with a reduced expression of this gene are more likely to develop prostate cancer.
[Source: © 2017 Demidenko et al. 2017. Decreased expression of MT1E is a potential biomarker of
prostate cancer progression. Oncotarget, 8, pp. 61709–61718. Distributed under the terms of the Creative Commons Attribution License 3.0 (CC BY 3.0). Image redrawn and reannotated.]
What are effects of MT1E methylation?
A. It reduces transcription of MT1E, increasing the risk of prostate cancer.B. It increases translation of MT1E, reducing the risk of prostate cancer.
C. It reduces replication of MT1E, reducing the risk of prostate cancer.
D. It increases the chances of mutation in proto-oncogenes, increasing the risk of prostate cancer.
-
23M.1A.HL.TZ1.26:
DNA methylation profiles in zebrafish (Danio rerio) gametes were determined. The methylated areas were divided into three groups according to the amount of methylation: high, medium and low methylation.
[Source: Potok, M.E., Nix, D.A., Parnell, T.J. and Cairns, B.R., 2013.
Reprogramming the Maternal Zebrafish Genome afterFertilization to
Match the Paternal Methylation Pattern.
Cell, [e-journal] 153(4), pp. 759–772. http://dx.doi.org/10.1016/j.
cell.2013.04.030.]Methylation of DNA in sperm and egg is removed immediately after fertilization. What is the reason for this?
A. Methylation allows RNA polymerase to join the promoter.B. It is needed to form homologous pairs of chromosomes.
C. It allows expression of genes linked to early development.
D. Transcription of promoters only occurs in methylated genes.
- 23M.1A.HL.TZ2.8: What is the proteome of an individual? A. The amino acids unique to an individual making up the...
D2.3 Water potential
-
21N.2.SL.TZ0.3a:
The image shows human red blood cells.
[Source: someoneice/123rf.com.]
Outline what will happen to human red blood cells if transferred to distilled water.
-
22M.1A.SL.TZ2.2:
Red blood cells from a small mammal were immersed in NaCl (sodium chloride) solutions of different concentrations for 2 hours. The graph shows the percentage of hemolysed (ruptured) red blood cells at each concentration.
[Source: Zaidan, T. , de Matos, W. , Machado, É. , Junqueira, T. , Vicentini, S. , Presta, G. and Santos-Filho, S. (2010)
Cellular effects of an aqueous solution of Losartan® on the survival of Escherichia coli AB1157 in the presence
and absence of SnCl2, and on the physiological property (osmotic fragility) of the erytrocyte. Advances
in Bioscience and Biotechnology, 1, 300–304. doi: 10.4236/abb.2010.14039. Available at https://www.scirp.org/pdf/ABB20100400005_18844979.pdf Licensed under a Creative
Commons Attribution 4.0 International License (https://creativecommons.org/licenses/by/4.0/).]What can be deduced from the graph?
A. At Y, the net movement of Na ions between red blood cells and the NaCl solutions is zero.
B. At X, Na and Cl ions disrupt the structure of cell membranes.
C. At Y, the hypertonic NaCl solutions diffuse into the red blood cells.
D. At X, water has moved by osmosis into the red blood cells.
-
21N.2.SL.TZ0.5b:
Describe transport across cell membranes by osmosis.
-
19N.1B.SL.TZ0.1a:
Using the graph, estimate isotonic sucrose solutions for potato tissue and carrot tissue.
Potato:
Carrot:
- 19N.1B.SL.TZ0.1b: Suggest a reason for the difference in the isotonic points for the potato and the carrot tissues.
- 19N.1B.SL.TZ0.1c: From the evidence provided by the graph, evaluate the reliability of these data.
- 19N.1B.SL.TZ0.1d: Explain one reason for calculating the percentage change in mass.
-
19M.1A.SL.TZ1.4:
Which process(es) occur(s) by osmosis?
I. Uptake of water by cells in the wall of the intestine
II. Loss of water from a plant cell in a hypertonic environment
III. Evaporation of water from sweat on the skin surface
A. I only
B. I and II only
C. II and III only
D. I, II and III
- 19N.1B.SL.TZ0.3a: Estimate the solute concentration of the zucchini cells.
- 19N.1B.SL.TZ0.3b: If a zucchini is allowed to dry in the open air, predict how the osmolarity of the zucchini cells...
- 19N.1B.SL.TZ0.3c: Explain one reason for calculating the percentage changes in mass.
- 19N.1B.SL.TZ0.3d: Predict what would happen to a red blood cell placed in distilled water.
-
22M.1A.SL.TZ2.3:
In an experiment on osmosis, red blood cells were immersed in a salt solution for two hours. The micrographs show the appearance of these cells before and after immersion in the salt solution.
[Source: Ed Uthman, Acanthocytes, from peripheral blood [image online] Available at:
https://en.wikipedia.org/wiki/Acanthocyte#/media/File:Acanthocytes,_Peripheral_Blood_(3884092551).jpg
This file is licensed under the Creative Commons Attribution 2.0 Generic (CC BY 2.0) https://creativecommons.org/licenses/by/2.0/ Source adapted.]What explains the observed changes?
A. The salt solution was hypertonic and entered the red blood cells.
B. The salt solution was hypotonic and disrupted the membranes of the red blood cells.
C. The salt solution was hypertonic and water moved into it from the red blood cells.
D. The salt solution was hypotonic and mineral salts were lost from the red blood cells.
- 21M.1A.SL.TZ1.4: A human organ is being prepared for transplant. In what type of solution must it be bathed? A. A...
- 21M.1A.SL.TZ1.2: Which process explains the observations shown in the images? A. Active transport B....
- 22N.1A.SL.TZ0.3: What would happen if the unicellular organism was placed in a solution slightly less concentrated...
-
23M.1A.SL.TZ1.3:
Onion (Allium cepa) epidermis was placed in pure water and observed with a light microscope using high magnification.
What would happen to these cells if they were transferred to a hypertonic solution?
A. Cells would gain mass.B. Cells would take in water by osmosis and swell.
C. Cells would burst open, releasing their content.
D. Cell membranes would detach from walls at some points.
-
23M.1A.SL.TZ1.4:
Onion (Allium cepa) epidermis was placed in pure water and observed with a light microscope using high magnification.
What would happen to these cells if they were transferred to a hypertonic solution?
A. Cells would gain mass.B. Cells would take in water by osmosis and swell.
C. Cells would burst open, releasing their content.
D. Cell membranes would detach from walls at some points.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
-
21N.2.SL.TZ0.3a:
The image shows human red blood cells.
[Source: someoneice/123rf.com.]
Outline what will happen to human red blood cells if transferred to distilled water.
-
21N.2.SL.TZ0.a:
The image shows human red blood cells.
[Source: someoneice/123rf.com.]
Outline what will happen to human red blood cells if transferred to distilled water.
-
22M.1A.SL.TZ2.2:
Red blood cells from a small mammal were immersed in NaCl (sodium chloride) solutions of different concentrations for 2 hours. The graph shows the percentage of hemolysed (ruptured) red blood cells at each concentration.
[Source: Zaidan, T. , de Matos, W. , Machado, É. , Junqueira, T. , Vicentini, S. , Presta, G. and Santos-Filho, S. (2010)
Cellular effects of an aqueous solution of Losartan® on the survival of Escherichia coli AB1157 in the presence
and absence of SnCl2, and on the physiological property (osmotic fragility) of the erytrocyte. Advances
in Bioscience and Biotechnology, 1, 300–304. doi: 10.4236/abb.2010.14039. Available at https://www.scirp.org/pdf/ABB20100400005_18844979.pdf Licensed under a Creative
Commons Attribution 4.0 International License (https://creativecommons.org/licenses/by/4.0/).]What can be deduced from the graph?
A. At Y, the net movement of Na ions between red blood cells and the NaCl solutions is zero.
B. At X, Na and Cl ions disrupt the structure of cell membranes.
C. At Y, the hypertonic NaCl solutions diffuse into the red blood cells.
D. At X, water has moved by osmosis into the red blood cells.
-
21N.2.SL.TZ0.5b:
Describe transport across cell membranes by osmosis.
-
21N.2.SL.TZ0.b:
Describe transport across cell membranes by osmosis.
-
19N.1B.SL.TZ0.a:
Using the graph, estimate isotonic sucrose solutions for potato tissue and carrot tissue.
Potato:
Carrot:
- 19N.1B.SL.TZ0.b: Suggest a reason for the difference in the isotonic points for the potato and the carrot tissues.
- 19N.1B.SL.TZ0.c: From the evidence provided by the graph, evaluate the reliability of these data.
- 19N.1B.SL.TZ0.d: Explain one reason for calculating the percentage change in mass.
-
19M.1A.SL.TZ1.4:
Which process(es) occur(s) by osmosis?
I. Uptake of water by cells in the wall of the intestine
II. Loss of water from a plant cell in a hypertonic environment
III. Evaporation of water from sweat on the skin surface
A. I only
B. I and II only
C. II and III only
D. I, II and III
- 19N.1B.SL.TZ0.a: Estimate the solute concentration of the zucchini cells.
- 19N.1B.SL.TZ0.b: If a zucchini is allowed to dry in the open air, predict how the osmolarity of the zucchini cells...
- 19N.1B.SL.TZ0.c: Explain one reason for calculating the percentage changes in mass.
- 19N.1B.SL.TZ0.d: Predict what would happen to a red blood cell placed in distilled water.
-
22M.1A.SL.TZ2.3:
In an experiment on osmosis, red blood cells were immersed in a salt solution for two hours. The micrographs show the appearance of these cells before and after immersion in the salt solution.
[Source: Ed Uthman, Acanthocytes, from peripheral blood [image online] Available at:
https://en.wikipedia.org/wiki/Acanthocyte#/media/File:Acanthocytes,_Peripheral_Blood_(3884092551).jpg
This file is licensed under the Creative Commons Attribution 2.0 Generic (CC BY 2.0) https://creativecommons.org/licenses/by/2.0/ Source adapted.]What explains the observed changes?
A. The salt solution was hypertonic and entered the red blood cells.
B. The salt solution was hypotonic and disrupted the membranes of the red blood cells.
C. The salt solution was hypertonic and water moved into it from the red blood cells.
D. The salt solution was hypotonic and mineral salts were lost from the red blood cells.
- 21M.1A.SL.TZ1.4: A human organ is being prepared for transplant. In what type of solution must it be bathed? A. A...
- 21M.1A.SL.TZ1.2: Which process explains the observations shown in the images? A. Active transport B....
- 22N.1A.SL.TZ0.3: What would happen if the unicellular organism was placed in a solution slightly less concentrated...
-
23M.1A.SL.TZ1.3:
Onion (Allium cepa) epidermis was placed in pure water and observed with a light microscope using high magnification.
What would happen to these cells if they were transferred to a hypertonic solution?
A. Cells would gain mass.B. Cells would take in water by osmosis and swell.
C. Cells would burst open, releasing their content.
D. Cell membranes would detach from walls at some points.
-
23M.1A.SL.TZ1.4:
Onion (Allium cepa) epidermis was placed in pure water and observed with a light microscope using high magnification.
What would happen to these cells if they were transferred to a hypertonic solution?
A. Cells would gain mass.B. Cells would take in water by osmosis and swell.
C. Cells would burst open, releasing their content.
D. Cell membranes would detach from walls at some points.
- EXEX.1B.HL.TZ0.5aiii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
- EXEX.1B.HL.TZ0.iii: Comment on the significance of the error bars for muscle stiffness shown in the graph.
D3.1 Reproduction
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 21M.1A.SL.TZ2.30: What is a similarity between the testes of males and the ovaries of females in humans? A. They...
-
21M.2.HL.TZ2.5b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
-
21N.2.HL.TZ0.2d:
Explain the mechanism that prevents polyspermy during fertilization.
- 20N.1A.SL.TZ0.30: A female is overweight, feels cold and tired, and often fails to ovulate during the menstrual...
-
21M.1A.SL.TZ1.28:
The graph shows the blood levels of hormones associated with the menstrual cycle.
[Source: By OpenStax College - Anatomy & Physiology, Connexions Web site. http://cnx.org/content/col11496/1.6/, Jun 19, 2013., CC BY 3.0 (https://creativecommons.org/licenses/by/3.0/), https://commons.wikimedia.org/w/index.php?curid=30148641.]
Which line on the graph represents progesterone?
A. Line A
B. Line B
C. Line C
D. Line D
- 19M.2.SL.TZ2.4c: Successful sexual reproduction in flowering plants depends on several essential processes....
- 19M.1A.SL.TZ2.21: If seeds of an unknown species of plant are discovered, what assumption can be made about the...
- 22M.1A.SL.TZ2.29: What is an example of negative feedback in the menstrual cycle? A. High levels of estrogen...
-
19M.1A.SL.TZ2.31:
The diagram shows the human male reproductive system.
