MC test: Lewis acids & bases

Multiple choice test on 18.1 Lewis acids & bases

Use the following 'quiz' to test your knowledge and understanding of this sub-topic. You will need access to a periodic table (Section 6 of the IB data booklet).

If you get an answer wrong, read through the explanation carefully to learn from your mistakes.

Which are correct statements concerning the Brønsted-Lowry and Lewis theories of acids and bases?

I. Brønsted-Lowry theory is concerned with proton transfer and Lewis theory is concerned with electron pair transfer.

II. When 'curly arrows' are used in organic mechanisms it indicates a Lewis acid-base reaction.

III. All Lewis acids are also Brønsted-Lowry acids.

All Brønsted-Lowry acids are also Lewis acids since the transfer of a proton involves the movement of an electron pair. However, if a Lewis acid contains no protons then it cannot be a Brønsted-Lowry acid.

 

Which can act as a Lewis acid but not as a Bronsted-Lowry acid?

Zn2+ can attracts the electron pairs from ligands such as water to form complex ions e.g. [Zn(H2O)6]2+. Neither PF6 nor CH4 can accept a pair of electrons and NH4+ can also act as a Brønsted-Lowry acid.

 

Which reaction can be classified as an acid-base reaction only by using the Lewis theory.

The formation of sodium bromide from its elements is not an acid-base reaction. The other three are all Lewis acid-base reactions but the reactions of ammonia with water and hydrochloric acid are also Brønsted-Lowry acid-base reactions.

 

Which are correct statements about Lewis bases?

I. Lewis bases donate a pair of electrons.

II. All ligands can function as Lewis bases.

III. All nucleophiles can function as Lewis bases.

Ligands and nucleophiles both contain at least one non-bonding pair of electrons and function as Lewis bases by donating them when they react.

 

Which can act as a Lewis base?

Only a fluoride ion can donate a pair of electrons.

 

The mechanism for the electrophilic addition of hydrogen bromide to ethene is shown

Which row gives the correct description of how the reactants and intermediates are acting?

Rowethenehydrogen bromidecarbocation
intermediate
bromide ion
1Lewis baseLewis acidLewis baseLewis acid
2Lewis baseLewis acidLewis acidLewis base
3Lewis acidLewis baseLewis baseLewis acid
4Lewis acidLewis baseLewis acidLewis base

The π bond in ethene is donating a pair of electrons to the δ+ on the H atom of HBr and the bromide ion is donating a pair of electrons to the intermediate carbocation.

 

Aluminium chloride can act as a catalyst for the reaction between benzene and chlorine to form chlorobenzene.

Which best describes how chlorine is behaving in the first concerted step?

One of the chlorine atoms is accepting a pair of electrons from the delocalized benzene π electrons and at the same time the other chlorine atom is donating a pair of electrons to the aluminium chloride catalyst.

 

Which is not a Lewis acid-base reaction?

The chlorination of methane in ultraviolet light proceeds via a free radical mechanism where bonds are broken homolytically and does not involve the transfer of a pair of electrons.

 

Which are correct statements concerning the Lewis theory of acids and bases?

I. The conjugate base of a Brønsted-Lowry acid is a Lewis base.

II. A Lewis acid must contain an empty orbital capable of accepting a pair of electrons.

III. The bond formed between a Lewis acid and a Lewis base is a coordinate (dative) covalent bond.

Since all Brønsted-Lowry acids are also Lewis acids then all Brønsted-Lowry conjugate bases must be Lewis bases. A Lewis acid must have an empty orbital capable of accepting the pair of electrons donated by the Lewis base and as both electrons in the bond formed between a Lewis acid and Lewis base come from the base the bond formed will be a coordinate bond.

 

Which species cannot function as a Lewis acid?

Only I cannot function as a Lewis acid as it cannot accept a pair of electrons as it has a noble gas electron configuration. In fact it functions as a Lewis base in the reaction with iodine to form the triiodide ion, I3.

 

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