[Source: logika600/Shutterstock]
Which numbers indicate a gland providing fluid for sperm and a tube that transports sperm only?
-
19M.1A.SL.TZ1.30:
The diagram shows the human female reproductive system.
[Source: © International Baccalaureate Organization 2019]
What is produced by structure X?
A. FSH
B. X chromosomes
C. Fertilized eggs
D. Estrogen and progesterone
-
19N.2.SL.TZ0.8a:
Draw a half-view of an animal-pollinated flower.
-
21M.2.HL.TZ1.4c:
State one use of monoclonal antibodies.
-
21M.1A.HL.TZ1.39:
The pregnancy test for humans is based on detection of the hormone HCG. What is the reason for detection of this hormone indicating pregnancy?
A. HCG is involved in milk production.
B. HCG production is blocked by negative feedback during menstruation.
C. HCG is produced by an embryo.
D. HCG is released during the acrosome reaction.
- 19M.2.SL.TZ2.1b.i: Identify the structure labelled X.
- 19M.1B.SL.TZ2.1c: After fertilization, seeds of T. grandiflora form in a small pod. If you were provided with Petri...
-
21M.2.SL.TZ1.6a:
Describe the genetic and hormonal control of male sexual characteristics in a human.
- 19M.2.SL.TZ2.3c: Hormones are distributed throughout the body by the blood. Outline the roles of two reproductive...
-
21M.1A.HL.TZ2.40:
What function is maintained as a result of the release of HCG?
A. Production of milk by the mammary glands
B. Release of oxytocin by the posterior pituitary gland
C. Production of FSH by the anterior pituitary gland
D. Production of progesterone by the ovary
-
21N.1A.SL.TZ0.30:
What is a function of luteinizing hormone (LH) in the female menstrual cycle?
A. To promote secondary sexual characteristics
B. To inhibit progesterone secretion
C. To stimulate the follicle to release estrogen
D. To trigger ovulation
-
19M.1A.SL.TZ1.32:
The image shows a cross-section of a flower.
[Source: © International Baccalaureate Organization 2019]
Where does production of haploid gametes occur?
A. I and II only
B. III and IV only
C. I and III only
D. II and IV only
-
19M.1A.SL.TZ2.30:
The diagram shows the human female reproductive system
[Source: © International Baccalaureate Organization 2019]
Which labels indicate where fertilization occurs and where luteinizing hormone (LH) acts?
- 19N.1A.SL.TZ0.34: A pollen tube grows down the style to an egg inside the ovary of a flower. What is the next...
- 22N.1A.HL.TZ0.39: Which step occurs in both spermatogenesis and oogenesis? A. First division of meiosis is stopped...
- 22N.1A.HL.TZ0.40: What is the role of HCG in pregnancy? A. It is secreted by the embryo to stimulate progesterone...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
-
23M.2.HL.TZ1.6c:
Describe the hormone feedback mechanisms that help to prepare a woman’s body for pregnancy, sustain the pregnancy and then give birth.
-
23M.2.SL.TZ2.3a:
State the name and function of structures I and II.
Structure I name and function: ..............................................................................................................
..........................................................................................................................................................
Structure II name and function: .............................................................................................................
..........................................................................................................................................................
-
23M.2.SL.TZ2.3b:
Structure III is the ovary. Outline the processes that occur in the ovary.
- 23M.2.SL.TZ2.3c: Structure IV contains a gland that secretes a sugary liquid. Suggest a benefit to the plant of...
-
23M.2.HL.TZ2.4b:
Pangolins are unique among mammals in having evolved scales, which are a recognition feature of reptiles. Explain which features you expect pangolins to have, which would show that they are mammals, not reptiles.
- 23M.2.SL.TZ2.2a: State how many chromosomes there would be in male or female gametes of L. purpureus.
- 23M.1A.SL.TZ1.32: What is always needed for seed germination? A. Light B. Oxygen C. Carbon dioxide D. Fertilizer
- 23M.1A.HL.TZ1.37: What is used in a pregnancy test kit? A. Monoclonal antibodies against hybridoma cells B. ...
- 23M.1A.HL.TZ1.40: What happens in the acrosome reaction? A. Enzymes digest the zona pellucida around an ovum,...
- 23M.1A.HL.TZ2.39: At what stage of spermatogenesis does the first division of meiosis occur? A. Spermatogonium to...
- 23M.1A.HL.TZ2.40: Which statement applies to the placenta? A. Carbon dioxide diffuses from fetus to mother across...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 22M.1A.HL.TZ1.40: What is the role of HCG in early pregnancy? A. It prevents the degeneration of the corpus luteum...
- 22M.1A.HL.TZ1.37: Which mechanism prevents polyspermy? A. Polar body formation B. The acrosome reaction C....
- 19N.1A.SL.TZ0.30: On the graph, which curve represents the change in FSH levels during the menstrual cycle?
- 21M.1A.SL.TZ2.30: What is a similarity between the testes of males and the ovaries of females in humans? A. They...
-
21M.2.HL.TZ2.5b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
-
21M.2.HL.TZ2.b:
Outline how sperm are produced from diploid cells in the testis and how this production can be sustained over many decades of adult life.
-
21N.2.HL.TZ0.2d:
Explain the mechanism that prevents polyspermy during fertilization.
-
21N.2.HL.TZ0.d:
Explain the mechanism that prevents polyspermy during fertilization.
- 20N.1A.SL.TZ0.30: A female is overweight, feels cold and tired, and often fails to ovulate during the menstrual...
-
21M.1A.SL.TZ1.28:
The graph shows the blood levels of hormones associated with the menstrual cycle.
[Source: By OpenStax College - Anatomy & Physiology, Connexions Web site. http://cnx.org/content/col11496/1.6/, Jun 19, 2013., CC BY 3.0 (https://creativecommons.org/licenses/by/3.0/), https://commons.wikimedia.org/w/index.php?curid=30148641.]
Which line on the graph represents progesterone?
A. Line A
B. Line B
C. Line C
D. Line D
- 19M.2.SL.TZ2.4c: Successful sexual reproduction in flowering plants depends on several essential processes....
- 19M.2.SL.TZ2.c: Successful sexual reproduction in flowering plants depends on several essential processes....
- 19M.1A.SL.TZ2.21: If seeds of an unknown species of plant are discovered, what assumption can be made about the...
- 22M.1A.SL.TZ2.29: What is an example of negative feedback in the menstrual cycle? A. High levels of estrogen...
-
19M.1A.SL.TZ2.31:
The diagram shows the human male reproductive system.
[Source: logika600/Shutterstock]
Which numbers indicate a gland providing fluid for sperm and a tube that transports sperm only?
-
19M.1A.SL.TZ1.30:
The diagram shows the human female reproductive system.
[Source: © International Baccalaureate Organization 2019]
What is produced by structure X?
A. FSH
B. X chromosomes
C. Fertilized eggs
D. Estrogen and progesterone
-
19N.2.SL.TZ0.a:
Draw a half-view of an animal-pollinated flower.
-
21M.2.HL.TZ1.4c:
State one use of monoclonal antibodies.
-
21M.2.HL.TZ1.c:
State one use of monoclonal antibodies.
-
21M.1A.HL.TZ1.39:
The pregnancy test for humans is based on detection of the hormone HCG. What is the reason for detection of this hormone indicating pregnancy?
A. HCG is involved in milk production.
B. HCG production is blocked by negative feedback during menstruation.
C. HCG is produced by an embryo.
D. HCG is released during the acrosome reaction.
- 19M.2.SL.TZ2.b.i: Identify the structure labelled X.
- 19M.1B.SL.TZ2.c: After fertilization, seeds of T. grandiflora form in a small pod. If you were provided with Petri...
-
21M.2.SL.TZ1.6a:
Describe the genetic and hormonal control of male sexual characteristics in a human.
-
21M.2.SL.TZ1.a:
Describe the genetic and hormonal control of male sexual characteristics in a human.
- 19M.2.SL.TZ2.3c: Hormones are distributed throughout the body by the blood. Outline the roles of two reproductive...
- 19M.2.SL.TZ2.c: Hormones are distributed throughout the body by the blood. Outline the roles of two reproductive...
-
21M.1A.HL.TZ2.40:
What function is maintained as a result of the release of HCG?
A. Production of milk by the mammary glands
B. Release of oxytocin by the posterior pituitary gland
C. Production of FSH by the anterior pituitary gland
D. Production of progesterone by the ovary
-
21N.1A.SL.TZ0.30:
What is a function of luteinizing hormone (LH) in the female menstrual cycle?
A. To promote secondary sexual characteristics
B. To inhibit progesterone secretion
C. To stimulate the follicle to release estrogen
D. To trigger ovulation
-
19M.1A.SL.TZ1.32:
The image shows a cross-section of a flower.
[Source: © International Baccalaureate Organization 2019]
Where does production of haploid gametes occur?
A. I and II only
B. III and IV only
C. I and III only
D. II and IV only
-
19M.1A.SL.TZ2.30:
The diagram shows the human female reproductive system
[Source: © International Baccalaureate Organization 2019]
Which labels indicate where fertilization occurs and where luteinizing hormone (LH) acts?
- 19N.1A.SL.TZ0.34: A pollen tube grows down the style to an egg inside the ovary of a flower. What is the next...
- 22N.1A.HL.TZ0.39: Which step occurs in both spermatogenesis and oogenesis? A. First division of meiosis is stopped...
- 22N.1A.HL.TZ0.40: What is the role of HCG in pregnancy? A. It is secreted by the embryo to stimulate progesterone...
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.22: The first day of the menstrual cycle is when menstruation begins. What occurs around day 15 of...
-
23M.2.HL.TZ1.6c:
Describe the hormone feedback mechanisms that help to prepare a woman’s body for pregnancy, sustain the pregnancy and then give birth.
-
23M.2.HL.TZ1.c:
Describe the hormone feedback mechanisms that help to prepare a woman’s body for pregnancy, sustain the pregnancy and then give birth.
-
23M.2.SL.TZ2.3a:
State the name and function of structures I and II.
Structure I name and function: ..............................................................................................................
..........................................................................................................................................................
Structure II name and function: .............................................................................................................
..........................................................................................................................................................
-
23M.2.SL.TZ2.3b:
Structure III is the ovary. Outline the processes that occur in the ovary.
- 23M.2.SL.TZ2.3c: Structure IV contains a gland that secretes a sugary liquid. Suggest a benefit to the plant of...
-
23M.2.SL.TZ2.a:
State the name and function of structures I and II.
Structure I name and function: ..............................................................................................................
..........................................................................................................................................................
Structure II name and function: .............................................................................................................
..........................................................................................................................................................
-
23M.2.SL.TZ2.b:
Structure III is the ovary. Outline the processes that occur in the ovary.
- 23M.2.SL.TZ2.c: Structure IV contains a gland that secretes a sugary liquid. Suggest a benefit to the plant of...
-
23M.2.HL.TZ2.4b:
Pangolins are unique among mammals in having evolved scales, which are a recognition feature of reptiles. Explain which features you expect pangolins to have, which would show that they are mammals, not reptiles.
-
23M.2.HL.TZ2.b:
Pangolins are unique among mammals in having evolved scales, which are a recognition feature of reptiles. Explain which features you expect pangolins to have, which would show that they are mammals, not reptiles.
- 23M.2.SL.TZ2.2a: State how many chromosomes there would be in male or female gametes of L. purpureus.
- 23M.2.SL.TZ2.a: State how many chromosomes there would be in male or female gametes of L. purpureus.
- 23M.1A.SL.TZ1.32: What is always needed for seed germination? A. Light B. Oxygen C. Carbon dioxide D. Fertilizer
- 23M.1A.HL.TZ1.37: What is used in a pregnancy test kit? A. Monoclonal antibodies against hybridoma cells B. ...
- 23M.1A.HL.TZ1.40: What happens in the acrosome reaction? A. Enzymes digest the zona pellucida around an ovum,...
- 23M.1A.HL.TZ2.39: At what stage of spermatogenesis does the first division of meiosis occur? A. Spermatogonium to...
- 23M.1A.HL.TZ2.40: Which statement applies to the placenta? A. Carbon dioxide diffuses from fetus to mother across...
D3.2 Inheritance
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 20N.1A.SL.TZ0.35: Andalusian fowl have varied colours and types of feathers. The allele for black feathers is...
- 21N.1A.SL.TZ0.15: In humans, male pattern baldness is caused by a recessive sex-linked gene found only on the X...
- 21M.1A.SL.TZ1.18: Which genotype would be normally found in a gamete? A. Rr B. RS C. rStt D. TUt
-
19M.1A.SL.TZ2.14:
The pedigree chart shows a family affected by cystic fibrosis.
[Source: © International Baccalaureate Organization 2019]
What is the genotype of the affected boy’s father?
A. AA only
B. Either AA or Aa
C. Aa only
D. aa only
-
21M.2.SL.TZ2.5a:
Autosomal genes are located in chromosomes that are not sex chromosomes. The inheritance of autosomal genes is affected by whether the genes are linked or unlinked. Explain the two types of inheritance, using the example of parents that are heterozygous for two genes A and B.
- 19N.2.HL.TZ0.2a: State the type of inheritance shown.
- 19N.2.HL.TZ0.2b: Identify the recombinants.
- 19N.2.HL.TZ0.2c: The chi-squared value was calculated as shown. Deduce, with reasons, whether the observed ratio...
- 22M.1A.SL.TZ1.14: Chromosome numbers vary between species. Which statement refers to humans? A. An egg cell has 22...
- 22M.1A.SL.TZ1.16: Huntington’s disease is an autosomal dominant genetic disease. What are the chances of two...
-
21N.2.SL.TZ0.2a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
- 21N.2.SL.TZ0.2a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
-
21N.2.HL.TZ0.2c:
Explain gene linkage and its effects on inheritance.
- 19N.2.SL.TZ0.6b: Outline how two parents could have a child with any of the four ABO blood groups.
-
19M.1A.SL.TZ1.16:
Which pedigree chart is consistent with the inheritance of red-green colour blindness?
[Source: © International Baccalaureate Organization 2019]
-
19M.1A.HL.TZ2.20:
William Bateson and Reginald Punnett used the sweet pea (Lathyrus odoratus) in genetics studies in the early 20th century. Pure-breeding plants that produced purple flowers and long pollen grains were crossed with pure-breeding plants that produced red flowers and round pollen grains. The resulting offspring all produced purple flowers and long pollen grains. Two of the F1 generation plants were crossed. The table shows the ratio of phenotypes in the F2 generation.
What is an explanation for these experimental results?
A. Purple flowers and long pollen grains are dominant and the alleles have assorted independently.
B. The genes for flower colour and pollen shape are linked and all plants producing long pollen grains are recombinants.
C. The genes for flower colour and pollen shape are linked and all plants producing red flowers are recombinants.
D. Plants producing purple flowers and round pollen grains arose through crossing over.
-
19N.1A.SL.TZ0.16:
A pair of alleles controls the secretion of antigens corresponding to blood group in saliva. Examine the pedigree chart.
[Source: © International Baccalaureate Organization 2019]
Based on this pedigree chart, which best describes the allele conferring antigen secretion in saliva?
A. Dominant
B. Recessive
C. Sex-linked
D. Co-dominant
- 21N.1A.SL.TZ1.12: Huntington’s disease can develop in middle age and leads to death of brain cells. It is carried...
-
22M.2.SL.TZ1.8c:
Explain the reasons for variation in human height.
- 19M.2.HL.TZ1.2d.i: A fly that is homozygous dominant for both body colour and wing size mates with a fly that is...
- 19M.2.HL.TZ1.2d.ii: The offspring, which were all heterozygous for grey body and normal wings, were crossed with...
- 19N.1A.SL.TZ0.15: A variety of Pelargonium has yellow leaves. When plants of this variety are crossed, the...
- 19N.2.SL.TZ0.7b: Outline how two parents could have a child with any of the four ABO blood groups.
-
21M.2.SL.TZ2.5c:
Congenital lactase deficiency is a type of lactose intolerance that occurs in infants. It is inherited in an autosomal recessive pattern. Calculate the chance of congenital lactose intolerance in a child whose parents are both carriers for the disorder, showing fully how you reached your answer.
- 22M.1A.SL.TZ2.17: A group of students used quadrat sampling to gather data on the presence of two plant species in...
-
22M.2.SL.TZ2.6b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
- 19M.1A.SL.TZ2.15: The children in a family have blood groups A, B and O. What are the genotypes of their...
-
19M.1A.SL.TZ1.15:
Creeper in chickens is a condition in which the chickens are born with very short legs. The creeper allele (C) is dominant over the normal allele (c). Embryos which are homozygous for the dominant allele fail to develop into viable chickens and die before they hatch. What phenotypic ratio would you expect in the live offspring of a cross between two creeper chickens?
A. All creeper
B. 1 creeper; 2 normal
C. 2 creeper; 1 normal
D. 3 creeper; 1 normal
-
19N.1A.HL.TZ0.12:
The pedigree chart shows the inheritance of hemophilia in some of the descendants of Queen Victoria. Which letter points to a family member certain to be heterozygous?
[Source: © International Baccalaureate Organization 2019]
-
21M.1A.HL.TZ1.36:
In fruit flies (Drosophila melanogaster), grey bodies (b+) are dominant to black bodies (b) and normal wings (vg+) are dominant to vestigial wings (vg). Homozygous vestigial winged, black bodied flies were crossed with individuals that were heterozygous for both traits. 2300 individuals were counted and the phenotypes observed were recorded as shown.
965 normal wings, grey bodies
944 vestigial wings, black bodies
206 vestigial wings, grey bodies
185 normal wings, black bodiesWhich statement is valid?
A. The predicted phenotypic ratio was 9:3:3: 1.
B. There is independent assortment of wings but not body colour.
C. The expected number of vestigial winged, grey bodied flies was 575.
D. The traits are on different chromosomes.
- 21N.1A.HL.TZ1.35: A dihybrid cross was carried out between two plants to determine whether the genes for seed shape...
- 20N.1A.SL.TZ0.13: In the pedigree chart, individuals affected by a genetic disease are shown as shaded symbols....
- 19M.2.SL.TZ2.7b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 21N.2.SL.TZ0.6c: Distinguish between continuous and discrete variation, using examples.
-
21M.2.SL.TZ1.7a:
Outline the inheritance of blood types in the ABO blood system in humans.
- 20N.2.SL.TZ0.5a: Identify the genotype of the male wire-haired dog.
- 20N.2.SL.TZ0.5b: Using a Punnett square, determine how a smooth-haired puppy could be produced in the offspring.
- 20N.1A.SL.TZ0.15: What are all the possible phenotypes of children born to a mother with blood group AB and a...
- 22M.1A.SL.TZ2.13: Which statement defines alleles? A. They are the different forms of a gene that have the same...
- 22M.1A.SL.TZ2.15: The pedigree chart shows the inheritance of hemochromatosis, a genetic disease which causes an...
-
19M.1A.SL.TZ1.13:
The system of sex determination in chimpanzees (Pan troglodytes) is the same as in other mammals. A chimpanzee has 48 chromosomes in the nuclei of its body cells.
What can be deduced from this information?
A. The sex of the chimpanzee
B. The number of genes in each chromosome
C. Whether non-disjunction has occurred
D. The number of autosomes in a diploid cell
- 19N.1A.SL.TZ0.10: Which statements are characteristics of alleles? I. Alleles differ significantly in number of...
- 20N.1A.SL.TZ0.14: Tall heterozygous pea plants were crossed and the resulting seeds grown. Out of 360 plants, 270...
- 21M.1A.SL.TZ2.15: A woman with blood type A has three children with a man who has blood type AB. The first child...
-
22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.1A.HL.TZ0.35: Black, short-haired guinea pigs, heterozygous for both characteristics, were crossed. They...
- 22N.1A.SL.TZ0.13: What is a difference between two alleles of a gene? A. Their positions on homologous...
-
22N.1A.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
- 23M.2.SL.TZ1.5a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.5b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.5c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
-
23M.2.SL.TZ1.5d:
Identify, using one recognition feature visible in the photo, the phylum in which D. plantarius is classified.
- 23M.2.SL.TZ1.5a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.5b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.5c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
- 23M.2.SL.TZ1.5d: The proportion of banded and unbanded individuals in a population of D. plantarius can change....
-
23M.2.SL.TZ1.6c:
Explain how the presence of a Y chromosome in the cells of a human embryo causes it to develop as a male.
- 23M.2.SL.TZ2.4cii: Sex is determined in the same way in pangolins as in humans. State how many autosomes there are...
-
23M.2.SL.TZ2.2b:
Using a Punnett grid, explain the results of this cross.
-
23M.2.SL.TZ2.2c:
Suggest a reason for the F2 generation not corresponding exactly to the expected ratio of purple-flowered and white-flowered plants.
-
23M.1A.SL.TZ1.10:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1A.SL.TZ1.34:
A total of 271 164 people were tested for blood groups in Mexico. The pie chart summarizes the ABO blood group distribution.
[Source: Canizalez-Román, A. et al., 2018. Blood Groups Distribution and Gene Diversity
of the ABO and Rh (D) Loci in the Mexican Population.
BioMed Research International, (Article ID 1925619).
http://dx.doi.org/10.1155/2018/1925619. Public domain.]What can be concluded from the ABO blood group distribution in Mexico?
A. Allele frequencies are not the same for all blood group alleles.
B. The majority of the Mexican population shows a co-dominant phenotype.
C. Most of the Mexican population can receive blood from all blood groups.
D. Only 2 % of the Mexican population have a heterozygous genotype for blood groups.
-
23M.1A.SL.TZ1.14:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1A.SL.TZ2.13:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
-
23M.1A.SL.TZ2.16:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
- 23M.1A.SL.TZ2.32: In the fruit fly Drosophila, the alleles for red eyes and brown bodies are dominant to the...
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 22M.2.SL.TZ1.4a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.4b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.2.SL.TZ1.a: State the probability that Edward had hemophilia.
-
22M.2.SL.TZ1.b:
Explain the reasons for none of the females in the pedigree chart having hemophilia.
- 22M.1A.HL.TZ1.36: An individual is heterozygous for two linked genes . To investigate the frequency of crossing...
- 20N.1A.SL.TZ0.35: Andalusian fowl have varied colours and types of feathers. The allele for black feathers is...
- 21N.1A.SL.TZ0.15: In humans, male pattern baldness is caused by a recessive sex-linked gene found only on the X...
- 21M.1A.SL.TZ1.18: Which genotype would be normally found in a gamete? A. Rr B. RS C. rStt D. TUt
-
19M.1A.SL.TZ2.14:
The pedigree chart shows a family affected by cystic fibrosis.
[Source: © International Baccalaureate Organization 2019]
What is the genotype of the affected boy’s father?
A. AA only
B. Either AA or Aa
C. Aa only
D. aa only
-
21M.2.SL.TZ2.5a:
Autosomal genes are located in chromosomes that are not sex chromosomes. The inheritance of autosomal genes is affected by whether the genes are linked or unlinked. Explain the two types of inheritance, using the example of parents that are heterozygous for two genes A and B.
-
21M.2.SL.TZ2.a:
Autosomal genes are located in chromosomes that are not sex chromosomes. The inheritance of autosomal genes is affected by whether the genes are linked or unlinked. Explain the two types of inheritance, using the example of parents that are heterozygous for two genes A and B.
- 19N.2.HL.TZ0.2a: State the type of inheritance shown.
- 19N.2.HL.TZ0.2b: Identify the recombinants.
- 19N.2.HL.TZ0.2c: The chi-squared value was calculated as shown. Deduce, with reasons, whether the observed ratio...
- 19N.2.HL.TZ0.a: State the type of inheritance shown.
- 19N.2.HL.TZ0.b: Identify the recombinants.
- 19N.2.HL.TZ0.c: The chi-squared value was calculated as shown. Deduce, with reasons, whether the observed ratio...
- 22M.1A.SL.TZ1.14: Chromosome numbers vary between species. Which statement refers to humans? A. An egg cell has 22...
- 22M.1A.SL.TZ1.16: Huntington’s disease is an autosomal dominant genetic disease. What are the chances of two...
-
21N.2.SL.TZ0.2a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
- 21N.2.SL.TZ0.2a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
-
21N.2.HL.TZ0.2c:
Explain gene linkage and its effects on inheritance.
-
21N.2.SL.TZ0.a.i:
Draw a Punnett square to show all the possible genotypes of Queen Victoria’s children.
- 21N.2.SL.TZ0.a.ii: Deduce the genotype of Queen Victoria’s daughter Alice.
-
21N.2.HL.TZ0.c:
Explain gene linkage and its effects on inheritance.
- 19N.2.SL.TZ0.6b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.2.SL.TZ0.b: Outline how two parents could have a child with any of the four ABO blood groups.
-
19M.1A.SL.TZ1.16:
Which pedigree chart is consistent with the inheritance of red-green colour blindness?
[Source: © International Baccalaureate Organization 2019]
-
19M.1A.HL.TZ2.20:
William Bateson and Reginald Punnett used the sweet pea (Lathyrus odoratus) in genetics studies in the early 20th century. Pure-breeding plants that produced purple flowers and long pollen grains were crossed with pure-breeding plants that produced red flowers and round pollen grains. The resulting offspring all produced purple flowers and long pollen grains. Two of the F1 generation plants were crossed. The table shows the ratio of phenotypes in the F2 generation.
What is an explanation for these experimental results?
A. Purple flowers and long pollen grains are dominant and the alleles have assorted independently.
B. The genes for flower colour and pollen shape are linked and all plants producing long pollen grains are recombinants.
C. The genes for flower colour and pollen shape are linked and all plants producing red flowers are recombinants.
D. Plants producing purple flowers and round pollen grains arose through crossing over.
-
19N.1A.SL.TZ0.16:
A pair of alleles controls the secretion of antigens corresponding to blood group in saliva. Examine the pedigree chart.
[Source: © International Baccalaureate Organization 2019]
Based on this pedigree chart, which best describes the allele conferring antigen secretion in saliva?
A. Dominant
B. Recessive
C. Sex-linked
D. Co-dominant
- 21N.1A.SL.TZ1.12: Huntington’s disease can develop in middle age and leads to death of brain cells. It is carried...
-
22M.2.SL.TZ1.8c:
Explain the reasons for variation in human height.
-
22M.2.SL.TZ1.c:
Explain the reasons for variation in human height.
- 19M.2.HL.TZ1.2d.i: A fly that is homozygous dominant for both body colour and wing size mates with a fly that is...
- 19M.2.HL.TZ1.2d.ii: The offspring, which were all heterozygous for grey body and normal wings, were crossed with...
- 19M.2.HL.TZ1.d.i: A fly that is homozygous dominant for both body colour and wing size mates with a fly that is...
- 19M.2.HL.TZ1.d.ii: The offspring, which were all heterozygous for grey body and normal wings, were crossed with...
- 19N.1A.SL.TZ0.15: A variety of Pelargonium has yellow leaves. When plants of this variety are crossed, the...
- 19N.2.SL.TZ0.7b: Outline how two parents could have a child with any of the four ABO blood groups.
- 19N.2.SL.TZ0.b: Outline how two parents could have a child with any of the four ABO blood groups.
-
21M.2.SL.TZ2.5c:
Congenital lactase deficiency is a type of lactose intolerance that occurs in infants. It is inherited in an autosomal recessive pattern. Calculate the chance of congenital lactose intolerance in a child whose parents are both carriers for the disorder, showing fully how you reached your answer.
-
21M.2.SL.TZ2.c:
Congenital lactase deficiency is a type of lactose intolerance that occurs in infants. It is inherited in an autosomal recessive pattern. Calculate the chance of congenital lactose intolerance in a child whose parents are both carriers for the disorder, showing fully how you reached your answer.
- 22M.1A.SL.TZ2.17: A group of students used quadrat sampling to gather data on the presence of two plant species in...
-
22M.2.SL.TZ2.6b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
-
22M.2.SL.TZ2.b:
A family has a history of hemophilia that is caused by a sex-linked recessive allele. A woman from this family is a carrier and marries a man who does not have the allele. Showing your working, determine the probability of their children having the disease.
- 19M.1A.SL.TZ2.15: The children in a family have blood groups A, B and O. What are the genotypes of their...
-
19M.1A.SL.TZ1.15:
Creeper in chickens is a condition in which the chickens are born with very short legs. The creeper allele (C) is dominant over the normal allele (c). Embryos which are homozygous for the dominant allele fail to develop into viable chickens and die before they hatch. What phenotypic ratio would you expect in the live offspring of a cross between two creeper chickens?
A. All creeper
B. 1 creeper; 2 normal
C. 2 creeper; 1 normal
D. 3 creeper; 1 normal
-
19N.1A.HL.TZ0.12:
The pedigree chart shows the inheritance of hemophilia in some of the descendants of Queen Victoria. Which letter points to a family member certain to be heterozygous?
[Source: © International Baccalaureate Organization 2019]
-
21M.1A.HL.TZ1.36:
In fruit flies (Drosophila melanogaster), grey bodies (b+) are dominant to black bodies (b) and normal wings (vg+) are dominant to vestigial wings (vg). Homozygous vestigial winged, black bodied flies were crossed with individuals that were heterozygous for both traits. 2300 individuals were counted and the phenotypes observed were recorded as shown.
965 normal wings, grey bodies
944 vestigial wings, black bodies
206 vestigial wings, grey bodies
185 normal wings, black bodiesWhich statement is valid?
A. The predicted phenotypic ratio was 9:3:3: 1.
B. There is independent assortment of wings but not body colour.
C. The expected number of vestigial winged, grey bodied flies was 575.
D. The traits are on different chromosomes.
- 21N.1A.HL.TZ1.35: A dihybrid cross was carried out between two plants to determine whether the genes for seed shape...
- 20N.1A.SL.TZ0.13: In the pedigree chart, individuals affected by a genetic disease are shown as shaded symbols....
- 19M.2.SL.TZ2.7b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 19M.2.SL.TZ2.b: Mendel found the same pattern of inheritance in all the crosses that he performed. Outline, with...
- 21N.2.SL.TZ0.6c: Distinguish between continuous and discrete variation, using examples.
- 21N.2.SL.TZ0.c: Distinguish between continuous and discrete variation, using examples.
-
21M.2.SL.TZ1.7a:
Outline the inheritance of blood types in the ABO blood system in humans.
-
21M.2.SL.TZ1.a:
Outline the inheritance of blood types in the ABO blood system in humans.
- 20N.2.SL.TZ0.5a: Identify the genotype of the male wire-haired dog.
- 20N.2.SL.TZ0.5b: Using a Punnett square, determine how a smooth-haired puppy could be produced in the offspring.
- 20N.2.SL.TZ0.a: Identify the genotype of the male wire-haired dog.
- 20N.2.SL.TZ0.b: Using a Punnett square, determine how a smooth-haired puppy could be produced in the offspring.
- 20N.1A.SL.TZ0.15: What are all the possible phenotypes of children born to a mother with blood group AB and a...
- 22M.1A.SL.TZ2.13: Which statement defines alleles? A. They are the different forms of a gene that have the same...
- 22M.1A.SL.TZ2.15: The pedigree chart shows the inheritance of hemochromatosis, a genetic disease which causes an...
-
19M.1A.SL.TZ1.13:
The system of sex determination in chimpanzees (Pan troglodytes) is the same as in other mammals. A chimpanzee has 48 chromosomes in the nuclei of its body cells.
What can be deduced from this information?
A. The sex of the chimpanzee
B. The number of genes in each chromosome
C. Whether non-disjunction has occurred
D. The number of autosomes in a diploid cell
- 19N.1A.SL.TZ0.10: Which statements are characteristics of alleles? I. Alleles differ significantly in number of...
- 20N.1A.SL.TZ0.14: Tall heterozygous pea plants were crossed and the resulting seeds grown. Out of 360 plants, 270...
- 21M.1A.SL.TZ2.15: A woman with blood type A has three children with a man who has blood type AB. The first child...
-
22N.2.SL.TZ0.4a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.4b:
Calculate the probability of male Y having an allele for the disorder.
- 22N.2.SL.TZ0.4c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
-
22N.2.SL.TZ0.a:
Draw the symbol for individual X on the diagram.
-
22N.2.SL.TZ0.b:
Calculate the probability of male Y having an allele for the disorder.
- 22N.2.SL.TZ0.c: Explain how the information in the box labelled B indicates that the gene is not sex-linked.
- 22N.1A.HL.TZ0.35: Black, short-haired guinea pigs, heterozygous for both characteristics, were crossed. They...
- 22N.1A.SL.TZ0.13: What is a difference between two alleles of a gene? A. Their positions on homologous...
-
22N.1A.SL.TZ0.15:
A couple have four children whose blood groups are A, B and AB. What is the likely combination of the parents’ genotypes?
A. IAi and IBi
B. IAi and IBIB
C. IAIB and ii
D. IAIA and IBIB
- SPM.1A.HL.TZ0.31: Female grasshoppers have XX sex chromosomes and males have XO, signifying a single X chromosome....
- SPM.2.HL.TZ0.7a: Identify the recombinant phenotypes amongst the offspring.
-
SPM.2.HL.TZ0.7b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
- SPM.2.HL.TZ0.a: Identify the recombinant phenotypes amongst the offspring.
-
SPM.2.HL.TZ0.b:
Explain whether these results fit the predicted Mendelian ratios for this cross.
-
SPM.2.SL.TZ0.7b:
Outline one example of a human disease caused by an autosomal recessive allele.
-
SPM.2.SL.TZ0.b:
Outline one example of a human disease caused by an autosomal recessive allele.
- 23M.2.SL.TZ1.5a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.5b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.5c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
-
23M.2.SL.TZ1.5d:
Identify, using one recognition feature visible in the photo, the phylum in which D. plantarius is classified.
- 23M.2.SL.TZ1.a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
-
23M.2.SL.TZ1.d:
Identify, using one recognition feature visible in the photo, the phylum in which D. plantarius is classified.
- 23M.2.SL.TZ1.5a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.5b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.5c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
- 23M.2.SL.TZ1.5d: The proportion of banded and unbanded individuals in a population of D. plantarius can change....
- 23M.2.SL.TZ1.a: Explain the conclusion that can be drawn from Cross 1.
-
23M.2.SL.TZ1.b:
Deduce reasons for the difference between the results of Cross 2 and Cross 3.
- 23M.2.SL.TZ1.c: There were 79 progeny in Cross 4. Predict the expected results by completing the table.
- 23M.2.SL.TZ1.d: The proportion of banded and unbanded individuals in a population of D. plantarius can change....
-
23M.2.SL.TZ1.6c:
Explain how the presence of a Y chromosome in the cells of a human embryo causes it to develop as a male.
-
23M.2.SL.TZ1.c:
Explain how the presence of a Y chromosome in the cells of a human embryo causes it to develop as a male.
- 23M.2.SL.TZ2.4cii: Sex is determined in the same way in pangolins as in humans. State how many autosomes there are...
- 23M.2.SL.TZ2.ii: Sex is determined in the same way in pangolins as in humans. State how many autosomes there are...
-
23M.2.SL.TZ2.2b:
Using a Punnett grid, explain the results of this cross.
-
23M.2.SL.TZ2.2c:
Suggest a reason for the F2 generation not corresponding exactly to the expected ratio of purple-flowered and white-flowered plants.
-
23M.2.SL.TZ2.b:
Using a Punnett grid, explain the results of this cross.
-
23M.2.SL.TZ2.c:
Suggest a reason for the F2 generation not corresponding exactly to the expected ratio of purple-flowered and white-flowered plants.
-
23M.1A.SL.TZ1.10:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1A.SL.TZ1.34:
A total of 271 164 people were tested for blood groups in Mexico. The pie chart summarizes the ABO blood group distribution.
[Source: Canizalez-Román, A. et al., 2018. Blood Groups Distribution and Gene Diversity
of the ABO and Rh (D) Loci in the Mexican Population.
BioMed Research International, (Article ID 1925619).
http://dx.doi.org/10.1155/2018/1925619. Public domain.]What can be concluded from the ABO blood group distribution in Mexico?
A. Allele frequencies are not the same for all blood group alleles.
B. The majority of the Mexican population shows a co-dominant phenotype.
C. Most of the Mexican population can receive blood from all blood groups.
D. Only 2 % of the Mexican population have a heterozygous genotype for blood groups.
-
23M.1A.SL.TZ1.14:
Scientists sequenced the genes in each chromosome of chimpanzees (Pan troglodytes) and humans (Homo sapiens). The graph shows the mean divergence between the genes of these species by chromosome.
[Source: Material from: Mikkelsen, T.S. et al, Initial sequence of the chimpanzee genome and
comparison with the human genome, 2005 Nature, reproduced with permission of SNCSC.]
What can be deduced from this data?
A. Autosomes are more similar than Y chromosomes.B. There is the same number of chromosomes in humans and chimpanzees.
C. Humans are more closely related to chimpanzees than to other species.
D. Smaller chromosomes are more similar than larger chromosomes.
-
23M.1A.SL.TZ2.13:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
-
23M.1A.SL.TZ2.16:
The pedigree chart shows the inheritance of three generations of Duane syndrome, a condition caused by a dominant allele that affects alignment of the eyes.
[Source: Yang, M.-M., Ho, M. et al., 2013. Pedigree of a Chinese family with Duane retraction syndrome. [diagram online]
Available at: https://www.researchgate.net/figure/Pedigree-of-a-Chinese-family-with-Duane-retraction-syndrome-
Squares-men-circles_fig1_236921765 [Accessed 5 October 2021]. Public domain.]If individuals II:1 and II:2 had a third child, what is the probability that the child would have Duane syndrome?
A. 25 %
B. 50 %
C. 75 %
D. 100 %
- 23M.1A.SL.TZ2.32: In the fruit fly Drosophila, the alleles for red eyes and brown bodies are dominant to the...
D3.3 Homeostasis
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
20N.1B.SL.TZ0.1d.i:
Compare the data for plasma insulin levels before and after the study diet.
-
20N.1B.SL.TZ0.1d.ii:
State which cells secrete insulin.
- 20N.1B.SL.TZ0.1d.iii: Outline the reason for plasma insulin levels changing in the first 30 minutes of the test.
-
20N.1B.SL.TZ0.1e:
The hypothesis made before the study was that saturated fats in the diet affected the risk of coronary artery blockage and diabetes. Using all the data in question 1, evaluate whether this hypothesis is supported by the study.
- 19M.2.SL.TZ1.20c: HGH is a peptide hormone. Describe the mode of action of peptide hormones on target cells.
- 22M.1A.SL.TZ1.39: Glucose moves from the filtrate in the nephron into the bloodstream during normal kidney...
-
22M.1A.HL.TZ2.39:
The micrograph shows a glomerulus and Bowman’s capsule, where ultrafiltration takes place in the kidney.
[Source: MICROSCAPE/SCIENCE PHOTO LIBRARY.]
What facilitates the formation of glomerular filtrate?
A. Many fenestrations in walls of capillaries in the glomerulus
B. High pressure in the Bowman’s capsule
C. ADH secreted by the pituitary gland
D. Osmosis caused by a high concentration of urea in the blood
-
19M.2.SL.TZ2.6c:
Discuss the control of blood glucose levels and the consequences if they are not maintained.
- 19N.2.HL.TZ0.7a: Outline the reasons for the differences in blood concentrations between the renal artery and the...
- 22M.1A.SL.TZ1.30: What is most likely to increase in the presence of insulin? A. The rate of anaerobic...
-
22M.2.HL.TZ1.6c:
Explain how water balance is restored in mammals when they are dehydrated.
-
22M.2.SL.TZ2.8b:
Humans need to balance water and solute concentrations and also excrete nitrogenous wastes. Explain how the different parts of the kidney carry out these processes.
-
20N.2.HL.TZ0.7c:
Explain the role of the kidney in osmoregulation.
- 19M.1A.SL.TZ2.29: Which hormone is part of a negative feedback control system and acts on cells in the...
- 21M.1A.SL.TZ2.7: What property of water accounts for its usefulness as a coolant in sweat? A. High specific heat...
-
21N.1A.HL.TZ1.39:
Where in the nephron is most glucose reabsorbed?
[Source: National Institute of Diabetes and Digestive and Kidney Diseases, n.d. [Nephron]. [diagram online] Available at:
https://www.niddk.nih.gov/news/media-library/9164 [Accessed 23 March 2020].] - 19M.1A.HL.TZ2.33: What is the function of the loop of Henle? A. To reabsorb salt B. To maintain a hypertonic...
-
19M.1A.HL.TZ1.39:
The image shows a transverse section through a collecting duct in a vertebrate kidney.
[Source: Professor Peter Takizawa, Yale University]
How is the movement of materials across the wall of the collecting duct affected by the release of ADH from the pituitary gland?
A. There is increased movement of water in the direction of arrow I.
B. There is increased movement of sodium in the direction of arrow I.
C. There is increased movement of water in the direction of arrow II.
D. There is increased movement of sodium in the direction of arrow II.
- 19M.2.HL.TZ1.6c: Explain how blood solute concentrations are kept within narrow limits in the human body.
- 22N.2.HL.TZ0.5a.i: Identify structure X.
- 22N.2.HL.TZ0.5a.ii: Identify structure Y.
-
22N.2.HL.TZ0.5b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.5c:
Explain the role of the hormone ADH in osmoregulation.
-
22N.1A.SL.TZ0.2:
What life function is illustrated?
A. Nutrition
B. Homeostasis
C. Endocytosis
D. Response
- 22N.1A.SL.TZ0.29: The graph shows human body temperature variation in a daily rhythm of 24 hours. Which hormone...
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
-
23M.2.SL.TZ1.4bi:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.HL.TZ1.6a:
Outline the role of ADH in osmoregulation.
-
23M.2.SL.TZ1.4bi:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.HL.TZ2.2d:
The concentration of urea in blood plasma is typically about 30 mg per 100 ml. In urine it can be as high as 1800 mg per 100 ml. Explain how this increase in concentration is achieved.
- 23M.1A.SL.TZ1.19: What is secreted by the pancreas for digestion in the small intestine? A. Lipase to break bond...
-
23M.1A.HL.TZ1.39:
Merriam’s kangaroo rat (Dipodomys merriami) is a small mammal found in desert biomes in the southwestern USA and Mexico. What would help these kangaroo rats to conserve water in order to survive high temperatures in desert biomes?
A. Increased sweating
B. A long loop of Henle
C. Decreased secretion of ADH
D. Decreased reabsorption from the collecting duct
- 23M.1A.SL.TZ1.30: Which hormone helps control levels of glucose in blood? A. Insulin secreted by the liver...
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
- 22M.2.SL.TZ1.a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
22M.2.SL.TZ2.b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
- 22M.2.SL.TZ1.a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
22M.2.SL.TZ2.b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
- 22M.2.SL.TZ1.a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
22M.2.SL.TZ2.b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
- 22M.2.SL.TZ1.a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
22M.2.SL.TZ2.b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
- 22M.2.SL.TZ1.1a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.1b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.1c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.1d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.1e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.1f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.1g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.1h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.1i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.1j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.a: Estimate the difference between the highest and lowest mean body temperatures.
- 22M.2.SL.TZ1.b: Compare and contrast the changes in mean ambient and body temperatures during 2012.
-
22M.2.SL.TZ1.c:
Explain the change in heart rate during the period of hibernation.
- 22M.2.SL.TZ1.d: Distinguish between the changes in porosity of the bones in humans and bears as age increases.
- 22M.2.SL.TZ1.e: The life expectancy of a human at the time of the study was 80 years. Estimate the porosity of...
- 22M.2.SL.TZ1.f: The researchers assessed age as a proportion of normal life span, rather than in years. Suggest...
-
22M.2.SL.TZ1.g:
Describe what is happening to the bone during hibernation.
-
22M.2.SL.TZ1.h:
Suggest how the graph would differ for a human during a long period of inactivity.
-
22M.2.SL.TZ1.i:
Calculate the percentage increase in the mean concentration of osteocalcin from pre-hibernation to hibernation.
-
22M.2.SL.TZ1.j:
A hypothesis has been proposed that an increase in parathyroid hormone concentration causes an increase in osteocalcin in bears. Evaluate the evidence for this hypothesis provided by the data.
- 22M.2.SL.TZ1.1a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.1a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.1b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.1b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.1f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.1g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.1h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.1i:
State one feature of the sloth that would indicate it is a mammal.
- 22M.2.SL.TZ1.a.i: State the relationship between sloth body temperature and ambient temperature.
- 22M.2.SL.TZ1.a.ii: Explain how this relationship differs from that in humans.
- 22M.2.SL.TZ1.b.i: Describe the trend in body posture as ambient temperature rises from 22 to 34 °C.
- 22M.2.SL.TZ1.b.ii: Suggest reasons for this trend.
- 22M.2.SL.TZ1.f: The mean daily food intake fluctuated from day to day. State the month that contains the day on...
- 22M.2.SL.TZ1.g: Outline the relationship between ambient daily temperature and food intake in March.
- 22M.2.SL.TZ1.h: Suggest, with a reason, how the activity of the sloth varies with ambient temperature.
-
22M.2.SL.TZ1.i:
State one feature of the sloth that would indicate it is a mammal.
-
22M.2.SL.TZ2.5b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.5b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
22M.2.SL.TZ2.b.i:
Explain what happens in a person when they develop type I diabetes.
- 22M.2.SL.TZ2.b.ii: State how type I diabetes should be treated to avoid harmful health consequences of the condition.
-
20N.1B.SL.TZ0.1d.i:
Compare the data for plasma insulin levels before and after the study diet.
-
20N.1B.SL.TZ0.1d.ii:
State which cells secrete insulin.
- 20N.1B.SL.TZ0.1d.iii: Outline the reason for plasma insulin levels changing in the first 30 minutes of the test.
-
20N.1B.SL.TZ0.1e:
The hypothesis made before the study was that saturated fats in the diet affected the risk of coronary artery blockage and diabetes. Using all the data in question 1, evaluate whether this hypothesis is supported by the study.
-
20N.1B.SL.TZ0.d.i:
Compare the data for plasma insulin levels before and after the study diet.
-
20N.1B.SL.TZ0.d.ii:
State which cells secrete insulin.
- 20N.1B.SL.TZ0.d.iii: Outline the reason for plasma insulin levels changing in the first 30 minutes of the test.
-
20N.1B.SL.TZ0.e:
The hypothesis made before the study was that saturated fats in the diet affected the risk of coronary artery blockage and diabetes. Using all the data in question 1, evaluate whether this hypothesis is supported by the study.
- 19M.2.SL.TZ1.c: HGH is a peptide hormone. Describe the mode of action of peptide hormones on target cells.
- 22M.1A.SL.TZ1.39: Glucose moves from the filtrate in the nephron into the bloodstream during normal kidney...
-
22M.1A.HL.TZ2.39:
The micrograph shows a glomerulus and Bowman’s capsule, where ultrafiltration takes place in the kidney.
[Source: MICROSCAPE/SCIENCE PHOTO LIBRARY.]
What facilitates the formation of glomerular filtrate?
A. Many fenestrations in walls of capillaries in the glomerulus
B. High pressure in the Bowman’s capsule
C. ADH secreted by the pituitary gland
D. Osmosis caused by a high concentration of urea in the blood
-
19M.2.SL.TZ2.6c:
Discuss the control of blood glucose levels and the consequences if they are not maintained.
-
19M.2.SL.TZ2.c:
Discuss the control of blood glucose levels and the consequences if they are not maintained.
- 19N.2.HL.TZ0.7a: Outline the reasons for the differences in blood concentrations between the renal artery and the...
- 19N.2.HL.TZ0.a: Outline the reasons for the differences in blood concentrations between the renal artery and the...
- 22M.1A.SL.TZ1.30: What is most likely to increase in the presence of insulin? A. The rate of anaerobic...
-
22M.2.HL.TZ1.6c:
Explain how water balance is restored in mammals when they are dehydrated.
-
22M.2.HL.TZ1.c:
Explain how water balance is restored in mammals when they are dehydrated.
-
22M.2.SL.TZ2.8b:
Humans need to balance water and solute concentrations and also excrete nitrogenous wastes. Explain how the different parts of the kidney carry out these processes.
-
22M.2.SL.TZ2.b:
Humans need to balance water and solute concentrations and also excrete nitrogenous wastes. Explain how the different parts of the kidney carry out these processes.
-
20N.2.HL.TZ0.7c:
Explain the role of the kidney in osmoregulation.
-
20N.2.HL.TZ0.c:
Explain the role of the kidney in osmoregulation.
- 19M.1A.SL.TZ2.29: Which hormone is part of a negative feedback control system and acts on cells in the...
- 21M.1A.SL.TZ2.7: What property of water accounts for its usefulness as a coolant in sweat? A. High specific heat...
-
21N.1A.HL.TZ1.39:
Where in the nephron is most glucose reabsorbed?
[Source: National Institute of Diabetes and Digestive and Kidney Diseases, n.d. [Nephron]. [diagram online] Available at:
https://www.niddk.nih.gov/news/media-library/9164 [Accessed 23 March 2020].] - 19M.1A.HL.TZ2.33: What is the function of the loop of Henle? A. To reabsorb salt B. To maintain a hypertonic...
-
19M.1A.HL.TZ1.39:
The image shows a transverse section through a collecting duct in a vertebrate kidney.
[Source: Professor Peter Takizawa, Yale University]
How is the movement of materials across the wall of the collecting duct affected by the release of ADH from the pituitary gland?
A. There is increased movement of water in the direction of arrow I.
B. There is increased movement of sodium in the direction of arrow I.
C. There is increased movement of water in the direction of arrow II.
D. There is increased movement of sodium in the direction of arrow II.
- 19M.2.HL.TZ1.6c: Explain how blood solute concentrations are kept within narrow limits in the human body.
- 19M.2.HL.TZ1.c: Explain how blood solute concentrations are kept within narrow limits in the human body.
- 22N.2.HL.TZ0.5a.i: Identify structure X.
- 22N.2.HL.TZ0.5a.ii: Identify structure Y.
-
22N.2.HL.TZ0.5b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.5c:
Explain the role of the hormone ADH in osmoregulation.
- 22N.2.HL.TZ0.a.i: Identify structure X.
- 22N.2.HL.TZ0.a.ii: Identify structure Y.
-
22N.2.HL.TZ0.b:
State the region of the kidney in which the loop of Henle is situated.
-
22N.2.HL.TZ0.c:
Explain the role of the hormone ADH in osmoregulation.
-
22N.1A.SL.TZ0.2:
What life function is illustrated?
A. Nutrition
B. Homeostasis
C. Endocytosis
D. Response
- 22N.1A.SL.TZ0.29: The graph shows human body temperature variation in a daily rhythm of 24 hours. Which hormone...
- SPM.1A.HL.TZ0.30: How would the body respond to a rise above normal body temperature?
- SPM.1A.SL.TZ0.19: What conveys messages from the central nervous system to an endocrine gland? A. Sensory...
- SPM.1A.SL.TZ0.21: How would the body respond to a rise above normal body temperature?
-
SPM.2.SL.TZ0.8a:
Explain the mechanisms involved in thermoregulation in humans.
-
SPM.2.SL.TZ0.a:
Explain the mechanisms involved in thermoregulation in humans.
-
23M.2.SL.TZ1.4bi:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.SL.TZ1.i:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.HL.TZ1.6a:
Outline the role of ADH in osmoregulation.
-
23M.2.HL.TZ1.a:
Outline the role of ADH in osmoregulation.
-
23M.2.SL.TZ1.4bi:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.SL.TZ1.i:
With reference to the diagram, explain how water in sweat evaporates.
-
23M.2.HL.TZ2.2d:
The concentration of urea in blood plasma is typically about 30 mg per 100 ml. In urine it can be as high as 1800 mg per 100 ml. Explain how this increase in concentration is achieved.
-
23M.2.HL.TZ2.d:
The concentration of urea in blood plasma is typically about 30 mg per 100 ml. In urine it can be as high as 1800 mg per 100 ml. Explain how this increase in concentration is achieved.
- 23M.1A.SL.TZ1.19: What is secreted by the pancreas for digestion in the small intestine? A. Lipase to break bond...
-
23M.1A.HL.TZ1.39:
Merriam’s kangaroo rat (Dipodomys merriami) is a small mammal found in desert biomes in the southwestern USA and Mexico. What would help these kangaroo rats to conserve water in order to survive high temperatures in desert biomes?
A. Increased sweating
B. A long loop of Henle
C. Decreased secretion of ADH
D. Decreased reabsorption from the collecting duct
- 23M.1A.SL.TZ1.30: Which hormone helps control levels of glucose in blood? A. Insulin secreted by the liver...
D4.1 Natural selection
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
20N.2.SL.TZ0.8b:
Explain how natural selection can cause mate selection behaviour patterns to develop in a species such as eastern bluebirds.
- 19M.1B.SL.TZ2.12d: State one abiotic factor that could have determined the distribution of barnacles.
- 21M.1A.SL.TZ1.22: Which process results in decreased variation? A. Meiosis B. Mutation C. Sexual...
- 19M.1A.SL.TZ1.21: Which is an example of natural selection? A. A giraffe stretching its neck to reach higher...
- 22M.1A.SL.TZ1.13: The table shows the estimated total number of genes in several organisms. What can be deduced...
- 19N.2.SL.TZ0.4a: State the immediate consequence of a species producing more offspring than the environment can...
- 19N.2.SL.TZ0.4b: Explain the consequence of overpopulation on the survival and reproduction of better adapted...
- 20N.2.SL.TZ0.4b.ii: Explain how evolution by natural selection depends on mutations.
- 19M.1A.HL.TZ1.35: Natural selection can operate in different ways. What is the effect of disruptive selection? A....
- 19M.1A.SL.TZ2.20: What is required for natural selection to occur? I. Acquired characteristics II. Advantageous...
-
22M.2.SL.TZ2.7b:
Explain how natural selection can cause traits such as drought resistance to develop in wild plants.
- 21N.2.SL.TZ0.6c: Distinguish between continuous and discrete variation, using examples.
-
22N.1A.SL.TZ0.20:
By the end of the 19th century in England, the dark form of the moth Biston betularia formed up to 98% of the total population in industrial areas. From 1970, the percentage of dark forms decreased significantly. What is an explanation for the decrease?
A. An increase in environmental pollution killed the dark forms more than the light forms.
B. Reduction of pollution resulted in greater camouflage for light forms of the moth.
C. Dark forms could no longer find mates.
D. Light forms had superior feeding mechanisms.
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
-
23M.2.HL.TZ1.3a:
Explain how natural selection could increase the prevalence of an antibiotic resistance gene in a species of soil bacterium.
- 23M.1A.SL.TZ2.8ai: Identify the relationship between migration distance and plumage colouration.
-
23M.1A.SL.TZ2.8aii:
Suggest two reasons, other than mate selection, for variation in plumage colouration in red knots.
-
23M.1A.HL.TZ2.33:
The graphs show how the frequency (f) of a trait within a population changes when subjected to selection pressures. Which graph shows stabilizing selection?
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
- 19M.2.SL.TZ2.j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
- 19M.2.SL.TZ2.j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
- 19M.2.SL.TZ2.j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
- 19M.2.SL.TZ2.j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
22M.1A.HL.TZ1.21:
The graph shows the proportion of a bacterial population of Neisseria gonorrhoeae, displaying resistance to the antibiotic tetracycline.
[Source: © All rights reserved. Canadian Antimicrobial Resistance Surveillance System Report, 2016. Public Health Agency of Canada. Adapted and reproduced with permission from the Minister of Health, 2022.]
What can be deduced from this graph?
A. Bacteria with beneficial adaptations survive and pass on their genes.
B. Immunity to tetracycline is triggered by over-use of the antibiotic.
C. Genetic variation in this bacterial population is increasing.
D. Use of tetracycline inhibits the growth of antibiotic-resistant N. gonorrhoeae.
- 22M.1A.HL.TZ2.19: Some strains of the pathogenic bacterium Staphylococcus aureus have developed mechanisms that...
- 19M.2.SL.TZ2.1j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
- 19M.2.SL.TZ2.j: Discuss whether natural selection would favour the transgenic EBF-producing thale cress plants if...
-
20N.2.SL.TZ0.b:
Explain how natural selection can cause mate selection behaviour patterns to develop in a species such as eastern bluebirds.
- 19M.1B.SL.TZ2.d: State one abiotic factor that could have determined the distribution of barnacles.
- 21M.1A.SL.TZ1.22: Which process results in decreased variation? A. Meiosis B. Mutation C. Sexual...
- 19M.1A.SL.TZ1.21: Which is an example of natural selection? A. A giraffe stretching its neck to reach higher...
- 22M.1A.SL.TZ1.13: The table shows the estimated total number of genes in several organisms. What can be deduced...
- 19N.2.SL.TZ0.4a: State the immediate consequence of a species producing more offspring than the environment can...
- 19N.2.SL.TZ0.4b: Explain the consequence of overpopulation on the survival and reproduction of better adapted...
- 19N.2.SL.TZ0.a: State the immediate consequence of a species producing more offspring than the environment can...
- 19N.2.SL.TZ0.b: Explain the consequence of overpopulation on the survival and reproduction of better adapted...
- 20N.2.SL.TZ0.4b.ii: Explain how evolution by natural selection depends on mutations.
- 20N.2.SL.TZ0.b.ii: Explain how evolution by natural selection depends on mutations.
- 19M.1A.HL.TZ1.35: Natural selection can operate in different ways. What is the effect of disruptive selection? A....
- 19M.1A.SL.TZ2.20: What is required for natural selection to occur? I. Acquired characteristics II. Advantageous...
-
22M.2.SL.TZ2.7b:
Explain how natural selection can cause traits such as drought resistance to develop in wild plants.
-
22M.2.SL.TZ2.b:
Explain how natural selection can cause traits such as drought resistance to develop in wild plants.
- 21N.2.SL.TZ0.6c: Distinguish between continuous and discrete variation, using examples.
- 21N.2.SL.TZ0.c: Distinguish between continuous and discrete variation, using examples.
-
22N.1A.SL.TZ0.20:
By the end of the 19th century in England, the dark form of the moth Biston betularia formed up to 98% of the total population in industrial areas. From 1970, the percentage of dark forms decreased significantly. What is an explanation for the decrease?
A. An increase in environmental pollution killed the dark forms more than the light forms.
B. Reduction of pollution resulted in greater camouflage for light forms of the moth.
C. Dark forms could no longer find mates.
D. Light forms had superior feeding mechanisms.
- SPM.1A.HL.TZ0.39: What assumption is made when using the Hardy-Weinberg equation for calculating changes in allele...
-
SPM.1A.HL.TZ0.40:
Domestic dogs (Canis familiaris) have evolved from grey wolves (Canis lupus). Evidence suggests that the domestication of dogs first occurred around 30 000 years ago. Which best describes the evolution giving rise to the domestic dog?
A. The wolf produced offspring in large numbers which underwent natural selection.B. Variations in the wolf population that resembled modern dogs favoured wolf survival.
C. Wolves showing favourable traits were selected for breeding.
D. Dogs were better suited to changes in the natural environment than wolves.
- SPM.1A.SL.TZ0.30: What is an outcome of natural selection? A. Evolution B. Mutations C. Reproductive...
- SPM.2.SL.TZ0.6b: Explain how sexual reproduction gives rise to genetic variation.
- SPM.2.SL.TZ0.b: Explain how sexual reproduction gives rise to genetic variation.
-
23M.2.HL.TZ1.3a:
Explain how natural selection could increase the prevalence of an antibiotic resistance gene in a species of soil bacterium.
-
23M.2.HL.TZ1.a:
Explain how natural selection could increase the prevalence of an antibiotic resistance gene in a species of soil bacterium.
- 23M.1A.SL.TZ2.i: Identify the relationship between migration distance and plumage colouration.
-
23M.1A.SL.TZ2.ii:
Suggest two reasons, other than mate selection, for variation in plumage colouration in red knots.
-
23M.1A.HL.TZ2.33:
The graphs show how the frequency (f) of a trait within a population changes when subjected to selection pressures. Which graph shows stabilizing selection?
D4.2 Stability and change
- 20N.2.SL.TZ0.13a.i: Calculate the number of species of grebe with problems due to entanglement.
- 20N.2.SL.TZ0.13a.ii: Suggest how entanglement in plastics can lead to the death of marine birds.
- 20N.2.SL.TZ0.13b.i: Identify the group with the greatest number of species with problems due to ingestion of plastics.
-
20N.2.SL.TZ0.13b.ii:
Describe how ingested plastics can cause problems to marine birds.
-
20N.2.SL.TZ0.15b:
Sea otters are considered keystone species in this environment. Suggest how the presence of sea otters could affect the algae population.
-
20N.2.SL.TZ0.1a.i:
State the distance from the city centre at which the highest proportion of plants sampled contained HCN.
-
20N.2.SL.TZ0.1a.ii:
Outline the relationship shown in the graph.
-
20N.2.SL.TZ0.1b:
Deduce whether the pattern of cyanogenesis was the same in all of the areas around all four cities.
- 20N.2.SL.TZ0.1d.i: Identify with a reason the city where the plants were more insulated from freezing temperatures.
-
20N.2.SL.TZ0.1d.ii:
Using all of the data so far, suggest whether exposure to freezing temperatures in the four cities is supported as a reason for the differences in HCN production in T. repens.
- 19M.2.HL.TZ2.15a.ii: Using the climograph, identify the relationship between maximum temperature and rainfall.
- 19M.2.HL.TZ2.15a.iii: Using the climograph, outline the pattern of rainfall.
- 19M.2.HL.TZ2.15b: Natural forests in the area around Mangalore contain hardwood trees such as teak, Tectona...
- 19M.1A.SL.TZ2.19: Which is not essential in a viable mesocosm? A. Light source B. Autotroph C. Saprotroph D....
- 19N.2.SL.TZ0.17c: Describe the major characteristics of a eutrophic lake.
- 19N.2.SL.TZ0.13a: Explain why some biologists think protecting keystone species would help preserve biological...
- 19N.2.SL.TZ0.5c: Explain the movement of energy and inorganic nutrients in an ecosystem.
- 19M.2.SL.TZ1.14a: Describe the relationship between rock phosphate production and world population.
- 19M.2.SL.TZ1.14b: Phosphate can be lost from agricultural land in several different ways. State one of these.
- 19M.2.SL.TZ1.14c: Describe how the changes in world rock phosphate production after 1985 may have affected world...
- 19N.2.SL.TZ0.15a: Compare and contrast the information provided for baleen whales and sea turtles.
- 19N.2.SL.TZ0.15b: Outline how plastic ingestion may lead to biomagnification in these marine species.
- 19N.2.SL.TZ0.14c: Explain why some biologists think protecting keystone species would help preserve biological...
- 19M.2.HL.TZ1.10b: Compare and contrast the community structure within and outside the marine protected area.
- 19M.2.SL.TZ1.10c: With respect to this food chain, outline what is meant by a keystone species.
-
21N.2.SL.TZ0.1a:
Describe the effect of temperature on the total biomass.
-
21N.2.SL.TZ0.1b:
Compare and contrast the effects of temperature on the biomass of autotrophs and heterotrophs with added nutrients.
-
21N.2.SL.TZ0.1c:
Explain the effect of temperature on the rate of photosynthesis in this mesocosm.
-
21N.2.SL.TZ0.1d:
Suggest reasons for the decreases in biomass of autotrophs as temperature rises, despite the increases in photosynthesis.
- 21N.2.SL.TZ0.1e: Describe the effects of temperature and nitrate concentration on biomass.
-
21N.2.SL.TZ0.1f:
Suggest two abiotic factors, other than temperature and nutrient supply, that may affect the production of biomass of the grasslands.
- 21N.2.SL.TZ0.1g: The first study used mesocosms and the second study was carried out in natural grassland. Discuss...
-
19N.2.SL.TZ0.8c:
Explain the movement of energy and inorganic nutrients in an ecosystem.
- 21N.1A.SL.TZ0.17: What is exchanged between a sealed mesocosm and the surrounding external environment? A....
-
19N.1B.SL.TZ0.1a:
Compare and contrast the design of both mesocosms (vertical flow and horizontal flow).
- 19N.1B.SL.TZ0.1b: Suggest with a reason which system best reproduces the conditions of the natural environment.
- 19N.1B.SL.TZ0.1c: State two variables other than temperature and light that should be controlled in this...
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
23M.2.SL.TZ1.16a:
Outline how the prickly pear cactus may become an ecological problem in Kruger National Park.
-
23M.2.SL.TZ1.18a:
Label with a P on the -axis the level of commercial sea fishing activity that would result in maximum sustainability.
- 23M.2.SL.TZ1.18b: Outline the reason for the change in yield in region III of the diagram.
- 23M.2.SL.TZ1.18c: Suggest a reason that it is difficult to keep global commercial sea fishing activity at a...
-
23M.1B.SL.TZ2.3a:
State two variables measured by the probes.
1:
2:
- 23M.1B.SL.TZ2.3b: Suggest one advantage of using a mesocosm in this type of research.
-
23M.1B.SL.TZ2.3c:
Outline the requirements for sustainability within a sealed mesocosm.
- 23M.2.HL.TZ2.17a: Outline primary succession.
- 23M.2.SL.TZ2.18ai: State the relationship between DDE concentration and eggshell thickness.
- 23M.2.SL.TZ2.18aii: Suggest one reason for a decline in the brown pelican population with the most eggshell thinning.
-
23M.2.SL.TZ2.18b:
Deduce, giving reasons, which brown pelican population decreased the most in the years following the study.
-
23M.2.SL.TZ2.18c:
Outline the biomagnification of DDE in brown pelicans.
-
23M.2.SL.TZ2.19:
Duckweed (Lemna gibba) is a plant that grows on the surface of water. It was grown in cultures and the percentage increase in total area covered per day was obtained. The graph shows the specific growth rates per day for duckweed measured over 22 days.
Material from: Mkandawire, M. and Dudel, E.G., Assignment of Lemna gibba L. (duckweed) bioassay for in situ
ecotoxicity assessment, published 2005, Aquatic Ecology, reproduced with permission of SNCSC.Suggest reasons for the slowing down of duckweed population growth after day 6.
- 23M.2.SL.TZ2.20a: Outline the effect of nitrogen compounds from agricultural land leaching into a lake.
- 23M.2.SL.TZ2.20b: State the relationship between elevation and nitrogen concentration in leaves of pitcher plants.
-
23M.2.SL.TZ2.20c:
Suggest two reasons, other than elevation, for the differences in nitrogen concentration in leaves of pitcher plants.
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
- 20N.2.SL.TZ0.a.i: Calculate the number of species of grebe with problems due to entanglement.
- 20N.2.SL.TZ0.a.ii: Suggest how entanglement in plastics can lead to the death of marine birds.
- 20N.2.SL.TZ0.b.i: Identify the group with the greatest number of species with problems due to ingestion of plastics.
-
20N.2.SL.TZ0.b.ii:
Describe how ingested plastics can cause problems to marine birds.
-
20N.2.SL.TZ0.b:
Sea otters are considered keystone species in this environment. Suggest how the presence of sea otters could affect the algae population.
-
20N.2.SL.TZ0.1a.i:
State the distance from the city centre at which the highest proportion of plants sampled contained HCN.
-
20N.2.SL.TZ0.1a.ii:
Outline the relationship shown in the graph.
-
20N.2.SL.TZ0.1b:
Deduce whether the pattern of cyanogenesis was the same in all of the areas around all four cities.
- 20N.2.SL.TZ0.1d.i: Identify with a reason the city where the plants were more insulated from freezing temperatures.
-
20N.2.SL.TZ0.1d.ii:
Using all of the data so far, suggest whether exposure to freezing temperatures in the four cities is supported as a reason for the differences in HCN production in T. repens.
-
20N.2.SL.TZ0.a.i:
State the distance from the city centre at which the highest proportion of plants sampled contained HCN.
-
20N.2.SL.TZ0.a.ii:
Outline the relationship shown in the graph.
-
20N.2.SL.TZ0.b:
Deduce whether the pattern of cyanogenesis was the same in all of the areas around all four cities.
- 20N.2.SL.TZ0.d.i: Identify with a reason the city where the plants were more insulated from freezing temperatures.
-
20N.2.SL.TZ0.d.ii:
Using all of the data so far, suggest whether exposure to freezing temperatures in the four cities is supported as a reason for the differences in HCN production in T. repens.
- 19M.2.HL.TZ2.a.ii: Using the climograph, identify the relationship between maximum temperature and rainfall.
- 19M.2.HL.TZ2.a.iii: Using the climograph, outline the pattern of rainfall.
- 19M.2.HL.TZ2.b: Natural forests in the area around Mangalore contain hardwood trees such as teak, Tectona...
- 19M.1A.SL.TZ2.19: Which is not essential in a viable mesocosm? A. Light source B. Autotroph C. Saprotroph D....
- 19N.2.SL.TZ0.c: Describe the major characteristics of a eutrophic lake.
- 19N.2.SL.TZ0.a: Explain why some biologists think protecting keystone species would help preserve biological...
- 19N.2.SL.TZ0.5c: Explain the movement of energy and inorganic nutrients in an ecosystem.
- 19N.2.SL.TZ0.c: Explain the movement of energy and inorganic nutrients in an ecosystem.
- 19M.2.SL.TZ1.a: Describe the relationship between rock phosphate production and world population.
- 19M.2.SL.TZ1.b: Phosphate can be lost from agricultural land in several different ways. State one of these.
- 19M.2.SL.TZ1.c: Describe how the changes in world rock phosphate production after 1985 may have affected world...
- 19N.2.SL.TZ0.a: Compare and contrast the information provided for baleen whales and sea turtles.
- 19N.2.SL.TZ0.b: Outline how plastic ingestion may lead to biomagnification in these marine species.
- 19N.2.SL.TZ0.c: Explain why some biologists think protecting keystone species would help preserve biological...
- 19M.2.HL.TZ1.b: Compare and contrast the community structure within and outside the marine protected area.
- 19M.2.SL.TZ1.c: With respect to this food chain, outline what is meant by a keystone species.
-
21N.2.SL.TZ0.1a:
Describe the effect of temperature on the total biomass.
-
21N.2.SL.TZ0.1b:
Compare and contrast the effects of temperature on the biomass of autotrophs and heterotrophs with added nutrients.
-
21N.2.SL.TZ0.1c:
Explain the effect of temperature on the rate of photosynthesis in this mesocosm.
-
21N.2.SL.TZ0.1d:
Suggest reasons for the decreases in biomass of autotrophs as temperature rises, despite the increases in photosynthesis.
- 21N.2.SL.TZ0.1e: Describe the effects of temperature and nitrate concentration on biomass.
-
21N.2.SL.TZ0.1f:
Suggest two abiotic factors, other than temperature and nutrient supply, that may affect the production of biomass of the grasslands.
- 21N.2.SL.TZ0.1g: The first study used mesocosms and the second study was carried out in natural grassland. Discuss...
-
21N.2.SL.TZ0.a:
Describe the effect of temperature on the total biomass.
-
21N.2.SL.TZ0.b:
Compare and contrast the effects of temperature on the biomass of autotrophs and heterotrophs with added nutrients.
-
21N.2.SL.TZ0.c:
Explain the effect of temperature on the rate of photosynthesis in this mesocosm.
-
21N.2.SL.TZ0.d:
Suggest reasons for the decreases in biomass of autotrophs as temperature rises, despite the increases in photosynthesis.
- 21N.2.SL.TZ0.e: Describe the effects of temperature and nitrate concentration on biomass.
-
21N.2.SL.TZ0.f:
Suggest two abiotic factors, other than temperature and nutrient supply, that may affect the production of biomass of the grasslands.
- 21N.2.SL.TZ0.g: The first study used mesocosms and the second study was carried out in natural grassland. Discuss...
-
19N.2.SL.TZ0.c:
Explain the movement of energy and inorganic nutrients in an ecosystem.
- 21N.1A.SL.TZ0.17: What is exchanged between a sealed mesocosm and the surrounding external environment? A....
-
19N.1B.SL.TZ0.a:
Compare and contrast the design of both mesocosms (vertical flow and horizontal flow).
- 19N.1B.SL.TZ0.b: Suggest with a reason which system best reproduces the conditions of the natural environment.
- 19N.1B.SL.TZ0.c: State two variables other than temperature and light that should be controlled in this...
-
SPM.2.HL.TZ0.9a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
SPM.2.HL.TZ0.a:
Describe how toxins such as DDT might concentrate in the bodies of birds.
-
23M.2.SL.TZ1.a:
Outline how the prickly pear cactus may become an ecological problem in Kruger National Park.
-
23M.2.SL.TZ1.a:
Label with a P on the -axis the level of commercial sea fishing activity that would result in maximum sustainability.
- 23M.2.SL.TZ1.b: Outline the reason for the change in yield in region III of the diagram.
- 23M.2.SL.TZ1.c: Suggest a reason that it is difficult to keep global commercial sea fishing activity at a...
-
23M.1B.SL.TZ2.a:
State two variables measured by the probes.
1:
2:
- 23M.1B.SL.TZ2.b: Suggest one advantage of using a mesocosm in this type of research.
-
23M.1B.SL.TZ2.c:
Outline the requirements for sustainability within a sealed mesocosm.
- 23M.2.HL.TZ2.a: Outline primary succession.
- 23M.2.SL.TZ2.i: State the relationship between DDE concentration and eggshell thickness.
- 23M.2.SL.TZ2.ii: Suggest one reason for a decline in the brown pelican population with the most eggshell thinning.
-
23M.2.SL.TZ2.b:
Deduce, giving reasons, which brown pelican population decreased the most in the years following the study.
-
23M.2.SL.TZ2.c:
Outline the biomagnification of DDE in brown pelicans.
-
23M.2.SL.TZ2.19:
Duckweed (Lemna gibba) is a plant that grows on the surface of water. It was grown in cultures and the percentage increase in total area covered per day was obtained. The graph shows the specific growth rates per day for duckweed measured over 22 days.
Material from: Mkandawire, M. and Dudel, E.G., Assignment of Lemna gibba L. (duckweed) bioassay for in situ
ecotoxicity assessment, published 2005, Aquatic Ecology, reproduced with permission of SNCSC.Suggest reasons for the slowing down of duckweed population growth after day 6.
- 23M.2.SL.TZ2.a: Outline the effect of nitrogen compounds from agricultural land leaching into a lake.
- 23M.2.SL.TZ2.b: State the relationship between elevation and nitrogen concentration in leaves of pitcher plants.
-
23M.2.SL.TZ2.c:
Suggest two reasons, other than elevation, for the differences in nitrogen concentration in leaves of pitcher plants.
D4.3 Climate Change
-
21M.2.SL.TZ2.4c:
Explain how energy enters, flows through and is lost from marine food chains.
-
22M.2.SL.TZ1.3a:
Calculate the increase in mean global temperature between 1880 and 2010.
.......... °C
- 22M.2.SL.TZ1.3b: Outline how changes in temperature over short time periods could give a misleading impression of...
-
22M.2.SL.TZ1.3c:
Explain how increased carbon dioxide in the air leads to the greenhouse effect.
- 20N.1A.SL.TZ0.18: Under certain conditions, living organisms on Earth produce and release methane. What favours the...
- 21N.2.SL.TZ0.1a.i: Identify the site with the highest incidence of diseased colonies.
- 21N.2.SL.TZ0.1a.ii: Deduce whether there is a trend in the incidence of white syndrome over the north-south range of...
-
21N.2.SL.TZ0.1b.i:
Describe the evidence that is provided by the data in the table for the harmful effects of rising sea temperatures on corals.
-
21N.2.SL.TZ0.1b.ii:
The researchers concluded that there was a threshold coral cover percentage, below which infection rates tended to remain fairly low. Using the data in the table, identify this threshold level.
-
21N.2.SL.TZ0.1b.iii:
Suggest a reason for a larger percentage of corals being infected with white syndrome on reefs with a higher cover of corals.
-
21N.2.SL.TZ0.1c.i:
Compare and contrast the data for 1998–1999 and 2002–2003.
- 21N.2.SL.TZ0.1c.ii: Suggest a reason for the correlation between coral cover and WSSTA in 1998–1999.
-
21N.2.SL.TZ0.1d:
Some scientists predict that, if humans continue to produce carbon dioxide at the current rate, the pH of the oceans will become more acidic. Suggest possible effects on the coral reefs.
- 21N.2.SL.TZ0.1e: This study was carried out over six years on the Australian Great Barrier Reef. State one...
- 19M.2.HL.TZ2.3b: Suggest how climate change can influence the natural selection of organisms that live in the...
-
21M.1A.SL.TZ2.19:
Which gases have made the most significant contributions to global warming?
A. Water and carbon dioxide
B. Carbon dioxide and methane
C. Methane and nitrous oxide
D. Carbon dioxide and ozone
-
21M.2.SL.TZ1.7c:
Discuss the relationship between atmospheric carbon dioxide concentration and global temperatures.
- 22M.2.SL.TZ2.3b.ii: Explain the role of methane in climate change.
- 19N.1A.SL.TZ0.20: What material is formed when organic matter is not fully decomposed in acidic waterlogged...
- 20N.1A.SL.TZ0.19: The oceans absorb much of the carbon dioxide in the atmosphere. The combustion of fossil fuels...
- 22M.1A.SL.TZ1.16: What is a potential consequence of the rise in global temperatures? A. Increased exposure to UV...
- 21N.1A.SL.TZ0.19: How do greenhouse gases contribute to global warming? A. They destroy the ozone layer, allowing...
-
21M.2.SL.TZ1.3a:
The map shows the widespread distribution of coral reef ecosystems (indicated by black dots) in the world’s oceans. Death of coral reefs is related to increasing atmospheric carbon dioxide concentrations.
[Source: National Oceanic and Atmospheric Administration, 2021. Where Reef Building Corals Found. [map online] Available at: https://oceanservice.noaa.gov/education/tutorial_corals/media/supp_coral05a.html [Accessed 20 May 2021].]
Explain how increased atmospheric carbon dioxide concentrations can lead to coral death.
-
22N.2.SL.TZ0.3a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
-
22N.2.SL.TZ0.3b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
- 22N.2.SL.TZ0.3c: State one other gas that contributes to global warming.
- 22M.1A.SL.TZ2.15: The table shows features of greenhouse gases in the atmosphere. According to the data in the...
- 23M.2.SL.TZ1.1a: Compare and contrast the LAI data for the arctic and temperate zones.
-
23M.2.SL.TZ1.1b:
Suggest reasons for the differences in LAI between the boreal and equatorial zones.
-
23M.2.SL.TZ1.1c:
Analyse the data shown in the graph for evidence of a relationship between LAI and El Niño events.
- 23M.2.SL.TZ1.1d: The data in the graph show a long-term trend in global LAI.
-
23M.2.SL.TZ1.1di:
State the trend.
-
23M.2.SL.TZ1.1dii:
Global ecosystem modelling suggests that most of the change in LAI is due to increases in atmospheric carbon dioxide. Explain how rising atmospheric carbon dioxide (CO2) concentration could cause the observed change in LAI.
-
23M.2.SL.TZ1.1e:
State the effect of elevated CO2 on net primary production in these young, developing forests.
-
23M.2.SL.TZ1.1f:
Outline one benefit of conducting similar FACE experiments in multiple locations.
-
23M.2.SL.TZ1.1g:
Evaluate the evidence from the bar chart that increases in carbon dioxide cause increases in carbon storage in young, developing forests.
-
23M.2.SL.TZ2.6c:
Describe how human activities have caused average surface air temperatures on Earth to increase.
-
21M.2.SL.TZ2.4c:
Explain how energy enters, flows through and is lost from marine food chains.
-
21M.2.SL.TZ2.c:
Explain how energy enters, flows through and is lost from marine food chains.
-
22M.2.SL.TZ1.3a:
Calculate the increase in mean global temperature between 1880 and 2010.
.......... °C
- 22M.2.SL.TZ1.3b: Outline how changes in temperature over short time periods could give a misleading impression of...
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22M.2.SL.TZ1.3c:
Explain how increased carbon dioxide in the air leads to the greenhouse effect.
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22M.2.SL.TZ1.a:
Calculate the increase in mean global temperature between 1880 and 2010.
.......... °C
- 22M.2.SL.TZ1.b: Outline how changes in temperature over short time periods could give a misleading impression of...
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22M.2.SL.TZ1.c:
Explain how increased carbon dioxide in the air leads to the greenhouse effect.
- 20N.1A.SL.TZ0.18: Under certain conditions, living organisms on Earth produce and release methane. What favours the...
- 21N.2.SL.TZ0.1a.i: Identify the site with the highest incidence of diseased colonies.
- 21N.2.SL.TZ0.1a.ii: Deduce whether there is a trend in the incidence of white syndrome over the north-south range of...
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21N.2.SL.TZ0.1b.i:
Describe the evidence that is provided by the data in the table for the harmful effects of rising sea temperatures on corals.
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21N.2.SL.TZ0.1b.ii:
The researchers concluded that there was a threshold coral cover percentage, below which infection rates tended to remain fairly low. Using the data in the table, identify this threshold level.
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21N.2.SL.TZ0.1b.iii:
Suggest a reason for a larger percentage of corals being infected with white syndrome on reefs with a higher cover of corals.
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21N.2.SL.TZ0.1c.i:
Compare and contrast the data for 1998–1999 and 2002–2003.
- 21N.2.SL.TZ0.1c.ii: Suggest a reason for the correlation between coral cover and WSSTA in 1998–1999.
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21N.2.SL.TZ0.1d:
Some scientists predict that, if humans continue to produce carbon dioxide at the current rate, the pH of the oceans will become more acidic. Suggest possible effects on the coral reefs.
- 21N.2.SL.TZ0.1e: This study was carried out over six years on the Australian Great Barrier Reef. State one...
- 21N.2.SL.TZ0.a.i: Identify the site with the highest incidence of diseased colonies.
- 21N.2.SL.TZ0.a.ii: Deduce whether there is a trend in the incidence of white syndrome over the north-south range of...
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21N.2.SL.TZ0.b.i:
Describe the evidence that is provided by the data in the table for the harmful effects of rising sea temperatures on corals.
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21N.2.SL.TZ0.b.ii:
The researchers concluded that there was a threshold coral cover percentage, below which infection rates tended to remain fairly low. Using the data in the table, identify this threshold level.
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21N.2.SL.TZ0.b.iii:
Suggest a reason for a larger percentage of corals being infected with white syndrome on reefs with a higher cover of corals.
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21N.2.SL.TZ0.c.i:
Compare and contrast the data for 1998–1999 and 2002–2003.
- 21N.2.SL.TZ0.c.ii: Suggest a reason for the correlation between coral cover and WSSTA in 1998–1999.
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21N.2.SL.TZ0.d:
Some scientists predict that, if humans continue to produce carbon dioxide at the current rate, the pH of the oceans will become more acidic. Suggest possible effects on the coral reefs.
- 21N.2.SL.TZ0.e: This study was carried out over six years on the Australian Great Barrier Reef. State one...
- 19M.2.HL.TZ2.3b: Suggest how climate change can influence the natural selection of organisms that live in the...
- 19M.2.HL.TZ2.b: Suggest how climate change can influence the natural selection of organisms that live in the...
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21M.1A.SL.TZ2.19:
Which gases have made the most significant contributions to global warming?
A. Water and carbon dioxide
B. Carbon dioxide and methane
C. Methane and nitrous oxide
D. Carbon dioxide and ozone
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21M.2.SL.TZ1.7c:
Discuss the relationship between atmospheric carbon dioxide concentration and global temperatures.
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21M.2.SL.TZ1.c:
Discuss the relationship between atmospheric carbon dioxide concentration and global temperatures.
- 22M.2.SL.TZ2.3b.ii: Explain the role of methane in climate change.
- 22M.2.SL.TZ2.b.ii: Explain the role of methane in climate change.
- 19N.1A.SL.TZ0.20: What material is formed when organic matter is not fully decomposed in acidic waterlogged...
- 20N.1A.SL.TZ0.19: The oceans absorb much of the carbon dioxide in the atmosphere. The combustion of fossil fuels...
- 22M.1A.SL.TZ1.16: What is a potential consequence of the rise in global temperatures? A. Increased exposure to UV...
- 21N.1A.SL.TZ0.19: How do greenhouse gases contribute to global warming? A. They destroy the ozone layer, allowing...
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21M.2.SL.TZ1.3a:
The map shows the widespread distribution of coral reef ecosystems (indicated by black dots) in the world’s oceans. Death of coral reefs is related to increasing atmospheric carbon dioxide concentrations.
[Source: National Oceanic and Atmospheric Administration, 2021. Where Reef Building Corals Found. [map online] Available at: https://oceanservice.noaa.gov/education/tutorial_corals/media/supp_coral05a.html [Accessed 20 May 2021].]
Explain how increased atmospheric carbon dioxide concentrations can lead to coral death.
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21M.2.SL.TZ1.a:
The map shows the widespread distribution of coral reef ecosystems (indicated by black dots) in the world’s oceans. Death of coral reefs is related to increasing atmospheric carbon dioxide concentrations.
[Source: National Oceanic and Atmospheric Administration, 2021. Where Reef Building Corals Found. [map online] Available at: https://oceanservice.noaa.gov/education/tutorial_corals/media/supp_coral05a.html [Accessed 20 May 2021].]
Explain how increased atmospheric carbon dioxide concentrations can lead to coral death.
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22N.2.SL.TZ0.3a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
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22N.2.SL.TZ0.3b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
- 22N.2.SL.TZ0.3c: State one other gas that contributes to global warming.
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22N.2.SL.TZ0.a:
It has been argued that variation in the global mean surface temperature has been caused by variation in energy from the Sun. Analyse whether evidence from the graphs supports this argument.
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22N.2.SL.TZ0.b:
Explain how increased levels of atmospheric carbon dioxide contribute to global warming.
- 22N.2.SL.TZ0.c: State one other gas that contributes to global warming.
- 22M.1A.SL.TZ2.15: The table shows features of greenhouse gases in the atmosphere. According to the data in the...
- 23M.2.SL.TZ1.1a: Compare and contrast the LAI data for the arctic and temperate zones.
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23M.2.SL.TZ1.1b:
Suggest reasons for the differences in LAI between the boreal and equatorial zones.
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23M.2.SL.TZ1.1c:
Analyse the data shown in the graph for evidence of a relationship between LAI and El Niño events.
- 23M.2.SL.TZ1.1d: The data in the graph show a long-term trend in global LAI.
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23M.2.SL.TZ1.1di:
State the trend.
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23M.2.SL.TZ1.1dii:
Global ecosystem modelling suggests that most of the change in LAI is due to increases in atmospheric carbon dioxide. Explain how rising atmospheric carbon dioxide (CO2) concentration could cause the observed change in LAI.
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23M.2.SL.TZ1.1e:
State the effect of elevated CO2 on net primary production in these young, developing forests.
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23M.2.SL.TZ1.1f:
Outline one benefit of conducting similar FACE experiments in multiple locations.
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23M.2.SL.TZ1.1g:
Evaluate the evidence from the bar chart that increases in carbon dioxide cause increases in carbon storage in young, developing forests.
- 23M.2.SL.TZ1.a: Compare and contrast the LAI data for the arctic and temperate zones.
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23M.2.SL.TZ1.b:
Suggest reasons for the differences in LAI between the boreal and equatorial zones.
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23M.2.SL.TZ1.c:
Analyse the data shown in the graph for evidence of a relationship between LAI and El Niño events.
- 23M.2.SL.TZ1.d: The data in the graph show a long-term trend in global LAI.
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23M.2.SL.TZ1.di:
State the trend.
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23M.2.SL.TZ1.dii:
Global ecosystem modelling suggests that most of the change in LAI is due to increases in atmospheric carbon dioxide. Explain how rising atmospheric carbon dioxide (CO2) concentration could cause the observed change in LAI.
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23M.2.SL.TZ1.i:
State the trend.
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23M.2.SL.TZ1.ii:
Global ecosystem modelling suggests that most of the change in LAI is due to increases in atmospheric carbon dioxide. Explain how rising atmospheric carbon dioxide (CO2) concentration could cause the observed change in LAI.
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23M.2.SL.TZ1.e:
State the effect of elevated CO2 on net primary production in these young, developing forests.
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23M.2.SL.TZ1.f:
Outline one benefit of conducting similar FACE experiments in multiple locations.
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23M.2.SL.TZ1.g:
Evaluate the evidence from the bar chart that increases in carbon dioxide cause increases in carbon storage in young, developing forests.
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23M.2.SL.TZ2.6c:
Describe how human activities have caused average surface air temperatures on Earth to increase.
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23M.2.SL.TZ2.c:
Describe how human activities have caused average surface air temperatures on Earth to increase.